\(\frac{x}{125}\)=\(\frac{69}{115}\)
Tìm x là :.......
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Tìm x biết:x/125=69/115. Tìm x ?
x:125=\(\frac{69}{115}\)
x=\(\frac{69}{115}\times125\)
x=75
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x/125=69/115
X = 75
cho mik nhiều
Tim x, biet:
x/125 = 69/115
Ban nao nhanh tay minh se ket ban voi.
Cho\(\frac{x+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}\)và \(\frac{9-x}{7}+\frac{11-x}{9}=2\)Tìm x+y+z
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2.CMR C=\(220^{119^{69}}+119^{69^{220}}+69^{220^{119}}\)chia hết cho 102
Tìm x:
\(\frac{x+11}{115}+\frac{x+22}{104}=\frac{x+33}{93}+\frac{x+44}{82}\)
\(\frac{x+11}{115}+\frac{x+22}{104}=\frac{x+33}{93}+\frac{x+44}{82}\)
\(\Leftrightarrow\frac{1+\left(x+11\right)}{115}+\frac{1+\left(x+22\right)}{104}=\frac{1+\left(x+33\right)}{93}+\frac{1+\left(x+44\right)}{82}\)
\(\Leftrightarrow\frac{x+126}{115}+\frac{x+126}{104}=\frac{x+126}{93}+\frac{x+126}{82}\)
\(\Leftrightarrow\left(x+126\right).\left(\frac{1}{115}+\frac{1}{104}+\frac{1}{93}+\frac{1}{82}\right)=0\)
\(\Leftrightarrow x+126=6\Leftrightarrow x=-126\)vì\(\frac{1}{115}+\frac{1}{104}+\frac{1}{93}+\frac{1}{82}\ne0\)
vậy x=-126
Tìm x , biết :a) x+frac{7}{12}frac{17}{18}-frac{1}{9} b) frac{29}{30}-left(frac{13}{23}+xright)frac{7}{69}c) frac{-5}{6}.frac{125}{25} x frac{-7}{15}.frac{9}{14} (x thuộc Z)d) left(frac{-5}{3}^3right) x frac{-24}{35}.frac{-5}{6} ( x thuộc Z ) ththu
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Tìm x , biết :
a) \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
b) \(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
c) \(\frac{-5}{6}.\frac{125}{25}< x< \frac{-7}{15}.\frac{9}{14}\) (\(x\) thuộc Z)
d) \(\left(\frac{-5}{3}^3\right)< x< \frac{-24}{35}.\frac{-5}{6}\) ( \(x\) thuộc Z ) \(\)ththu
\(\frac{69}{91}=\frac{x-5}{133}\)tìm x
=> 133 x 69 = ( x - 5 ) x 91
=> 9177 = 91 x ( x - 5 )
=> x - 5 = 1311/13
=> x = 1376/13
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Tìm x biết :
\(\frac{x}{15}+\frac{x-19}{17}+\frac{x+69}{18}=0\)
<=> 17.6x+90(x-19)+17.5(x+69)=0
<=> 102x+90x-1710+85x+5865=0
<=> 277x=-4155 => x=-4155/277=-15
ĐS: x=-15
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Tìm x : \(\frac{x-39}{19}+\frac{x-49}{29}=\frac{x-59}{39}+\frac{x-69}{49}\)
Lí do = 0 nè:
\(\frac{x-39}{19}+\frac{x-49}{29}=\frac{x-5}{39}+\frac{x-69}{49}\)
=> \(\frac{x-39}{19}+\frac{x-49}{29}=0+\left(\frac{x-5}{39}+\frac{x-69}{49}\right)\)
=> \(\frac{x-39}{19}+\frac{x-49}{29}-\left(\frac{x-5}{39}+\frac{x-69}{49}\right)=0\)
=> \(\frac{x-39}{19}+\frac{x-49}{29}-\frac{x-5}{39}-\frac{x-69}{49}=0\)
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