B = (1+1/1.3)(1+1/2.4)(1+1/3.5)......(1+1/2014.2016)(1+ 1/2015.2017)
Nếu có thể thì các bạn giải ra giùm mik nha
Rút gọn biểu thức
\(B=\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right).....\left(1+\frac{1}{2014.2016}\right)\left(1+\frac{1}{2015.2017}\right)\)
Giúp mình với....
A= 1/2 ( 1 + 1.3) ( 1 + 1/2.4) ( 1 + 3.5 ) ...............( 1 + 1/ 2015.2017)
C=(1+1/1.3)(1+1/2.4)(1+1/3.5)......(1+1/2014.2016)
\(C=\left(1+\frac{1}{1.3}\right)\)\(.\left(1+\frac{1}{2.4}\right)\)\(.\left(1+\frac{1}{3.5}\right)\)\(.\left(1+\frac{1}{2014.2016}\right)\)
\(=\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}...\frac{2015^2}{2014.2016}\)
\(=\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}...\frac{2015.2015}{2014.2016}\)
\(=\frac{\left(2.3.4...2015\right).\left(2.3.4...2015\right)}{\left(1.2.3...2014\right).\left(3.4.5...2016\right)}\)
\(=\frac{2015.2}{2016}\)
\(=...\)(tự tinhs)
c= (1+1/1.3).(1+1/2.4).(1+1/3.5)*...*(1+1/2014.2016)
tính m=(1+1/1.3)+(1+1/2.4)+(1+3.5).....(1+1/2014.2016)
tính :(1+1/1.3).(1+1/2.4)+(1+1/3.5)+...+(1+1/2014.2016)
luu y : dau /la phan cach giua mau so va tu so
Tính C:
C = ( 1+1/1.3)(1+1/2.4)(1+1/3.5).....(1+1/2014.2016)
(Mình đang rất vội nên mong các bạn trả lời sớm. Cảm ơn nhiều!)
A=2016.(1+1/1.3).(1+1/2.4).(1+1/3.5)...(1+1/2014.2016)
\(\frac{\left(1.3+1\right)\left(2.4+1\right)\left(3.5+1\right).......\left(2014.2016+1\right)}{1.3.2.4.3.5...............2014.2016}\)