3+3+3+32+2+1+4+9+100=?
Chưng tỏ
a, S= 1/2^2+1/3^2+...+1/9^2
Chứng tỏ 2/5<S<8/9
b, 1/2-1/4+1/8-1/16+1/32-1/64<1/3
c, 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
tính nhanh
4/5-2/3/+1/5-1/3
2/5 x 7/4 - 2/5x3/7
13/4 x 2/3 x 4/13 x 3/12
75/100 + 18/21 + 19/32 +1/4 + 3/21 + 13/32
2/5 + 6/9+3/4+3/5+1/3+1/4
Bài giải
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
a , =(4/5+1/5)-(2/3+1/3)=1-1=0
b , =2/5 x (7/4-3/7) =2/5 x 37/28 =74/140=37/70
c, =13/4 x 2/3 x 13/4 x 2/3=26/12 x 26/12= 13/6 x 13/6 =13 x 13/6 x 6(gạch 13 trên tử thì tử còn 1 x 13,mẫu hết.) =1 x 13/1=13
d, =3/4+6/7+19/32 +1/4+1/7 +13/32=(3/4+1/4 )+(6/7+1/7)+(19/32+13/32)=1+1+1=3
e, =(2/5+3/5)+(2/3+1/3)+(3/4+1/4) [6/9 rút gọn thành 2/3] =1+1+1=3
Bài 1 : Tính các biểu thức :
a ) 1727 + [ 6993 : 111 +( 848 - 95 ) ] x 4 - 2
b ) 75/ 100 + 18/21 + 19/32 + 1/4 + 3/21 + 13/32
c ) 4 2/5 + 5 6/9 + 2 3/4 + 3/5 + 1/3 + 1/4
d ) 3/4 + 25/36 - ( 4/9 + 13/18 + 1/72 )
a, 1727 + [ 6993 : 111 + ( 848 - 95 ) ] x 4 - 2
= 1727 + [ 63 + 753 ] x 4 - 2
= 1727 + 816 x 4 - 2
= 1727 + 3264 - 2
= 4991 - 2
= 4989
b, 75/100 + 18/21 + 19/32 + 1/4 + 3/21 + 13/32
= 75/100 + 1/4 + ( 18/21 + 3/21 ) + ( 19/32 + 13/32 )
= 75/100 + 25/100 + 21/21 + 32/32
= 100/100 + 1 + 1
= 1 + 1 + 1 = 3
c, 4 2/5 + 5 6/9 + 2 3/4 + 3/5 + 1/3 + 1/4
= ( 4 2/5 + 3/5 ) + ( 2 3/4 + 1/4 ) + 5 6/9 + 1/3
= 5 + 3 + 5 6/9 + 3/9
= 5 + 3 + 6
= 8 + 6 = 14
d, 3/4 + 25/36 - ( 4/9 + 13/18 + 1/72 )
= 27/36 + 25/36 - ( 32/72 + 52/72 + 1/72 )
= 52/36 - ( 84/72 + 1/72 )
= 52/36 - 85/72
= 104/72 - 85/72
= 19/72
Tính nhanh
a 75/100 + 18/21 + 19/32 + 1/4 + 3/21 + 13/32
b 4 và 2/5 + 5 và 6/9 + 2 và 3/4 + 1/4 + 1/3 + 3/5
mik cần gấp các bn ơi
a )
75/100 + 18/21 + 19/32 + 1/4 + 3/21 + 13/32
= 3/4 + 18/21 + 19/321 + 1/4 + 3/21 + 13/32
= ( 3/4 + 1/4 ) + ( 18/21 + 3/21 ) + ( 19/32 + 13/32 )
= 1 + 1 + 1
= 3
b )
4 và 2/5 + 5 và 6/9 + 2 và 3/4 + 1/4 + 1/3 + 3/5
= 22/5 + 51/9 + 11/4 + 1/4 + 1/3 + 3/5
= ( 22/5 + 3/5 ) + ( 51/9 + 1/3 ) + ( 11/4 + 1/4 )
= 25/5 + 54/9 + 12/4
= 5 + 6 + 3
= 14
a)\(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}=\frac{3}{4}+\frac{18}{21}+\frac{1}{4}+\frac{19}{32}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1=3\)
Viết gọn các tích hoawch thương sau dưới dạng 1 lũy thừa
a) 4^4 . 2^3
b) 9^3 . 3 . 27^2
c) 100 . 10^4 . 100^3
d) 25^4 : 5^7
e) 49^8 : 7^16
f) 16^9 : 4^5
g) 8 . 4^2 . 32^3
h) 4 . 16^5 .4^2
i) 3^2 . 27 . 9^3
Viết gọn các tích hoawch thương sau dưới dạng 1 lũy thừa
a) 4^4 . 2^3
b) 9^3 . 3 . 27^2
c) 100 . 10^4 . 100^3
d) 25^4 : 5^7
e) 49^8 : 7^16
f) 16^9 : 4^5
g) 8 . 4^2 . 32^3
h) 4 . 16^5 .4^2
i) 3^2 . 27 . 9^3
Rút gọn
1) (0.9)^5/(0.3)^6
2)20^5*5^410/100^5
3)4^6*9^5+6^9*120/8^4*3^12-6^11
4)4^2*25^2+32*125/2^3*5^2
1, 3^4
2, 5^405
3, -20/3
4, 4
KHÔNG BÍT ĐÚNG HAY KO =>HIHIHIHI
bai 1: Thuc hien phep tinh
a) 75/100 + 18/21 + 19/32 + 1/4 + 3/21 + 13/32
b) 22/5 + 51/9 + 11/4 + 3/5 + 1/3 + 1/4
1a
75/100+18/21+19/32+1/4+3/21+13/32
= 3/4 +6/7+19/32+1/4+1/7+13/32
= (3/4+1/4)+(19/32+13/32)+(6/7+1/7)
= 1+1+1=3
1b
22/5+51/9+11/4+3/5+1/3+1/4
=22/5+17/3+11/4+3/5+1/3+1/4
=(22/5+3/5)+(17/3+1/3)+(11/4+1/4)
=25/5+18/3+12/4
=5+6+3
=14
tìm x biết
a] 3/2 * x + 1/4 * x - 1/2 * x = 10/9
b] 2/3 : x + 7/3 : x = 1/2
c] 7 * x + 8 * x + 9 * x + .... + 100 * x = 1025
d] 32 * [ x - 3 ] + 18 * x = 2
c] 7 * x + 8 * x + 9 * x + .... + 100 * x = 1025
(7+8+9+...+100)*x=1025
Coi A= 7+8+...+100
Số các số hạng của A là:
(100-7):1+1=94 (số)
=>A=(100+7)*94:2=5029
Ta lại có:
5029*x=1025
=>x=1025:5019=1025/5019
a, \(x.\left(\frac{3}{2}+\frac{1}{4}-\frac{1}{2}\right)=x.\left(\frac{6}{4}+\frac{1}{4}-\frac{2}{4}\right)=\frac{10}{9}\)
\(x.\frac{5}{4}=\frac{10}{9}\)
\(x=\frac{10}{9}:\frac{5}{4}=\frac{10}{9}.\frac{4}{5}=\frac{8}{9}\)
a, 1+2+3+4+5+6+7+8+9+...+100
b, 23+54+32+67+100x0
a, 1+2+3+4+5+6+7+8+9+...+100
Tổng dãy số trên là :
\(\frac{100.\left(100+1\right)}{2}=5050\)
b, 23+54+32+67+100x0
= 23 + 54 + 32 + 67
= ( 23 + 67 ) + ( 54 + 32 )
= 90 + 86
= 176
Study well
a, ko ghi đề
=(100+1)+(99+2)+...+(50+51) ( có 50 cặp )
=(101) x 50
=5050
b,ko ghi đề nốt
=(23+54+32+67)+0
=176
Nhớ k đúng mk nha ^^
a) 1 + 2 + 3 + 4 +...+ 100 có: ( 100 - 1 ) : 1 + 1 = 100 ( số hạng )
=> 1 + 2 + 3 + 4 +...+ 100 = ( 100 + 1 ) x 100 : 2 = 5050.
b) 23 + 54 + 32 + 67 + 100 x 0
= 23 + 54 + 32 + 67
= ( 23 + 67 ) + 54 + 32
= 90 + 54 + 32
= 144 + 32
= 176