Bài 3: 

a: =>x=13-24=-11

b: =>3x=12

hay x=4

c)\(\Leftrightarrow\)(x+1)+2 chia hết  x+1
\(\Rightarrow\)2 chia hết x+1
\(\Rightarrow\)x+1 ∈ {1,-1,2,-2}
\(\Rightarrow\)x ∈ {0,-2,1,-3}

c) \(x+3⋮x+1\)

\(\Rightarrow x+1+2⋮x+1\)

\(\Rightarrow2⋮x+1\) ( vì \(x+1⋮x+1\) )

\(\Rightarrow x+1\in\text{Ư}_{\left(2\right)}\)

\(\text{Ư}_{\left(2\right)}=\text{ }\left\{1;-1;2;-2\right\}\)

vậy................

a, Với x \(\varepsilon\)Z: 

(x-2)(x+3)= 15

<=> x²  + x - 6 = 15

<=> x² + x - 21 = 0

Ta có: a=1 , b=1 , c= -21

=> \(\Delta\)= 1² - 4.1.(-21) = 85 > 0

=> phương trình có hai nghiệm phân biệt:

x₁= \(\frac{-1+\sqrt{85}}{2}\)(không thỏa mãn điều kiện)

x₂= \(\frac{-1-\sqrt{85}}{2}\)(không thỏa mãn)

vậy phương trình không tồn tại nghiệm x thuộc Z

a. (x+1) + (x+3) + (x+5) + ......+(x+99)=0

    x.50+(1+3+5+.......+99)=0

     x.50 + 2500                =0

     x.50                           =0+2500

      x.50                           = 2500

      x                                 =2500:50

     x                                  =50

Bài làm :

\(a,\left[\left(250-25\right):15\right]:x=\left(450-60\right):130\)

\(\Rightarrow\left(225:15\right):x=390:130\)

\(\Rightarrow15:x=3\)

\(\Rightarrow x=15:3\)

\(\Rightarrow x=5\)

\(b,390-\left(x-7\right)=169:13\)

\(\Rightarrow390-\left(x-7\right)=13\)

\(\Rightarrow x-7=390-13\)

\(\Rightarrow x-7=377\)

\(\Rightarrow x=377+7\)

\(\Rightarrow x=384\)

\(c,x-6:2-\left(48-24\right):2:6-3=0\)

\(\Rightarrow x-6:2-24:2:6=3\)

\(\Rightarrow x-3-2=3\)

\(\Rightarrow x=3+2+3\)

\(\Rightarrow x=8\)

Học tốt nhé

a) ((250-25):15):x=(450-60):130

(225:15):x=390:130

15:x=3

x=15:3=5

b) 390-(x-7)=169:13

390-x+7=13

x+7=390-13=377

x=377-7=370

c)x-6:2-(48-24):2:6-3=0

x-3-24:2:6-3=0

x-3-2-3=0

x-8=0

x=8

tk cho mk :>>

\(\frac{x+22}{11}+\frac{x+23}{12}=\frac{x+24}{13}+\frac{x+25}{14}\)

\(\Leftrightarrow\left(\frac{x+22}{11}+1\right)+\left(\frac{x+23}{12}+1\right)=\left(\frac{x+24}{13}+1\right)+\left(\frac{x+25}{14}+1\right)\)

\(\Leftrightarrow\frac{x+33}{11}+\frac{x+35}{12}=\frac{x+37}{13}+\frac{x+39}{14}\)

\(\Leftrightarrow\frac{x+33}{11}+\frac{x+35}{12}-\frac{x+37}{13}-\frac{x+39}{14}=0\)

\(\Leftrightarrow\frac{2184\cdot\left(x+33\right)+2002\cdot\left(x+35\right)-1848\cdot\left(x+37\right)-1716\cdot\left(x+39\right)}{24024}=0\)

\(\Leftrightarrow2184x+72072+2002x+70070-1848x-68376-1716x-66924=0\)

\(\Leftrightarrow622x+6842=0\)

\(\Leftrightarrow x=-11\)

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