Tìm x biết (2015 - x) :29 + 32 = 100
tìm x biết : ( 2008 - x ) : 29 + 32 =100
\(\left(2008-x\right):29+32=100\)
\(\Leftrightarrow\left(2008-x\right):29=68\)
\(\Leftrightarrow2008-x=1972\)
\(\Leftrightarrow x=36\)
(Tíck cho mìk vs nhá!)
( 2008 - x ) : 29 + 32 = 100
( 2008 - x ) : 29 = 100 - 32
( 2008 - x ) : 29 = 68
2008 - x = 68 x 29
2008 - x = 1972
x = 2008 - 1972
x = 36
Vậy x = 36
\(\left(2008-x\right):29+32=100\)
\(\left(2008-x\right):29=100-32\)
\(\left(2008-x\right):29=68\)
\(2008-x=68\cdot29\)
\(2008-x=1976\)
\(x=2008-1976\)
\(x=32\)
Tìm x:
a) (2009 - x) : 29 + 32 = 100.
b) (x - 2) x 3 - 270 : 45 = 120.
\(\left(2009-x\right):29+32=100\\ =>\left(2009-x\right):29=100-32=68\\ =>2009-x=68.29=1972\\ =>x=2009-1972=37\)
-
\(\left(x-2\right).3-270:45=120\\ =>3\left(x-2\right)-6=120\\ =>3\left(x-2\right)=120+6=126\\ =>x-2=126:3=42\\ =>x=42+2=44\)
X-2018/29+x-2017/30+x-2016/31+x-2015/32=+4
Tìm x
a) ( x - 149 ) : 35 = 270
b) ( 2009 - x ) : 29 + 32 = 100
c) x + 472 = 918
#)Giải :
a)\(\left(x-149\right)\div35=270\)
\(\Leftrightarrow x-149=9450\)
\(\Leftrightarrow x=9599\)
\(a,(x-149):35=270\)
\(\Leftrightarrow x-149=9450\)
\(\Leftrightarrow x=9450+149=9599\)
Vậy x = 9599
\(b,(2009-x):29+32=100\)
\(\Leftrightarrow(2009-x):29=68\)
\(\Leftrightarrow2009-x=1972\)
\(\Leftrightarrow x=2009-1972=37\)
Vậy x = 37
\(c,x+472=918\)
\(\Leftrightarrow x=918-472=446\)
Vậy x = 446
a) (x - 149) : 35 = 270
x - 149 = 270 . 35
x - 149 = 9450
x = 9450 + 149
x = 9599
b) (2009 - x) : 29 + 32 = 100
(2009 - x) : 29 = 100 - 32
(2009 - x) : 29 = 68
2009 - x = 68 x 29
2009 - x = 1972
x = 2009 - 1972
x = 37
c) x + 172 = 918
x = 918 - 472
x = 446
Tìm x, biết :
3/2 + 5/4 + 9/8 + 17/16 + 33/32 - 6 + x-1/x+1 = 31/32 - 2/2015
3/2+5/4+9/8/+17/16+33/32-6+x-1/x+1=31/32-2/2015
=(1+1/2)+(1+1/4)+(1+1/8)+(1+1/16)+(1+1/32-6+x-1/x+1=31/32-2/2015
=(1/2+1/4+1/8+1/16+1/32)+(1+1+1+1+1)-6+x-1/x+1=31/32-2/2015
=31/32+5-6+x-1/x+1=31/32-2/2015
=5-6+x-1/x+1=31/32-2/2015-31/32
=-1+x-1/x+1=-2/2015
=x-1/x+1=-2/2015- -1
=x-1/x+1=2013/2015
=>x=2014
bài 1 tính
a, 24 x 66 - 24 + 36 x 24
b, 29 x 173 - 29 x 72 -29
c, 1+5+10+15+...+55+60
d, 1x2+2x3+3x4 +...+18x19+19x20
bài 2 tìm x
a,106- ( x+ 7) =9
b, 2 x ( x+ 4) + 5 =65
c, (16x x -32) x 45=0
d, x+4 x x = 100 : 5
bài 2 tìm x
a,106- ( x+ 7) =9
x+7 = 106 - 9
x+7 = 107
x= 107 - 7
x=100
b, 2 x ( x+ 4) + 5 =65
2 x (x+4) = 65 - 5
2 x (x+4) = 60
x+4 = 60:2
x+4= 30
x= 30 - 4
x=26
c, (16x x -32) x 45=0
16 x X - 32 = 0: 45
16 x X - 32 =0
16 x X = 0 + 32
16 x X = 32
X= 32:16
X=2
d, x+4 x x = 100 : 5
X + 4 x X = 20
(1+4) x X = 20
5 x X = 20
X= 20:5
X=4
Bài 1:
a, 24 x 66 - 24 + 36 x 24
= 24 x (66-1+36)
= 24 x 101
= 24 x 100 + 24
= 2400+24
=2424
b, 29 x 173 - 29 x 72 - 29
= 29 x (173 - 72 -1)
= 29 x 100
= 2900
c, 1+5+10+15+...+55+60
= (5+60) x 6 + 1 (có 6 cặp)
= 65 x 6 + 1
= 390 +1 =391
d, D= 1 x 2 + 2 x 3 + 3 x 4 +...+18 x 19 + 19 x 20
3D= 1 x 2 x 3+ 2 x 3 x (4-1) + 3 x 4 x (5-2) +...+ 18 x 19 x (20 - 17) + 19 x 20 x (21-18)
3D= 1 x 2 x 3 - 1 x 2 x 3 + 2 x 3 x 4 - 2 x 3 x 4 +.... + 19 x 20 x 21 - 18 x 19 x 20
3D= 19 x 20 x 21 =7980
=> D= 7980:3=2660
[2009-x]:29+32=100
( 2009 - x ) : 29 + 32 = 100
( 2009 - x ) : 29 = 100 - 32
( 2009 - x ) : 29 = 68
( 2009 - x ) = 68 . 29
2009 - x = 1972
x = 2009 - 1972
x = 37
[2009 - x] : 29 =100-32
[2009-x] : 29 =68
2009-x =68x29
2009-x=1972
x=2009-1972
x=37
(2009-x):29+32=100
=>(2009-x):29=100-32
=>(2009-x):29=68
=>2009-x=68x29
=>2009-x=1972
=>x=2009-1972
=>x=37
cho A = 1+3+ 32 +33+ ... + 32015
chứng tỏ 2A +1 là một lũy thừa của 3
b) tìm x biết : (x-32) 2015 = (x-32)2017
(2009 - x ) : 29 +32 = 100
(2009-x) : 29 + 32 = 100
(2009-x): 29 = 68
2009-x = 68 x 29
2009 - x = 2001
x= 2009 - 2001
x=8
( 2009 - x ) : 29 + 32 = 100
( 2009 - x ) : 29 = 100 - 32
( 2009 - x ) : 29 = 68
2009 - x = 68 x 29
2009 - x = 1972
x = 2009 - 1972
x = 37