giúp mình vs ạ

a) \(\left(2x-3\right)^2-\left(2x+5\right)^2=10\)

\(\Leftrightarrow4x^2-12x+9-4x^2-20x-25-10=0\)

\(\Leftrightarrow-32x-26=0\)

\(\Leftrightarrow-32x=26\)

\(\Rightarrow x=-\frac{13}{16}\)

b) \(4\left(x+1\right)^2+\left(2x-1\right)^2+8\left(x-1\right)\left(x+1\right)=11\)

\(\Leftrightarrow4x^2+8x+4+4x^2-4x+1+8x^2-8=0\)

\(\Leftrightarrow16x^2+4x-3=0\)

\(\Leftrightarrow4\left(4x^2+x+\frac{1}{16}\right)-\frac{13}{4}=0\)

\(\Leftrightarrow\left[2\left(2x+\frac{1}{4}\right)\right]^2-\left(\frac{\sqrt{13}}{2}\right)^2=0\)

\(\Leftrightarrow\left(4x+\frac{1}{2}-\frac{\sqrt{13}}{2}\right)\left(4x+\frac{1}{2}+\frac{\sqrt{13}}{2}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}4x+\frac{1-\sqrt{13}}{2}=0\\4x+\frac{1+\sqrt{13}}{2}=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{\sqrt{13}-1}{8}\\x=\frac{-1-\sqrt{13}}{8}\end{cases}}\)

c) \(\left(x+5\right)^2=45+x^2\)

\(\Leftrightarrow x^2+10x+25-x^2-45=0\)

\(\Leftrightarrow10x-20=0\)

\(\Leftrightarrow10x=20\)

\(\Rightarrow x=2\)

d) \(\left(2x-3\right)^2-\left(2x-1\right)^2=-3\)

\(\Leftrightarrow4x^2-12x+9-4x^2+4x-1+3=0\)

\(\Leftrightarrow-8x+11=0\)

\(\Leftrightarrow-8x=-11\)

\(\Rightarrow x=\frac{11}{8}\)

e) \(\left(x-1\right)^2-\left(5x-3\right)^2=0\)

\(\Leftrightarrow\left(x-1-5x+3\right)\left(x-1+5x-3\right)=0\)

\(\Leftrightarrow\left(-4x+2\right)\left(6x-4\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}-4x+2=0\\6x-4=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{2}{3}\end{cases}}\)

a) ( 2x - 3 )² - ( 2x + 5 )² = 10

<=> 4x² - 12x + 9 - ( 4x² + 20x + 25 ) = 10 

<=> 4x² - 12x + 9 - 4x² - 20x - 25 = 10

<=> -32x - 16 = 10

<=> -32x = 26

<=> x = -26/32 = -13/16

b) 4( x + 1 )² + ( 2x - 1 )² + 8( x + 1 )( x - 1 ) = 11

<=> 4( x² + 2x + 1 ) + ( 4x² - 4x + 1 ) + 8( x² - 1 ) = 11

<=> 4x² + 8x + 4 + 4x² - 4x + 1 + 8x² - 8 = 11

<=> 16x² + 4x - 14 = 0

<=> 2( 8x² + 2x - 7 ) = 0

<=> 8x² + 2x - 7 = 0

\(\Delta=b^2-4ac=2^2-4\cdot8\cdot\left(-7\right)=4+224=228\)( không muốn xài delta đâu nhưng bí quá ;-; )

\(\Delta>0\)nên phương trình đã cho có hai nghiệm phân biệt :

\(\hept{\begin{cases}x_1=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-2+\sqrt{228}}{2\cdot8}=\frac{-2+\sqrt{228}}{16}=\frac{-1+\sqrt{57}}{8}\\x_2=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-2-\sqrt{228}}{2\cdot8}=\frac{-2-\sqrt{228}}{18}=\frac{-1-\sqrt{57}}{8}\end{cases}}\)

( Mình nghĩ ý này bạn nên xem lại đề )

c) ( x + 5 )² = 45 + x²

<=> x² + 10x + 25 = 45 + x²

<=> x² + 10x - x² = 45 - 25

<=> 10x = 20

<=> x = 2 

d) ( 2x - 3 )² - ( 2x - 1 )² = -3

<=> 4x² - 12x + 9 - ( 4x² - 4x + 1 ) = -3

<=> 4x² - 12x + 9 - 4x² + 4x - 1 = -3

<=> -8x + 8 = -3

<=> -8x = -11

<=> x = 11/8

e) ( x - 1 )² - ( 5x - 3 )² = 0

<=> [ x - 1 - ( 5x - 3 ) ][ x - 1 + ( 5x - 3 ) ] = 0

<=> [ x - 1 - 5x + 3 ][ x - 1 + 5x - 3 ] = 0

<=> [ -4x + 2 ][ 6x - 4 ] = 0

<=> \(\orbr{\begin{cases}-4x+2=0\\6x-4=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{2}{3}\end{cases}}\)

280 - ( x - 140 ) : 35 = 270

<=>    ( x - 140 ) : 35 = 280 -270

<=>    ( x -140 ) : 35 = 10

<=>      x -140          = 10 . 35

<=>      x  -140         = 350

<=>      x                 = 350 + 140

<=>     x                  = 490 

1) 280 - ( x - 140 ) : 35 = 270

=> ( x - 140 ) : 35 = 280 - 270 = 10

     x - 140 = 350

=> x = 350 + 140

=> x = 390

2) ( 190 - 2x ) : 35 - 32 = 16

     190 - 2x = ( 16 + 32 ) . 35 = 1680

    x = ( 190 - 1680 ) : 2

   x = -745

3) 720 : { 41 - ( 2x - 5 )} -2.5

Sai đề.

4) ( x : 23 + 45 ) . 37 - 22 = 24 .105

    x : 23 + 45 = ( 24.105 + 22 ) : 37

    x : 23 = 2542/37 - 45 = 877/37

    x = 877/37.23 = 20171/37

5) ( 3x - 4 ) ( x - 1 ) = 0

=> 3x - 4 = 0 hoặc x - 1 = 0

3x - 4 = 0      hoặc x - 1 = 0

=> x = 4/3        => x = 1

Vậy x \(\in\) { 4/3;1 }

6) 2^2x : 4 = 8³

=> 2^2x = 8³ . 4 = 2048 = 2¹¹

=> 2x = 11

=> x = 11/2 

Nhiều như vậy sao trả lời hết được 

Xin lỗi nha

Tk cho mk 1 cái 

(x+3).(2x-18)=0

=>x+3=0 hoặc 2x-18 =0

+)x+3=0

x=-3

+)2x-18=0

2x =18

x =9

Vậy x \(\in\)\(_{\left\{-3;9\right\}}\)

2x+35=x-27

2x-x =-35-27

x = -62

\(a.2x+35=x-27\)

\(\Leftrightarrow2x-x=-27-35\)

\(\Rightarrow x=-62\). Vậy \(x=-62\)

\(b.2x-41=3x+\left(-23\right)\)

\(\Leftrightarrow2x-3x=-23+41\)

\(\Leftrightarrow-x=18\)

\(\Rightarrow x=-18\). Vậy \(x=-18\)

\(c.4\left(x-3\right)-3\left(x+5\right)=45.\left(-2\right)-34\)

\(\Leftrightarrow4x-12-3x-15=-124\)

\(\Leftrightarrow4x-3x=-124+12+15\)

\(\Rightarrow x=-97\). Vậy \(x=-97\)

\(d.\left(x+3\right)\left(2x-18\right)=0\)

\(\Leftrightarrow\hept{\begin{cases}x+3=0\\2x-18=0\end{cases}\Rightarrow\hept{\begin{cases}x=-3\\x=9\end{cases}}}\). Vậy \(x=-3;9\)

Đề bài mình viết thiếu là CM biểu thức sau không phụ thuộc vào x ( nghĩa là kết quả phải ra số tự nhiên không có x ) 

\(A=\left(2x+1\right)\left(x-1\right)-2x\left(x+2\right)-5\left(-x+3\right)+4\)

\(=2x^2-2x+x-1-2x^2-4x+5x-15+4\)

\(=-12\left(đpcm\right)\)

\(B=\left(4x+3\right)\left(2x-5\right)-\left(8x+1\right)\left(x+3\right)+13\left(3x+1\right)+2\)

\(=8x^2-20x+6x-15-\left(8x^2+24x+x+3\right)+39x+13+2\)

\(=-3\left(đpcm\right)\)

Bài 1:

a, 2x + 35 = x - 27

    2x - x = -27 - 35

    x = -62

 b, 2x - 41 = 3x + (-23)

     2x - 3x = -23 + 41

     -x = 18

     x = -18

c, 4 . (x - 3) - 3 . (x - 5) = 45 . (-2) - 34

   4x - 12 - 3x + 15 = -90 - 34

   4x - 3x = -90 - 34 + 12 - 15

   x = -127

Bài 2:

- ( -1234 + 345 - 29 ) - ( 1234 + 135 - 59 )

= 1234 - 345 + 29 - 1234 - 135 + 59

= (1234 - 1234) - (345 + 135) + (29 + 59)

= 0 - 480 + 88

= -392

a)2x+35=x-27

2x-x=-27-35

1x=-62

x=-62:1

X=-62

1, a, 2x + 35 = x - 27 

<=> 2x - x = -27 - 35 

,<=> x = -72 

Vậy x = -72

b, 2x - 41 = 3x + ( - 23 )

<=> 2x - 3x = 41 - 23

<=> -1x = 18

<=> x = -18 

Vậy x = -18 

c, tương tự dùng phân phối .

2, = 1234 - 345 + 29 - 1234 - 135 + 59 

= ( 1234 - 1234 ) + ( -345 - 135 ) + ( 29 + 59 )

= 0 - 480 + 88 = -480 + 88 = -392