\(x\times98+x:0,5=2017\)

\(x\times98+x\times2=2017\)

\(x\times\left(98+2\right)=2017\)

\(x\times100=2017\)

\(x=2017:100=20,17\)

Chúc bạn học tốt !!!

x=20,17

x*98+x/0,5=2017
x*98+x*2=2017
x*100=2017
x=20,17

\(x\times98+x:0,5=2017\)

\(x\times98+x\times2=2017\)

    \(x\times\left(98+2\right)=2017\)

               \(x\times100=2017\)

                             \(x=2017:100\)

                              \(x=20,17\)

Xx98=2017x0,5

X x 98= 1008,5

   x=1008,5:98

   x=10,29081633

\(x.98:0,5=2017\)

                \(x.98=2017.0,5\)

                \(x.98=1008,5\)

                \(x=1008,5:98\)

\(x=10,29\)

x*98:0.5=2017

x*98=2017*0.5

x*98=1008.5

x=1008.5:98=\(\frac{2017}{196}\)

k cho tròn 130 zới!!!

biết rồi thì hỏi làm gì

X : 0,5 = X : \(\frac{1}{2}\)= X x \(\frac{2}{1}\)= X x 2

X*98+X:0,5=2017

X*98+X:1/2=2017

X*98+X*2=2017

X*(98+2)=2017

X*100=2017

X       =2017:100

X       =20,17

X * 98 + X : 0,5 = 2017

X * 98 + X : 1/2 = 2017

X * 98 + X * 2 = 2017

X * ( 98 + 2 ) = 2017

X * 100 = 2017

         X = 2017 : 100

         X = 20,17

cảm ơn các bạn nha

\(x\times98+x:0,5=2017\)

\(x\times98+x\times2=2017\)

   \(x\times\left(98+2\right)=2017\)

             \(x\times100=2017\)

                          \(x=2017:100\)

                          \(x=20,17\)

\(x\times98+x\div0,5=2017\)

\(x\times98+x\times2=2017\)

\(x\times\left(98+2\right)=2017\)

\(x\times100=2017\)

\(x=2017\div100\)

\(x=20,17\)

x x 98 + x : 0,5 = 2017

x x 98 + x x 2 = 2017

x x ( 98 + 2 ) = 2017

x x 100 = 2017

x = 2017 : 100

x = 2017

X x 98 + X : 0,5 = X x 98 + X x 2 = X x 100 = 125 =>X = 1,25

Ta có:  \(\frac{x-18}{2018}=\frac{x-17}{2017}\)

\(\Rightarrow\left(x-18\right).2017=\left(x-17\right).2018\)( tính chất của 2 tỉ số bằng nhau )

\(2017x-2017.18=2018x-2018.17\)

\(2018.17-2017.18=2018x-2017x\)

\(\left(2017+1\right).17-2017.\left(17+1\right)=x\)

\(2017.17+17-2017.17-2017=x\)

\(x=-2000\)

Vậy \(x=-2000\)

\(\frac{x+1}{99}+\frac{x+2}{98}=\frac{x-1}{101}+\frac{x-2}{102}\)

\(\Rightarrow\left(\frac{x+1}{99}+1\right)+\left(\frac{x+2}{98}+1\right)=\left(\frac{x-1}{101}+1\right)+\left(\frac{x-2}{102}+1\right)\) ( cộng cả 2 vế thêm 2 )

\(\frac{x+100}{99}+\frac{x+100}{98}=\frac{x+100}{101}+\frac{x+100}{102}\)

\(\Rightarrow\frac{x+100}{99}+\frac{x+100}{98}-\frac{x+100}{101}-\frac{x+100}{102}=0\)

\(\left(x+100\right).\left(\frac{1}{99}+\frac{1}{98}-\frac{1}{101}-\frac{1}{100}\right)=0\)

Ta có: \(\frac{1}{99}+\frac{1}{98}-\frac{1}{101}-\frac{1}{100}\ne0\)

\(\Rightarrow x+100=0\)

​​​\(x=-100\)​

Vậy \(x=-100\)

a, \(\frac{x-18}{2018}=\frac{x-17}{2017}\)

=>\(\frac{x-18}{2018}+1=\frac{x-17}{2017}+1\)

=>\(\frac{x-18+2018}{2018}=\frac{x-17+2017}{2017}\)

=>\(\frac{x+2000}{2018}=\frac{x+2000}{2017}\)

=>\(\frac{x+2000}{2018}-\frac{x+2000}{2017}=0\)

=>\(\left(x+2000\right)\left(\frac{1}{2018}-\frac{1}{2017}\right)=0\)

Mà \(\frac{1}{2018}-\frac{1}{2017}\ne0\)

=>x+2000=0 => x=-2000

b, 

=>\(\frac{x+1}{99}+1+\frac{x+2}{98}+1=\frac{x-1}{101}+1+\frac{x-2}{102}+1\)

=>\(\frac{x+1+99}{99}+\frac{x+2+98}{98}=\frac{x-1+101}{101}+\frac{x-2+102}{102}\)

=>\(\frac{x+100}{99}+\frac{x+100}{98}=\frac{x+100}{101}+\frac{x+100}{102}\)

=>\(\frac{x+100}{99}+\frac{x+100}{98}-\frac{x+100}{101}-\frac{x+100}{102}=0\)

=>\(\left(x+100\right)\left(\frac{1}{99}+\frac{1}{98}-\frac{1}{101}-\frac{1}{102}\right)=0\)

Mà \(\frac{1}{99}+\frac{1}{98}-\frac{1}{101}-\frac{1}{102}\ne0\)

=>x+100=0 => x=-100

\(\frac{x-1}{2018}=\frac{x-17}{2017}\)

\(\Rightarrow\frac{x-18}{2018}=\frac{x-17}{2017}=\frac{\left(x-18\right)-\left(x-17\right)}{2018-2017}=-\frac{1}{1}=-1\)

\(\Rightarrow x-18=-2018\)

\(\Rightarrow x=-2000\)

Uyên ơi m đừng mất dậy đừng chửi con gái h đú vc