Tính nhanh
1988x1996+1997+1995/1997x1996-1995x1996
1998 x1996 +1997+1995 trên 1997x1996-1995x1996
\(\dfrac{1998.1996+1997+1995}{1997.1996-1995.1996}\)
\(=\dfrac{1998.1996}{1997.1996-1995.1996}+\dfrac{1997+1995}{1997.1996-1995.1996}\)
\(=\dfrac{1998.1996}{1996\left(1997-1995\right)}-\dfrac{1997-1995}{1996\left(1997-1995\right)}\)
\(=\dfrac{1998}{1997-1995}-\dfrac{1}{1996}\)
\(=\dfrac{1998}{2}-\dfrac{1}{1996}\)
\(=999-\dfrac{1}{1996}\)
\(\approx998,99\)
\(\frac{1988x1996+1997+1995}{1997x1996-1995x1996}\)
nêu cách giải nha
Tính nhanh:
\(\frac{1988x1996+1997+1995}{1997x1996-1995x1996}\)
Ai làm nhanh và đúng mình tick cho!:)
=\(\frac{1988x1996+1996+1996}{1996x\left(1997-1995\right)}\)=\(\frac{1996x\left(1988+2\right)}{1996x2}\)
=\(\frac{1996x1990}{1996x2}\)=\(\frac{1990}{2}\)=\(995\)
Hello!!!
1997x1996-1/1995*1997+1996
1988x1996 + 1997+ 1995/ 1997x 1996- 1995x1996
= (1988 x 1996 + 1997 x 11 + 1985) : (1997 x 1996 - 1995 x 1996)
= (1988 x 1996 + (1996 + 1) x 11 + 1985) : (1996 x (1997 - 1995))
= (1988 x 1996 + 1996 x 11 + (11 + 1985)) : (1996 x 2)
= (1996 x (1988 + 11) + 1996 : (1996 x 2)
= (1996 x 1999 + 1996) : (1996 x 2)
= (1996 x 1999 + 1996 x 1) : (1996 x 2)
= (1996 x (1999 + 1)) : (1996 x 2)
= 1996 x 2000 : 1996 x 2
= 2000 : 2
= 1000.
Rút gọn phân số :
-1997x1996+1 / (-1995)x(-1997) + 1996
-1997*1996+1/-1995*(-1997)+1996
=-1997*(1995+1)+1/-1*1995*(-1)*1997+1996
=-1997*1995+(-1997)+1/1995*1997+1996
=-1*1997*1995+(-1996)/1995*1997+1996
=-1
Tính nhanh
1998x1996+1997x11+1985/1997x1996-1995x1996
1998x1996+1997x11+1985/1997x1996-1995x1996 = 2939,00600901352028042063094642 (sử dụng máy tính là nhanh nhất)
1998x1996+1997x11+1985/1997x1996-1995x1996
\(\dfrac{1998\times1996+1997\times11+1985}{1997\times1996-1995\times1996}\\ =\dfrac{1998\times1996+\left(1996+1\right)\times11+1985}{\left(1997-1995\right)\times1996}\\ =\dfrac{1998\times1996+1996\times11+11+1985}{2\times1996}\\ =\dfrac{1996\times1998+1996\times11+1996}{2\times1996}\\ =\dfrac{1996\times\left(1998+11+1\right)}{2\times1996}\\ =\dfrac{1996\times2010}{2\times1996}\\ =\dfrac{2010}{2}\\ =1005\)
tính biểu thức sau một cách hợp lý:
1998x1996+1997x11+1985/1997x1996-1995x1996
Tính \(\frac{1998x1996+1997x11+1985}{1997x1996-1995x1996}\)
ta có :
\(\frac{1998x1996+1997x11+1985}{1997x1996-1995x1996}\)= \(\frac{1998x1996+1996x11+11+1985}{1996x\left(1997-1995\right)}\)= \(\frac{1996x\left(1998+11+1\right)}{1996x2}\)=\(\frac{2010}{2}=1005\)
vậy giá trị cần tìm là 1005
1998x1996+1997x11+1985/1997x1996-1995x1996
=1998x1996+(1996+1)x11+1985/1996x(1997-1995)
=1998x1996+1996x11+11+1985/1996x2
=1998x1996+1996x11+1996/1996x2
=1996x(1998+11+1)/1996x2
=2010/2
=1005