(1.25-4/5x)^3=-125
a,2^12.3^54^6.81/(2^2.3)^6+8^4.3^5
b, 4.(-1/2)^3-2.(-1/2)^2+3.(-1/2)+1
c, 5x-7=3x+9
d, 5x-|9-7x|=3
e, -5+|3x-1|+6=|-4|
g, (x-1)^2=(x-1)^4
h, 5^-1.25=125
i, |x+1|+|x+2|+|x+3|=4x
c) \(5x-7=3x+9\)
d) \(5x-\left|9-7x\right|=3\)
e) \(-5+\left|3x-1\right|+6=\left|-4\right|\)
h) \(5^{-1}.25^x=125\)
\(\Rightarrow\frac{1}{5}.25^x=125\)
\(\Rightarrow25^x=125:\frac{1}{5}\)
\(\Rightarrow25^x=625\)
\(\Rightarrow25^x=25^2\)
\(\Rightarrow x=2\)
Vậy \(x=2.\)
Chúc bạn học tốt!
g) \(\left(x-1\right)^2=\left(x-1\right)^4\)
\(\Rightarrow\left(x-1\right)^2-\left(x-1\right)^4=0\)
\(\Rightarrow\left(x-1\right)^2.\left[1-\left(x-1\right)^2\right]=0\)
\(\Rightarrow\left[{}\begin{matrix}\left(x-1\right)^2=0\\1-\left(x-1\right)^2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x-1=0\\\left(x-1\right)^2=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0+1\\x-1=1\\x-1=-1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=1\\x=1+1\\x=\left(-1\right)+1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=2\\x=0\end{matrix}\right.\)
Vậy \(x\in\left\{1;2;0\right\}.\)
i) \(\left|x+1\right|+\left|x+2\right|+\left|x+3\right|=4x\)
Ta có:
\(\left\{{}\begin{matrix}\left|x+1\right|\ge0\\\left|x+2\right|\ge0\\\left|x+3\right|\ge0\end{matrix}\right.\forall x.\)
\(\Rightarrow\left|x+1\right|+\left|x+2\right|+\left|x+3\right|\ge0\) \(\forall x.\)
\(\Rightarrow4x\ge0\)
\(\Rightarrow x\ge0.\)
Lúc này ta có: \(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)=4x\)
\(\Rightarrow x+1+x+2+x+3=4x\)
\(\Rightarrow\left(x+x+x\right)+\left(1+2+3\right)=4x\)
\(\Rightarrow3x+6=4x\)
\(\Rightarrow6=4x-3x\)
\(\Rightarrow6=1x\)
\(\Rightarrow x=6\left(TM\right).\)
Vậy \(x=6.\)
Chúc bạn học tốt!
0.8*0.04*1.25*25*0.6524*0.3476/10*125*4*25*8
không giúp bạn ấy thì thôi đừng chửi người ta thế chứ
A=1+1/4+3*1.25+3:1.25+2*1.2
mik cần gấp
5x - 2.(x-1) = 4 . 3 . 125.(-25).8
\(5x-2.\left(x-1\right)=4.3.125.\left(-25\right).8\)
\(5x-2x+2=-300000\)
\(3x+2=-300000\)
\(3x=-300000-2\)
\(3x=-300002\)
\(x=-\frac{300002}{3}\)
Tính nhanh:
0.8 x 0.04 x 1.25 x 25 x 0.6524 x 0.3476
Phần
10 x 125 x 4x 25 x8
0,8 x 0,04 x 1,25 x 25 x 0,6524 x 0,3476
= ( 0,8 x 1,25 ) x ( 0,04 x 25 ) x ( 0,3476 + 0,5624 )
= 1 x 1 x 0,9
= 1 x 0,9
= 0,9
10 x 125 x 4 x 25 x 8
= 10 x ( 125 x 8 ) x ( 4 x 25 )
= 10 x 1 000 x 100
= 1 000 000
0,8.0,04.1,25.25.0,6524.0,3476
=(0,8.1,25).(0,04.25).(0,3476+0,5624)
=1.1.0,9
=0,9
10.125.4.25.8
=10.(125.8).(4.25)
=10.1 000.100
=1000000
#HỌC TỐT#
( y - 1.25 *4 : ( y - 1.25 * 4 ) = 1
tìm nghiệm của các đa thức sau:
a)2x - 5
b)x^3 -x^5
c)-7x + 3
d)x^3 + 5x
e)x^2 - 5x
f)(3x - 2).(5x^2 + 125)
g)-x +3/4
a) 2x - 5 = 0
2x = 0 + 5
2x = 5
x = 5:2
x = 5/2
b) x^3 - x^5 = 0
c) -7x + 3 = 0
-7x = 0 - 3
-7x = -3
x = -3 : - 7
x = 3/7
e) x^2 - 5x = 0
f ( 3x - 2 ) . ( 5 x^2 + 125 )=0
g) -x + 3/4 = 0
-x = 0 - 3/4
-x = -3/4
x = 3/4
Có mấy câu k bk giải
(4-5x)^3 = -1/125. ^3 day la ko hieu cua mu 3. Gi up Minh voi. De bai la Tim x
(4-5x)^3=-1/125
<=> 4-5x = -1/5
<=> -5x = -1/5 -4
<=> -5x = -21/5
<=> x = 21/25
tìm x :
5x + x = 39 - 311:39
thực hiện phép tính
225 : 32 +43 .125 -125 : 52
giúp mình với
Tìm x :
\(5x+x=39-3^{11}:3^9\)
\(6x=39-3^2\)
\(6x=39-9\)
\(6x=30\)
\(x=30:6\)
\(x=5\)
Thực hiện phép tính :
\(225:3^2+4^3.125-125:5^2\)
\(=225:9+64.125-125:25\)
\(=25+8000-5\)
\(=8020\)
a, 6x=39-3^2 b,225:9+64.125-125:25
6x=39-9 =25+64.125-125:25
6x=30 =25+8000-125:25
x=30:6 =25+8000-5
x=5 =8020