\(\frac{4}{5}\cdot\frac{3}{x}\cdot\frac{2}{11}=\frac{24}{165}\)

        \(\frac{3}{x}\)     \(=\frac{24}{165}:\frac{2}{11}:\frac{4}{5}\)

        \(\frac{3}{x}\)     \(=1\)

         \(x\)     \(=3\)

\(\frac{4}{3}:\frac{x}{5}=\frac{5}{13}\cdot\frac{4}{9}\)

\(\frac{4}{3}:\frac{x}{5}=\frac{20}{117}\)

      \(\frac{x}{5}=\frac{4}{3}:\frac{20}{117}\)

     \(\frac{x}{5}=\frac{39}{5}\)

     \(x=39\)

tớ không biết

 a } 4 / 5 x 3 /y x 2 / 11 = 24 / 165

= 4/5 x 2/11 x 3/y =24/125

=8/55           x 3/y=24/125

= 24/125:8/55

=33/25

4/5 x 3/y x 2/11 = 24/165

3/y x 2/11 = 24/165 : 4/5

3/y x 2/11 = 2/11

3/y = 2/11 : 2/11

3/y = 1 

b. 4/3 : y/5 = 5/13 x 4/9

4/3 : y/5    = 20/117

        y/5    = 4/3 : 20/117

        y/5    = 39/5

=> y = 39

phần a chắc sai nhưng phần b mih chắc chắn

nhớ k mih 3 lần nhé

a) ( x - 4 ) . ( x - 3 ) = 0

Thỏa mãn điều kiện x - 4 hoặc x - 3 bằng 0 .

\(\Rightarrow\hept{\begin{cases}x=4\\x=3\end{cases}}\)

b) ( x - 4 ) . ( y - 3 ) = 0

Thỏa mãn điều kiện x - 4 hoặc y - 3 bằng 0 .

\(\Rightarrow\hept{\begin{cases}x=4,x=3\\y=4,y=3\end{cases}}\)

c) x - 24 : 12 = 15

x - 2 = 15

x = 13

d) ( x - 12 ) : 13 = 5

x - 12 = 65

x = 77

e) 1 + 3 + 5 + ..... + x = 36

..... + x = 27

..... + x = 20

x = 11

f) 2 + 4 + .... + 2x = 110

2 + 4 + ....x = 55

Thỏa mãn điều kiện \(x\in N\left|2x+0\right|x⋮2\)

\(x\in\varnothing\)

\(a.\frac{4}{5}\times\frac{3}{x}\times\frac{2}{11}=\frac{24}{165}\)

\(\frac{3}{x}=\frac{24}{165}:\frac{4}{5}:\frac{2}{11}\)

\(\frac{3}{x}=1\)

\(\Rightarrow x=3\)

\(b.\frac{4}{3}:\frac{x}{5}=\frac{5}{13}\times\frac{4}{9}\)

\(\frac{4}{3}\times\frac{5}{x}=\frac{20}{117}\)

\(\frac{5}{x}=\frac{20}{117}:\frac{4}{3}\)

\(\frac{5}{x}=\frac{5}{39}\)

\(\Rightarrow x=39\)

Đúng nha

a: \(x+6\dfrac{1}{8}=8\)

=>\(x+\dfrac{49}{8}=\dfrac{64}{8}\)

=>\(x=\dfrac{64}{8}-\dfrac{49}{8}=\dfrac{15}{8}\)

b: \(\dfrac{11}{2}\cdot x=\dfrac{1}{5}:\dfrac{1}{3}\)

=>\(x\cdot\dfrac{11}{2}=\dfrac{1}{5}\cdot3=\dfrac{3}{5}\)

=>\(x=\dfrac{3}{5}:\dfrac{11}{2}=\dfrac{3}{5}\cdot\dfrac{2}{11}=\dfrac{6}{55}\)

c: \(x\cdot\dfrac{3}{5}+\dfrac{2}{5}\cdot x=\dfrac{4}{9}+\dfrac{1}{3}\)

=>\(x\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{4}{9}+\dfrac{3}{9}\)

=>\(x\cdot1=\dfrac{7}{9}\)

=>\(x=\dfrac{7}{9}\)

a) ( 1/2-1/3-1/6).(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10

0.(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10

0+3/4.x = 9/10

3/4.x = 9/10

x = 9/10: 3/4

x = 6/5

b) x + ( 3/1.3+3/3.5+...+3/13.15) = 11/5

x + 3/2. ( 1-1/3 + 1/3 - 1/5 + ...+ 1/13 - 1/15) = 11/5

x + 3/2. ( 1-1/15) = 11/5

x + 3/2.14/15 = 11/5

x + 7/5 = 11/5

x = 11/5 - 7/5

x = 4/5

..... là gì?

a) ( 1/2-1/3-1/6).(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10

0.(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10

0+3/4.x = 9/10

3/4.x = 9/10

x = 9/10: 3/4

x = 6/5

b) x + ( 3/1.3+3/3.5+...+3/13.15) = 11/5

x + 3/2. ( 1-1/3 + 1/3 - 1/5 + ...+ 1/13 - 1/15) = 11/5

x + 3/2. ( 1-1/15) = 11/5

x + 3/2.14/15 = 11/5

x + 7/5 = 11/5

x = 11/5 - 7/5

x = 4/5

a) 12 : x + 5 = 33 

     12 : x       = 33 - 5

     12 : x        = 28

             x       = 12 : 28

             x        = 1/4

Vậy x = 1/4

b) 5*(x + 19) = 170 - 50

5*(x+19) = 120

 x + 19 = 120 : 5

x + 19 = 24 

 x = 24 - 19

x = 5

Vậy x = 5

c) 11*(x - 6) - 11 = 4*x

11*(x-7) = 4x

11x - 77 = 4x

11x - 4x = 77

7x = 77

x = 11

Vậy x = 11