3S=1.2.3+2.3.3+3.4.3+...+49.50.3

=1.2.3+2.3.(4-1)+3.4.(5-2)+...+48.49.(50-47)+49.50.(51-48)

=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+48.49.50-47.48.49+49.50.51-48.49.50

=(1.2.3-1.2.3)+(2.3.4-2.3.4)+...(47.48.49-47.48.49)-(48.49.50-48.49.50)+49.50.51

=0+0+...+0+0+49.50.51

=49.50.51

\(S=\frac{\left(49.50.51\right)}{3}\)

=41650

Đáp số:41650

3A=1.2.3+2.3.3+..............+150.151.3

=1.2.3+2.3.(4-1)................+150.151.(152-149)

=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+....................+150.151.152-149.150.151

=150.151.152

=>A=\(\frac{150.151.152}{3}\)

A=1147600

thấy ổn thì t nhé

 A = 1.2 + 2.3 + 3.4 + ... + 2013.2014 
3A = 1.2.3 + 2.3.3 + 3.4.3 + ... + 2013.2014.3 
Mà : 
1.2.3 = 1.2.3 
2.3.3 = 2.3.4 - 2.3.1 
3.4.3 = 3.4.5 - 3.4.2 

2012.2013.3 = 2012.2013.2014 - 2012.2013.2011 
2013.2014.3 = 2013.2014.2015 - 2013.2014.2012 
Cộng tất cả, vế theo vế ---> 3S = 2013.2014.2015 
---> A = 2013.2014.2015 / 3 = 2723058910.

của bạn đây

 Tính tổng : A=1.2+2.3+3.4+..+19.20 

               3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 19.20.21

               3A = 19.20.21

                A = \(\frac{19.20.21}{3}=3990\)

Tính tổng : A=1.2+2.3+3.4+..+19.20

3a=1.2.3-1.2.3.+2.3.4-2.3.4+......+19.20.21

3a=19.20.21

a=19.20.21:3=3990

Lời giải:

$3A=1.2.3+2.3(4-1)+3.4(5-2)+...+2013.2014(2015-2012)$

$=(1.2.3+2.3.4+3.4.5+...+2013.2014.2015)-(1.2.3+2.3.4+...+2012.2013.2014)$

$=2013.2014.2015$

$\Rightarrow A=\frac{2013.2014.2015}{3}$

 A = 1.2 + 2.3 + 3.4 + ... + 2013.2014 
3A = 1.2.3 + 2.3.3 + 3.4.3 + ... + 2013.2014.3 
Mà : 
1.2.3 = 1.2.3 
2.3.3 = 2.3.4 - 2.3.1 
3.4.3 = 3.4.5 - 3.4.2 

2012.2013.3 = 2012.2013.2014 - 2012.2013.2011 
2013.2014.3 = 2013.2014.2015 - 2013.2014.2012 
Cộng tất cả, vế theo vế ---> 3S = 2013.2014.2015 
---> A = 2013.2014.2015 / 3 = 2723058910

4A= 4.( 1.2.3+2.3.4+4.5.6+5.6.7+...+2014.2015.2016

4A= 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + .4.5.6.4 + ....+ 2014.2015.2016.4

4A= 1.2.3.4 + 2.3.4.(5 - 1)+ 3.4.5.( 6-2)+.....+ 2014.2015.2016.(2017-2013)

4A= 1.2.3.4+  2.3.4.5-1.2.3.4.+  3.4.5.6-2.3.4.5+ .....+ 2014.2015.2016.2017-2013.2014.2015.2016

4A = 2013.2014.2015.2016

A = 4117265071920

=> 3A = 1.2.3 + 2.3.3 + 3.4.3 + .... + 2013.2014.3

=> 3A = 1.2.( 3 - 0 ) + 2.3.( 4 - 1 ) + 3.4.( 5 - 2 ) + ... + 2013.2014.( 2015 - 2012 )

=> 3A = 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + .... + 2013.2014.2015 - 2012.2013.2014

=> 3A = ( 1.2.3 - 1.2.3 ) + ( 2.3.4 - 2.3.4 ) + .... + ( 2012.2013.2014 - 2012.2013.2014 ) + 2013.2014.2015

=> 3A = 2013.2014.2015

=> A = ( 2013.2014.2015 ) : 3

A= 1.2+2.3+3.4+...+2015.2016

3A=1.2.3+2.3.3+3.4.3+...+2015.2016.3

3A=1.2.3+2.3.(4-1)+3.4.(5-2)+...+2015.2016.(2017-2014)

3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+2015.2016.2017-2014.2015.2016

3A=2015.2016.2017

3A=8193538080

A=8193538080:3

A=2731179360

3A = 1.2.3 + 2.3.3 + 3.4.3 + ..... + 2015.2016.3

=> 3A = 1.2.3 + 2.3.( 4 -1 ) + 3.4.( 5 - 2 ) + .... + 2015.2016.( 2017 - 2014 )

=> 3A = 1.2.3 + 2.3.4 - 1.2.3 + .... + 2015.2016.2017 - 2014.2015.2016

=> 3A = 2015.2016.2017

=> A = \(\frac{2015.2016.2017}{3}\)

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