Tìm \(x\in Z\) biết \(\left(x^3+5\right)\times\left(x^3+10\right)\times\left(x^3+15\right)\times\left(x^3+30\right)
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Tìm xin Z:a. 2timesleft(x-5right)-3timesleft(x-4right)left(-6right)+15timesleft(-3right)b.left(2x-5right)-722c.left(2timesleft|xright|-6right)times1144d.left|x+3right|+left|x+5right|+left|x+9right|4xe.left|x-1right|+left|x-5right|4g.x+left(x+1right)+left(x+2right)+.......+1000
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Tìm \(x\in Z\):
a. \(2\times\left(x-5\right)-3\times\left(x-4\right)=\left(-6\right)+15\times\left(-3\right)\)
b.\(\left(2x-5\right)-7=22\)
c.\(\left(2\times\left|x\right|-6\right)\times11=44\)
d.\(\left|x+3\right|+\left|x+5\right|+\left|x+9\right|=4x\)
e.\(\left|x-1\right|+\left|x-5\right|=4\)
g.\(x+\left(x+1\right)+\left(x+2\right)+.......+100=0\)
a) x=53
b) x=17
c) x=5;x=-5
d) x=17
e) x=5
g) ???
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Tìm x \(\frac{2}{\left(x-1\right)\times\left(x-3\right)}+\frac{5}{\left(x-3\right)\times\left(x-8\right)}+\frac{12}{\left(x-8\right)\times\left(x-20\right)}-\frac{1}{x-20}=-\frac{3}{4}\)-3/4
Tim \(x\in Z\)biet :
a; \(-12\times\left(x-5\right)+7\times\left(3-x\right)=20\)
b; 30\(30\times\left(x+1\right)-3\times\left(x-5\right)-15x=25\)
c; \(|5x-2|\le13\)
mn la on gip mik nha mik dang can gap
a,-12(x-5)+7(3-x)=20
-12x+60+21-7x=20
-19x=-61
x=\(\frac{61}{19}\)
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b,30(x+1)-3(x-5)-15x=25
30x+30+15-3x-15x=25
12x=-20
x=\(-\frac{20}{12}\)
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Xem thêm câu trả lời
Tìm x biết left|2x-4right|+left|3y+12right|+left(2z-10right)^{10}le0left|x-3right|+left|2y-6right|+left(4x-3yright)^2le0left(x-7right)timesleft(x+3right)0left(x-7right)timesleft(x+3right)timesleft(x-5right)0
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Tìm x biết
\(\left|2x-4\right|+\left|3y+12\right|+\left(2z-10\right)^{10}\le0\)
\(\left|x-3\right|+\left|2y-6\right|+\left(4x-3y\right)^2\le0\)
\(\left(x-7\right)\times\left(x+3\right)>0\)
\(\left(x-7\right)\times\left(x+3\right)\times\left(x-5\right)<0\)
cho: \(f\left(x\right)=a\times x^3+4\times x\times\left(x^2-1\right)+8\)
\(g\left(x\right)=x^3-4\times x\times\left(b\times x+1\right)+c-3\)
tìm a, b, c để \(f\left(x\right)=g\left(x\right)\)
1. Tìm x biết:
\(\left(3\times x-15\right)^7=0\)
\(10-\left\{\left[\left(x:3+17\right):10+3\times2^4\right]:10\right\}=5\)
Giúp mik với mọi người ơi !!!!
a ) \(\left(3\times x-15\right)^7=0.\)
\(3\times x-15=0\)
\(3\times x=15\)
\(x=5\)
b ) \(10-\left\{\left[\left(x\div3+17\right)\div10+3\times2^4\right]\div10\right\}=5\)
\(10-\left\{\left[\left(x\div3+17\right)\div10+3\times16\right]\div10\right\}=5\)
\(10-\left\{\left[\left(x\div3+17\right)\div10+48\right]\div10\right\}=5\)
\(\left[\left(x\div3+17\right)\div10+48\right]\div10=10-5\)
\(\left[\left(x\div3+17\right)\div10+48\right]\div10=5\)
\(\left(x\div3+17\right)\div10+48=50\)
\(\left(x\div3+17\right)\div10=2\)
\(x\div3+17=20\)
\(x\div3=3\)
\(x=9\)
Tìm x biết:
\(\frac{-1}{2}\times\left(3x-1\right)+\frac{3}{4}\left(3-2x\right)=-3\times\left(\frac{x}{2}-1\right)-\left(\frac{4}{5}\right)^{-1}\)
tìm x biết
\(x\times\left(4.6+\frac{3}{5}\right)+7.2-8.15\)\(42+\frac{3}{7}\times\left[3\times-1\right]=12\) \(\left[2\times x-1\right]=\left[x+2\right]\) \(\frac{x+2}{5}=\frac{2-3\times x}{3}\)
a) Thiếu đề (hoặc sai)
b) x đâu?
c)\(3x-1=x+2\)
\(\Rightarrow3x-x=2+1\)
\(\Rightarrow2x=3\)
\(\Rightarrow x=\frac{3}{2}\)
c) \(\frac{x+2}{5}=\frac{2-3x}{3}\)
\(\Rightarrow3.\left(x+2\right)=5.\left(2-3x\right)\)
\(\Rightarrow3x+6=10-15x\)
\(\Rightarrow3x+15x=10-6\)
\(\Rightarrow18x=4\)
\(\Rightarrow x=\frac{4}{18}=\frac{2}{9}\)
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câu 1 là \(x\times\left(4.6+\frac{3}{5}\right)=7.2-8.15\)
câu 2 là \(42+\frac{3}{7}.\left[3\times x-1=12\right]\)
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a)\(x.\left(4,6+\frac{3}{5}\right)=7,2-8,15\)
\(\Rightarrow\left(\frac{23}{5}+\frac{3}{5}\right).x=-0,95\)
\(\Rightarrow\frac{26}{5}.x=\frac{-19}{20}\)
\(\Rightarrow x=\frac{-19}{20}:\frac{26}{5}\)
\(\Rightarrow x=\frac{-19}{104}\)
Mà \(4.6\)là\(4,6\)hay \(4\times6?\)nếu sai tớ làm lại
b) Ngoặc sai rồi
\(42+\frac{3}{7}.\left(3x-1\right)=12\)
\(\Rightarrow\frac{3}{7}.\left(3x-1\right)=12-42\)
\(\Rightarrow\frac{3}{7}.\left(3x-1\right)=-30\)
\(\Rightarrow3x-1=-30:\frac{3}{7}\)
\(\Rightarrow3x-1=\frac{-10}{7}\)
\(\Rightarrow3x=\frac{-10}{7}+1\)
\(\Rightarrow3x=\frac{-10+7}{7}=\frac{-3}{7}\)
\(\Rightarrow x=\frac{-3}{7}:3=\frac{-1}{7}\)
Lưu ý nhé viết dấu nhân thì viết \("."\)một thể, \("\times"\)một thể. Còn dâu phảy của số thập phân thì viết ",'' nhé
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tìm x \(6\times\left(x-\frac{1}{y}\right)=3\times\left(y-\frac{1}{z}\right)=2\times\left(z-\frac{1}{x}\right)\)