a. \(\left(\dfrac{17}{2}+\dfrac{1}{2}+1\right).\dfrac{4}{7}\)

\(=\dfrac{19}{2}.\dfrac{4}{7}=\dfrac{38}{7}\)

b. \(\dfrac{2727}{2323}.\dfrac{69}{54}\)

\(=\dfrac{27}{23}.\dfrac{23.3}{27.2}=\dfrac{3}{2}\)

2. Chiều cao hình bình hành là: 1200 : 60 = 20 cm

a, \(\dfrac{17}{2}\) \(\times\) \(\dfrac{4}{7}\) + \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{4}{7}\)                   b, \(\dfrac{1515}{2323}\) \(\times\) \(\dfrac{69}{54}\) \(\times\) \(\dfrac{2727}{1515}\)

= \(\dfrac{17}{2}\) \(\times\) \(\dfrac{4}{7}\) + \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{4}{7}\) \(\times\) 1             = \(\dfrac{15}{23}\) \(\times\) \(\dfrac{23}{18}\) \(\times\) \(\dfrac{27}{15}\)

= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{17}{2}\) + \(\dfrac{1}{2}\) +  1)                          =   \(\dfrac{27}{18}\) 

= \(\dfrac{4}{7}\) \(\times\) ( 9 + 1)                                     = \(\dfrac{3}{2}\)

= \(\dfrac{4}{7}\times10\)

= \(\dfrac{40}{7}\)

Bài 2: Chiều cao của hình bình hành là: 

            1200 : 60 = 20 cm

           Đổi 20 cm = 2 dm

         Đáp số: 2 dm 

Tính

12x19/18=12,6666666667

 15:25/4=2,4

 1212/1515:2727/25225=7,40007334067

1414+1515+1616+1717+1818+1919/2020+2121+2222+2323+2424+2525=2525 nhé bạn

=20/27

bằng \(\frac{20}{27}\)

1212/1515 :2727/2525=4/5:27/25=4/5.25/27=20/27

Học tốt!

\(\frac{1212}{1515}:\frac{2727}{2525}\)

\(=\frac{1212}{1515}x\frac{2525}{2727}\)

\(=\frac{20}{27}\)

Chúc Học tốt

\(\frac{1212}{1515}:\frac{2727}{2525}=\frac{1212}{1515}x\frac{2525}{2727}=\frac{12x101}{15x101}x\frac{25x101}{27x101}=\frac{12x25}{15x27}=\frac{3x4x5x5}{3x5x27}=\frac{4x5}{27}=\frac{20}{27}.\)

Thanks

\(\frac{1414+1515+1616+1717+1818+1919}{2020+2121+2222+2323+2424+2525}\)

\(=\frac{101\times\left(14+15+16+17+18+19\right)}{101\times\left(20+21+22+23+24+25\right)}\)

\(=\frac{14+15+16+17+18+19}{20+21+22+23+24+25}\)

+) Tử số :

Số các số hạng là : ( 19 - 14 ) : 1 + 1 = 6 ( số )

Tổng là : ( 19 + 14 ) x 6 : 2 = 99

+) Mẫu số :

Số các số hạng là : ( 25 - 20 ) : 1 + 1 = 6 ( số )

Tổng là : ( 25 + 20 ) x 6 : 2 = 135

\(\Leftrightarrow\frac{99}{135}=\frac{11}{15}\)

\(\frac{1414+1515+1616+1717+1818+1919}{2020+2121+2222+2323+2424+2525}\)

= \(\frac{\left(1414+1919\right)+\left(1515+1818\right)+\left(1616+1717\right)}{\left(2020+2525\right)+\left(2121+2424\right)+\left(2222+2323\right)}\)

= \(\frac{3333+3333+3333}{4545+4545+4545}=\frac{3333}{4545}=\frac{11}{15}\)

t i c k nhé!! 45435436457

11/15

11/15

\(\frac{1010+1111+1212+1313+1414+1515+1616+1717}{2020+2121+2222+2323+2424+2525+2626+2727}\)

\(=\frac{101.10+101.11+...+101.17}{101.20+101.21+...+101.27}\)

\(=\frac{101.\left(10+11+...+17\right)}{101.\left(20+21+...+27\right)}\)

\(=\frac{108}{188}\)

\(=\frac{27}{47}\)

\(2>\left(\frac{1}{6}+\frac{2}{15}+\frac{3}{40}+\frac{4}{96}\right)\cdot5.y>\frac{5}{6}\)

\(\Rightarrow2>\left(\frac{1}{6}+\frac{2}{15}+\frac{3}{40}+\frac{1}{24}\right):5.y>\frac{5}{6}\)

\(\Rightarrow2>\left(\frac{20}{120}+\frac{16}{120}+\frac{9}{120}+\frac{5}{120}\right):5.y>\frac{5}{6}\)

\(\Rightarrow2>\frac{5}{12}:5.y>\frac{5}{6}\)

\(\Rightarrow2>\frac{1}{12}.y>\frac{5}{6}\)

Đặt :\(\frac{1}{12}.y=2\Rightarrow y=2:\frac{1}{12}=24\)

\(\frac{1}{12}.y=\frac{5}{6}\Rightarrow y=\frac{5}{6}:\frac{1}{12}=10\)

\(\Rightarrow24>y>10\)

\(\Rightarrow y\in\left\{11;12;...;23\right\}\)

ko biết

I am sorry

Kb nhé