\(M=\frac{131.145+100}{45-132.145}\)

\(=\frac{131-\frac{100}{145}}{\frac{45}{145}-132}\)

\(=\frac{131-\frac{20}{29}}{\frac{9}{29}-132}\)

\(=\frac{131\frac{-20}{29}}{-132\frac{9}{29}}\)

\(\frac{131.145+100}{45-132.140}=\frac{132.145-45}{45-132.140}=-1\)

\(\frac{49^6.5-7^{11}}{\left(-7\right)^{10}.5+2.49^5}=\frac{7^{11}.7-7^{11}.1}{7^{10}.5+2.7^{10}}=\frac{7^{11}.\left(7-1\right)}{7^{10}.\left(5+2\right)}=\frac{7^{11}.6}{7^{11}}=6\)

\(\frac{131.145+100}{45-132.145}=\frac{131.145+100}{45-145-131.145}=\frac{131.145+100}{-100-131.145}=\frac{131.145+100}{-\left(131.145+100\right)}=-1\)

Kết quả: -1285

                9

a) 2.5³-3.2+4⁵:4³
= 2.125-6+16
= 250+10
= 260

250-6 + 4^5-3 =>250-6 + 4² =>250-6 + 16 =>260

=260

ssh = (100 - 2) : 2 + 1 = 50 (số hạng)

=> B = (100 + 2) x 50 : 2 = 2550

45.69-31(-45)

=45.69+31.45

=45(69+31)

=45.100

=4500

Vậy kq là 4500

CHÚC BẠN HỌC TỐT!!!^^

NHỚ K CHO MIK NHHA!!!

=45.69 + 31.45

= 45.(69+31)

=45.100=4500

45.69-31(-45)

=45.69-(-31).45

=45.[69-(-31)]

=45.100

=4500

CHO XIN K

\(\frac{5}{2.4}+\frac{5}{4.6}+\frac{5}{6.8}+....+\frac{5}{48.50}\)

\(=\frac{5}{2}.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{48}-\frac{1}{50}\right)\)

\(=\frac{5}{2}.\left(\frac{1}{2}-\frac{1}{50}\right)\)

\(=\frac{5}{2}.\frac{12}{25}=\frac{6}{5}\)

\(\frac{5}{2.4}+\frac{5}{4.6}+\frac{5}{6.8}+...+\frac{5}{48.50}\)

\(=\frac{2}{5}.\left(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+...+\frac{2}{48.50}\right)\)

\(=\frac{2}{5}.\left(\frac{4-2}{2.4}+\frac{6-4}{4.6}+\frac{8-6}{6.8}+...+\frac{50-48}{48.50}\right)\)

\(=\frac{2}{5}.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{48}-\frac{1}{50}\right)\)

\(=\frac{2}{5}.\left(\frac{1}{2}-\frac{1}{50}\right)\)

\(=\frac{2}{5}.\frac{12}{25}\)

\(=\frac{24}{125}\)