tìm x
a, 697 : 15 . x + 364 / x =17
b, 92 . 4 - 27 = x + 350 / x + 315
1500 : [ ( 30x + 40 ) : x ] = 30
92 x 4 - 27 = x + 350 :x + 315
697 : 15x + 364 : x = 17
tìm số tự nhiên x biết:
a) 697 : \(\dfrac{15:x+364}{x}\) = 17
b) 92 : 4 - 27 = \(\dfrac{x+350}{x}\) + 315
c) 720 : [41 - ( 2x - 5 )] = 23 . 5
mọi ngườ giúp em câu này với ạ .
b, 92 : 4 - 27 = \(\dfrac{x+350}{x}\) + 315
23 - 27 = 1 + \(\dfrac{350}{x}\) + 315
316 + \(\dfrac{350}{x}\) = -4
\(\dfrac{350}{x}\) = - 316 - 4
\(\dfrac{350}{x}\) = -320
-320 \(x\) = 350
\(x\) = 350: (-320)
\(x\) = - \(\dfrac{35}{32}\) (loại)
Vậy \(x\) \(\in\) \(\varnothing\)
c, 720 : [ 41 - (2\(x\) - 5)] = 23.5
41 - (2\(x\) - 5) = 720 : (23.5)
41 - 2\(x\) + 5 = 18
46 - 2\(x\) =18
2\(x\) = 46 - 18
2\(x\) = 28
\(x\) = 28: 2
\(x\) = 14
Vậy \(x\) = 14
Tìm x :
a) [ ( x + 32 ) - 17 ] * 2 = 42
b) [ 61 + ( 53 - x ) ] * 17 = 1785
c) 697 : 15x + 364 / x = 17
d) 92 * 4 - 27 = x + 350 / x + 315
[(x + 32) - 17] . 2 = 42
(x + 32) - 17 = 42 : 2
(x + 32) - 17 = 21
x + 32 = 21 + 17
x + 32 = 38
x = 38 - 32
x = 6
Vậy x = 6
a) [ (x + 32 ) - 17 ] * 2 = 42
[ (x + 32 ) - 17 ] = 42 : 2
(x + 32 ) - 17 = 21
(x + 32 ) = 21 + 17
x + 32 = 38
x = 38 - 32
x = 6
tìm x:
\(697:\frac{15.x+364}{x}=17\)
\(92.4-27=\frac{x+350}{x}+315\)
tìm x:
\(697:\frac{15.x+364}{x}=17\)
\(92.4-27=\frac{x+350}{x}+315\)
\(697:\frac{15x+364}{x}=17\)
\(\frac{15x+364}{x}=697:17=41\)
\(\frac{15x}{x}+\frac{364}{x}=41\)
\(15+\frac{364}{x}=41\)
\(\frac{364}{x}=41-15=26\)
\(x=364:26=14\)
\(92.4-27=\frac{x+350}{x}+315\)
\(\frac{x+350}{x}+315=341\)
\(\frac{x+350}{x}=341-315=26\)
\(\frac{x}{x}+\frac{350}{x}=26\)
\(1+\frac{350}{x}=26\)
\(\frac{350}{x}=26-1=25\)
\(x=350:25=14\)
Tìm a biết:
Câu a: 697 : 15*a+34/a = 17
Câu b: 92 x 4 - 27 = a+350/a + 315
a, x-4867=(175x2050x70) :25+23
b,697:15.x+364/x=17
c, 92x4-27=x+350/x+315
Tìm số tự nhiên a biết:
a)697 : (15 . a + 364 / a) = 17
b)92 . 4 - 27 = (a + 350 / a) + 315
Tìm x thuộc N biết:
a) 697 ; 15 . x + 36 . 4/ x =17
b) 92 . 4 - 27 = x + 350/x + 315
c) 720 : [ 41 - ( 2 .x - 5 ) ] = 2^3 . 5
d) ( 2 +1 ) + ( x + 2 ) + ( x + 3) +...+ ( x +100 ) = 5750