trả lời đầy đủ cả bài giải nhé
 

Từ đề bài ta có được các đẳng thức sau

x=24.r₁+5

x=26.r₂+5

r₁-r₂=2=>r₁=r₂+2

thay vào biểu thức đầu ta được

x=24.(r₂+2)+5=24r₂+48+5=24r₂+53

=>2r₂-48=0

r₂=24

x=24.24+5=581

bạn Trần Quang Đài nhớ lại xem mình có làm sai không nhé, nếu đung mình k cho

Tui chỉ ấn 629 thui

co le la vay 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Gọi n là thương của phép chia cho 26, ta được:

26 x n + 5 = 24 x (n+2) + 5 = 24 x n + 48 + 5

2 x n = 48

n = 48 : 2 = 24

Số cần tìm là:

26 x 24 + 5 = 629

Đáp số:629

Ai tích mình mình tích lại cho(đi mà)

dòng ý vói Le Nho khong nho

số đo là 629

k di mk k lai

em biết chắc câu 2 thôi 

đáp án câu 2 là 23

Bài 1:

Theo đề bài ta có:

\(a=4q_1+3=9q_2+5\) (\(q_1\) và \(q_2\) là thương trong hai phép chia)

\(\Rightarrow\left[\begin{matrix}a+13=4q_1+3+13=4\left(q_1+4\right)\left(1\right)\\a+13=9q_2+5+13=9\left(q_2+2\right)\left(2\right)\end{matrix}\right.\)

Từ (1) và (2) suy ra: \(a+13=BC\left(4;9\right)\)

Mà \(Ư\left(4;9\right)=1\Rightarrow a+13=BC\left(4;9\right)=4.9=36\)

\(\Rightarrow a+13=36k\left(k\ne0\right)\)

\(\Rightarrow a=36k-13=36\left(k-1\right)+23\)

Vậy \(a\div36\) dư \(23\)

Câu 1

Theo bài ra ta có:

\(a=4q_1+3=9q_2+5\)(q1 và q2 là thương của 2 phép chia)

\(\Rightarrow a+13=4q_1+3+13=4\left(q_1+4\right)\left(1\right)\)

và \(a+13=9q_2+5+13=9.\left(q_2+2\right)\left(2\right)\)

Từ (1) và (2) ta có \(a+13\) là bội của 4 và 9 mà ƯC(4;9)=1

nên a là bội của 4.9=36

\(\Rightarrow a+13=36k\left(k\in N\right)\)

\(\Rightarrow a=36k-13\)

\(\Rightarrow a=36.\left(k-1\right)+23\)

Vậy a chia 36 dư 23

Bài 3:

\(a,2^{1000}\div5\)

Ta có:

\(2^{1000}=\left(2^4\right)^{250}=\overline{\left(...6\right)}^{250}=\overline{\left(...6\right)}\)

Vì a có tận cùng là 6

\(\Rightarrow2^{1000}\div5\) dư \(1\)

 Vì số đó chia cho 26 và 24 đều dư 5 nên nếu bớt đi 5 đơn vị thì số đó chia hết cho cả 24 và 26. 
Số chia hết cho 24 và 26 là 312, 624, 936.... 
Số cần tìm là 317, 629, 941... 
Nhận thấy 941 : 24 = 39 dư 5 và 941 : 26 = 36 dư 5 
mà 39 - 36 = 3 
Vậy Số cần phải tìm là 941 

CHÚC BẠN HỌC GIỎI

TK MÌNH NHÉ

sorry nha mk hết lượt ồi