a 2^x-15=17
b (7x-11)^3=2^5*5^2+200
a)x^20=x;b)2^x* 16^2=1024;c)64*4x=16^8;d)2^x-15=17;e)(7x-11)^3=2^5*5^2+200
x^20-x=0
x(x^19-1)=0
x= 0
hoặc x ^ 19 =1
x = 0 hoặc x= 1
Tìm x
720 : [41-(2x-5)] =2^3 . 5
2^x = 15 = 17
(7x-11)^3= 2^5.5^2+200
720 : [41-(2x-5)] =2^3 . 5
<=> 41-(2x-5)=720:40=18
<=> 2x-5=41-18=23
<=>2x=23+5=28
<=> x=28:2=14
2^x-15=17
<=> 2^x=17+15=32
<=> 2^x=2^5
<=> x=5
(7x-11)^3= 2^5.5^2+200
<=> (7x-11)^3=1000
<=> (7x-11)^3=10^3
<=> 7x-11=10
<=> 7x=10+11=21
<=> x=21:7=3
TÌM X
(7x-11)^3=2^5.5^2+200
x^10=x
(2x-15)^5=(2x-15)^3
b) x^10=1x
=> x=0 ; 1
c)(2x-15)^5=(2x-15)^3
=> (2x-15)^4 = (2x-15)^2
=> (2x-15)^2 =1
=> 2x-15=1
=> x=8
Tìm x
1) (7x - 11)x = 25.52+200
2) (2x - 15)5 = (2x - 15)3
thì cứ tính bên phải trước rồi tìm x như thường thôi
a. 2^x - 15 = 17
b. 27 . 3^x = 243
c. 3^x + 25 = 26 . 2^2 + 2 . 3^0
d. ( 7x - 11 )^3 = 2^5 . 5^2 + 200;
e. 3^x . 3 = 27
a) \(2^x-15=17\)
\(2^x=17+15\)
\(2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
b) \(27.3^x=243\)
\(3^x=243:27\)
\(3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
c) \(3^x+25=26.2^2+2.3^0\)
\(3^x+25=104+2\)
\(3^x+25=106\)
\(3^x=106-25\)
\(3^x=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
d) \(\left(7x-11\right)^3=2^5.5^2+200\)
\(\left(7x-11\right)^3=800+200\)
\(\left(7x-11\right)^3=1000\)
\(\Rightarrow\left(7x-11\right)^3=10^3\)
\(\Rightarrow7x-11=10\)
\(7x=10+11\)
\(7x=21\)
\(x=21:7\)
\(x=3\)
e) \(3^x.3=27\)
\(3^x=27:3\)
\(3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
a) \(2^x-15=17\)
\(\Leftrightarrow2^x=17+15\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
Vậy x = 5
b) \(27.3^x=243\)
\(\Leftrightarrow3^x=243:27\)
\(\Leftrightarrow3^x=9\)
\(\Leftrightarrow3^x=3^2\)
\(\Leftrightarrow x=2\)
Vậy x = 2
c) \(\left(7x-11\right)^3=2^5.5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=800+200\)
\(\Leftrightarrow\left(7x-11\right)^3=1000\)
\(\Leftrightarrow\left(7x-11\right)^3=10^3\)
\(\Leftrightarrow7x-11=10\)
\(\Leftrightarrow7x=10+11\)
\(\Leftrightarrow7x=21\)
\(\Leftrightarrow x=21:7\)
\(\Leftrightarrow x=3\)
Vậy x = 3
d) \(3^x.3=27\)
\(\Leftrightarrow3^x=27:3\)
\(\Leftrightarrow3^x=9\)
\(\Leftrightarrow3^x=3^2\)
\(\Leftrightarrow x=2\)
Vậy x = 2
_Chúc bạn học tốt_
tìm số tự nhiên x biết
a, 2x - 15 =17
b, ( 7x - 11)3 = 25 x 52+200
c,(2x - 15 )5 = 2x - 153
tìm số tự nhiên x biết
a, 2x - 15 =17
=> 2x = 17 + 15 = 32
=> 2x = 25
=> x = 5
b, ( 7x - 11)3 = 25 x 52+200
=> ( 7x - 11 )3 = 32 . 25 + 200
=> ( 7x - 11 )3 = 1000
=> ( 7x - 11 )3 = 103
=> 7x - 11 = 10
=> 7x = 10 + 11 = 21
=> x = 21 : 7 = 3
2x - 15 = 17
(7x-11)3 = 25 .52 + 200
Bài của Trịnh Tiến Đức sai câu đầu tiên rồi nhé
a, => 2x=2
=> x=1
b, => (7x-11)3=1000
=> 7x-11=10
=> 7x=21
=> x=3
Tìm x thuộc N biết:
a, (7x - 11)3 = 25 . 52 + 200
b, (2x - 15)5 = (2x - 15)3
tìm x
(7x-11)3=25.52+200
2 x - 15=17
Toán lớp 6Lũy thừa
2^x-15=17
<=> 2^x=17+15=32
<=> 2^x=2^5
<=> x=5
(7x-11)^3= 2^5.5^2+200
<=> (7x-11)^3=1000
<=> (7x-11)^3=10^3
<=> 7x-11=10
<=> 7x=10+11=21
<=> x=21:7=3