5 mu n nhan 5 mu n cong 1 nhan 5 mu n cong 2 be hon hoac bang 10 mu 18
a, 2nhan16>hoac bang 2 mu x nhan 74
b, 25 nho hon 5mu x nhan 5 mu 2 nho hon hoac bang 125
3 mu 3 nhan 9 tru 3 mu 4 nhan 3 cong 5 mu 8 nhan 5 mu 0 tru 5 mu 12 chia 25 mu 2
= 3^6 - 4 x 3 + 5^8 x 5^0 : 25^2
= 729 - 12 + 5^8 x 5^0 : 5^4
= 729 - 12 + 5^4
= 729 - 12 + 625
= 717 + 625
= 1342
\(3^3.9-3^4+5^8.5^0-5^{12}:25^2\)
\(=27.9-81+3905625.1-244140625:625\)
\(=-1235961951^{13}\)
tim x y thuoc z biet x mu 2 cong y nhan x cong y mu 2 bang x mu hai nhan y mu hai
1) Tính:
a) A = 7 mu 2 phan 2 nhan 9 cong 7 mu 2 phan 9 nhan 16 cong 7 mu 2 phan 16 nhan 23 cong van van cong 7 mu 2 phan 65 nhan 72
5 mu 6 cia 5 mu 3 cong 3 mu2 nhan 3 mu 3 tru 3 mu 4 nhan 3
5 mu 6 chia 5 mu 3 cong 3 mu 2 3 mu3 tru 3 mu 4 nhan 3
chung minh rang 8 mu 10 cong 2 mu 20 chia het cho 41
chung minh rang 313 mu 6 nhan 36 tru 313 mu 5 nhan 299 chia het cho 7
8^8+2^20
=(2^3)^8+2^20
=2^(3.8)+2^20
=2^24+2^20
=2^20.2^4+2^20
=2^20.(2^4+1)
=2^20.17 chia hết cho 17
k mk nha thanks bạn
chứng minh ý a 8mu10 cong 2 mũ 20 chia hết cho41
chứng minh ý b 31 mu36 nhận 36 -313 mu 5 nhận 299 chia hết ch
chung minhý c 3 mu n công 3 cộng 2 mu n công 3 công 2 mu n công 2 công 2 mu n công 2 chia hết 6
chung minh y d d=2 cong 2 mu 2 cong 2mu 3 cong 2 mu 4 cong 2 mu 5 cong 2 mu 6 cong ....cong 2 mu 58 cong 2 mu 59 cong 2 mu 60 chia het cho 31
chung minh y e, e= 1cong 3 cong 3 mu 2 cong 3 mu 3 cong..cong 3 mu 98 cong 3 mu 99 chung minh e chia het cho5 chia het cho11
CHO A= 3+3MU2+3mu3+3mu4+...+3mu2017 a) tim so tu nhien N biet 2A +3 = 3n b)tim chu so tan cung cua A
chung to rang B = 1/2mu 2 cong 1/3 mu 2 cong 1/4 mu 2 cong 1/5 mu 2 cong 1/6 mu 2cong 1/7 mu 2 cong 1/8 mu2 nho hon 1
2 mu m cong 2 mu n bang 2 mu m cong n tim m va n