Ta có: \(A=\dfrac{3^{10}+1}{3^9+1}\)

\(\Leftrightarrow A=\dfrac{3^{10}+3-2}{3^9+1}\)

hay \(A=3-\dfrac{2}{3^9+1}\)

Ta có: \(B=\dfrac{3^9+1}{3^8+1}\)

\(\Leftrightarrow B=\dfrac{3^9+3-2}{3^8+1}\)

hay \(B=3-\dfrac{2}{3^8+1}\)

Ta có: \(3^9+1>3^8+1\)

\(\Leftrightarrow\dfrac{2}{3^9+1}< \dfrac{2}{3^8+1}\)

\(\Leftrightarrow-\dfrac{2}{3^9+1}>-\dfrac{2}{3^8+1}\)

\(\Leftrightarrow-\dfrac{2}{3^9+1}+3>-\dfrac{2}{3^8+1}+3\)

hay A>B

Ta có: 

\(\frac{1}{3}\)A = \(\frac{3^{10}+1}{3^{10}+3}\)

            = \(\frac{3^{10}+1}{3^{10}+1+2}\)

            = \(1+\frac{3^{10}+1}{2}\)

\(\frac{1}{3}\)B = \(\frac{3^9+1}{3^9+3}\)

            = \(\frac{3^9+1}{3^9+1+2}\)

            = 1 + \(\frac{3^9+1}{2}\)

Đương nhiên \(1+\frac{3^{10}+1}{2}\)  > 1 + \(\frac{3^9+1}{2}\)

=> A > B

        phân số đấy ạ bà con

nhanh tay giải toán dược ngay điểm 10

A= 1/3+1/6+1/10+...+1/561

  = 2. (1/6+1/12+1/20+...+1/1122)

  = 2. [1/(2.3) + 1/(3.4) + 1/(4.5) +...+1/(33.34)]

  = 2. ( 1/2 - 1/3 +1/3 - 1/4 + 1/4 - 1/5 +...+ 1/33 - 1/34 )

  =2. (1/2 - 1/34)

  =2. 8/17

  =16/17

Vì 16/17 > 16/18 = 8/9 -> A > 8/9

ta có 

A/B=3^10+1/3^9+1 : 3^9+1/3^8+1

A/B=3^10+1/3^9+1 . 3^8+1/+3^9+1

A/B=(3^10+1).(3^8+1)/(3^9+1).(3^9+1)

A/B=3^18+3^10+3^8+1/3^18+3^9+3^9+1

Ta so sánh    3^10+3^8   và   3^9+3^9

                 3^8.(3^2+1)    và   3^8.(3+3)

                3^8.10             và    3^8.6

            vì   3^8.10  > 3^8.6

            nên  A>B