a)  3 4 = 6 8 < 6 7

b)  17 − 21 = 51 − 63 > 51 − 31

minh ko lam duoc'

a: -3/4=-9/12

-5/6=-10/12

mà -9>-10

nên -3/4>-5/6

b: -5/17<0<2/7

c: 11/10>1>9/14

ta có :

\(A=\frac{67^{2016}}{67^{2016}-11}=1+\frac{11}{67^{2016}-11}\)

\(B=\frac{67^{2016}+13}{67^{2016}+2}=1+\frac{11}{67^{2016}+2}\)

Vì \(67^{2016}-11< 67^{2016}+2\Rightarrow A>B\)

a) Ta có:

\(1-\frac{2005}{2006}=\frac{1}{2006}\)

\(1-\frac{2006}{2007}=\frac{1}{2007}\)

Vì \(\frac{1}{2006}>\frac{1}{2007}\)nên \(\frac{2005}{2006}>\frac{2006}{2007}\)

b) Ta có:

\(\frac{2008}{2007}-1=\frac{1}{2007}\)

\(\frac{2007}{2006}-1=\frac{1}{2006}\)

Vì \(\frac{1}{2006}>\frac{1}{2007}\)nên \(\frac{2008}{2007}< \frac{2007}{2006}\)

a, \(\frac{2005}{2006}v\text{à}\frac{2006}{2007}\)= \(\frac{2005\cdot2007}{2006\cdot2007}\)và \(\frac{2006\cdot2006}{2007\cdot2006}\)

= \(\frac{4024035}{4026042}\)< \(\frac{4024036}{4026042}\)

b, \(\frac{2008}{2007}v\text{à}\frac{2007}{2006}\)= \(\frac{2008\cdot2006}{2007\cdot2006}v\text{à}\frac{2007\cdot2007}{2006\cdot2007}\)

=\(\frac{4028048}{4026042}\)< \(\frac{4028049}{4026042}\)

a) \(\frac{17}{30}>\frac{51}{92}\)

b) \(\frac{-45}{47}>\frac{31}{-30}\)

c) \(\frac{22}{67}< \frac{51}{152}\)

d) \(-\frac{17}{39}< -\frac{17}{41};\frac{18}{-39}< -\frac{17}{41}\)