A ) x = 5/24

B ) x = 7/15

\(\frac{1}{6}=\frac{x}{18}\Rightarrow x=3\)

\(\frac{x}{8}=-\frac{1}{4}\Rightarrow x=-2\)

\(\frac{4}{-5}=\frac{x}{10}\Rightarrow x=-8\)

\(\frac{11}{5}=-\frac{22}{x}\Rightarrow x=-10\)

\(\frac{x}{8}=\frac{8}{x}\Rightarrow x^2=64\Rightarrow x=8\)

\(\frac{x}{-11}=-\frac{11}{x}\Rightarrow x^2=121\Rightarrow x=11\)

#H

Sửa đè \(\sqrt{x^2+10x+21}=3\sqrt{x+3}+2\sqrt{x+7}-6\)

Đk:\(x\ge-3\)

\(pt\Leftrightarrow\sqrt{\left(x+3\right)\left(x+7\right)}=3\sqrt{x+3}+2\sqrt{x+7}-6\)

Đặt \(\hept{\begin{cases}\sqrt{x+3}=a\\\sqrt{x+7}=b\end{cases}\left(a,b>0\right)}\) thì 

\(\Leftrightarrow ab=3a+2b-6\)

\(\Leftrightarrow\left(a-2\right)\left(b-3\right)=0\Rightarrow\orbr{\begin{cases}a=2\\b=3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}\sqrt{x+3}=2\\\sqrt{x+7}=3\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=1\\x=2\end{cases}}\) (thỏa)

ban oi viet dau can kieu gi vay

a)

\(\dfrac{x}{2}=\dfrac{y}{3};\dfrac{y}{4}=\dfrac{z}{5}\)

\(\Rightarrow\dfrac{x}{8}=\dfrac{y}{12};\dfrac{y}{12}=\dfrac{z}{15}\)

\(\Rightarrow\dfrac{x}{8}=\dfrac{y}{12}=\dfrac{z}{15}\)

\(\Rightarrow\dfrac{x^2}{64}=\dfrac{y^2}{144}=\dfrac{z^2}{225}\)

Áp dụng tính chất dãy tỉ số bằng nhau ta có:

\(\dfrac{x^2}{64}=\dfrac{y^2}{144}=\dfrac{x^2-y^2}{64-144}=\dfrac{16}{-80}=\dfrac{1}{-5}\)

Vì \(x^2;y^2;z^2\ge0\) nên không tồn tại 3 số cần tìm