\(\frac{1}{2}\times\frac{1}{4}\times\frac{1}{8}\times\frac{1}{16}\times\frac{1}{32}\times\frac{1}{64}=\)
1.Tính:
8 :8= 16:8= 24:8=
32:8= 40:8= 48:8=
56:8= 64:8= 72:8=
80:8=
2.Số?
\(...\times\frac{1}{8}=1\) \(...\times\frac{1}{8}=2\)\(...\times\frac{1}{8}=3\)\(...\times\frac{1}{8}=4\)
\(...\times\frac{1}{8}=5\) \(...\times\frac{1}{8}=6\)\(...\times\frac{1}{8}=7\)
\(...\times\frac{1}{8}=8\)\(...\times\frac{1}{8}=9\)
\(...\times\frac{1}{8}=10\)
8 : 8 = 1 16 : 8 = 2 24 : 8 = 3 32 : 8 = 4 40 : 8 = 5 48 : 8 = 6 56 : 8 = 7 64 : 8 = 8 72 : 8 = 9 80 : 8 = 10
8 : 8 = 1
16 : 8 = 2
24 : 8 = 3
32 : 8 = 4
40 : 8 = 5
48 : 8 = 6
56 : 8 = 7
64 : 8 = 8
72 : 8 = 9
80 : 8 = 10
\(\frac{1}{4}\times\frac{2}{6}\times\frac{3}{8}\times...\times\frac{30}{62}\times\frac{31}{64}\)
\(=\frac{1x2x3x...x30x31}{2^{31}x\left(2x3x4x...x31x32\right)}=\frac{1}{2^{31}x32}=\frac{1}{2^{36}}\)
\(\frac{1}{4}\times\frac{2}{6}\times\frac{3}{8}\times\frac{4}{10}\times\frac{5}{12}.....\frac{30}{62}\times\frac{31}{64}=2^x\)
\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}.....\frac{30}{62}.\frac{31}{64}=2^x\)
=>\(\frac{1}{2.2}.\frac{2}{2.3}.\frac{3}{2.4}.\frac{4}{2.5}.\frac{5}{2.6}....\frac{30}{2.31}.\frac{31}{2.32}=2^x\)
=>\(\frac{1.2.3.4.5....30.31}{2.2.2.3.2.4.2.5.2.6...2.31.2.32}=2^x\)
=>\(\frac{2.3.4.5...30.31}{2^{31}.32.\left(2.3.4.5...31\right)}=2^x\)
=>\(\frac{1}{2^{31}.2^5}=2^x\)
=>\(\frac{1}{2^{36}}=2^x\)
=> x=36
Vậy x=36
Chúc bn học tốt nhé!
\(\left(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}\right)\times x=1\)
= (64/256 + 32/256 + 16/256 + 8/256 + 4/256 + 2/256) X x =1
= 126 X x = 1
x = 1 : 126
x= 1/126
Tìm x biết : \(\frac{1}{4}\times\frac{2}{6}\times\frac{3}{8}\times\frac{4}{10}\times.......\times\frac{30}{62}\times\frac{31}{64}=2^x\)
\(\frac{1.2.3....31}{2^{30}.\left(2.3....31\right).32}=\frac{1}{2^{31}.32}=\frac{1}{2^{36}}=2^{-36}=2^x\)
Vậy x=-36
Hok tốt
\(\frac{1}{3}\times\frac{2}{5}\times\frac{3}{7}\times\frac{4}{9}\times\frac{5}{11}\times\frac{6}{15}\times\frac{7}{15}\times\frac{8}{15}\times\frac{9}{19}\times\frac{10}{21}\times\frac{11}{32}\times\frac{12}{25}\times\left\{\frac{126}{252}-\frac{2}{4}\right\}\)
Để nhân các phân số này, ta chỉ cần nhân tử số với nhau và mẫu số với nhau:
\[
\frac{1}{3} \times \frac{2}{5} \times \frac{3}{7} \times \frac{4}{9} \times \frac{5}{11} \times \frac{6}{15} \times \frac{7}{15} \times \frac{8}{15} \times \frac{9}{19} \times \frac{10}{21} \times \frac{11}{32} \times \frac{12}{25} \times \left( \frac{126}{252} - 4 \right)
\]
Sau đó, ta thực hiện các phép tính:
1. Nhân tử số:
\[1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9 \times 10 \times 11 \times 12 \times 126 = 997920\]
2. Nhân mẫu số:
\[3 \times 5 \times 7 \times 9 \times 11 \times 15 \times 15 \times 15 \times 19 \times 21 \times 32 \times 25 \times 252 = 7621237680\]
Kết quả là:
\[\frac{997920}{7621237680}\]
Bây giờ, ta có thể rút gọn phân số này bằng cách chia tử số và mẫu số cho 160:
\[ \frac{997920}{7621237680} = \frac{997920 ÷ 160}{7621237680 ÷ 160} = \frac{6237}{47695230} \]
tìm x biết
\(x+\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{90}=\frac{4}{3}\times\frac{9}{8}\times\frac{16}{15}\times....\times\frac{100}{99}+\frac{9}{110}\)
ta gọi \(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{90}\)là A
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\)
\(\Leftrightarrow1.\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{9}-\frac{1}{10}\right)\)
\(\Rightarrow A=1-\frac{1}{10}=\frac{9}{10}\)
ta gọi B là biểu thức thứ2
\(B=\frac{2.2}{3}\times\frac{3.3}{2.4}\times\frac{4.4}{3.5}\times...\times\frac{10.10}{9.11}\)
\(\Rightarrow\)2 x \(\frac{10}{11}\)\(=\frac{20}{11}\)
\(\Rightarrow\)\(x+\frac{9}{10}=\frac{20}{11}+\frac{9}{110}\)
\(\Rightarrow x=1\)
mk nghĩ vậy bạn ạ, mk mong nó đúng
a ) \(\frac{5}{6}-\frac{26}{5}\times\frac{1}{13}\)
b ) \(\subset\frac{19}{23}-\frac{22}{46}\supset\times\frac{23}{16}\)
c ) \(\frac{25}{8}\times\frac{14}{30}\)
d ) \(\subset\frac{3}{4}\times\frac{5}{7}\supset\times\subset\frac{20}{9}\times\frac{14}{15}\supset\)
e ) \(\frac{4}{35}\times\frac{25}{32}\times\frac{38}{24}\)
g ) \(\frac{1}{2}\times\frac{3}{4}\times\frac{2}{3}\times\frac{4}{5}\)
h ) \(\frac{5}{6}\times\frac{11}{4}-\frac{5}{4}\times\frac{23}{6}\)
i ) \(\frac{9}{16}\times\frac{13}{4}-\frac{9}{4}\times\frac{5}{16}+\frac{9}{16}\times\frac{17}{4}\)
k ) \(\subset7\times\frac{1}{3}\supset\times\subset\frac{1}{7}\times6\supset\)
m ) \(\frac{2}{3}\times\subset\frac{3}{5}+\frac{3}{7}\supset\)
n ) \(\frac{4}{5}\times\subset\frac{5}{8}+\frac{7}{4}\supset\)
p )\(\subset\frac{1}{33}+\frac{31}{333}-\frac{341}{3333}\supset\times\subset\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\supset\)
a.5/6 - 26/5 X 1/13 = 13/30
b.( 19/23 - 22/46 ) X 23/46 = 3/23
c.25/8 x 14/30 = 35/24
d.( 3/4 x 5/7 ) x ( 20/9 x 14/15 ) = 10/9
e.4/35 x 25/32 x 38/24 = 95/672
g. 1/2 x 3/4 x 2/3 x 4/5 = 1/5
h.5/6 x 11/4 - 5/4 x 23/6 = -5/2
i.9/16 x 13/4 - 9/4 x 5/16 + 9/16 x 17/4 = 225/64
k.( 7 x 1/3 ) x ( 1/7 x 6 ) = 2
m.2/3 x ( 3/5 + 3/7 ) = 34/35
n.4/5 x ( 5/8 + 7/4 ) = 19/10
p.( 1/33 + 31/333 - 341/3333 ) x ( 1/2 - 1/3 - 1/6 ) = 0
mih giành cả nửa tiếng để giải đó , k nha
có một số con nhân thì bạn rút gọn chéo , cộng trừ thì bn đổi chỗ các số hạng .Còn nếu như không đc thì bn tính thường thôi
1.Tính nhanh
a,\(\frac{1}{1\times4}+\frac{1}{4\times7}+............+\frac{1}{97\times100}\)
b,\(\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times...........\times\frac{99}{100}\)
c,\(\frac{3}{4}\times\frac{8}{9}\times\frac{15}{16}\times...........\times\frac{99}{100}\)
d,\(\left(\frac{1}{2}+1\right)\times\left(\frac{1}{3}+1\right)\times\left(\frac{1}{4}+1\right)\times............\times\left(\frac{1}{99}+1\right)\)
e,\(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times..........\times\left(1-\frac{1}{100}\right)\)
a,Đặt \(A=\frac{1}{1\times4}+\frac{1}{4\times7}+...+\frac{1}{97\times100}\)
\(\Rightarrow3A=\frac{3}{1\times4}+\frac{3}{4\times7}+...+\frac{3}{97\times100}\)
\(\Rightarrow3A=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{100}\)
\(\Rightarrow3A=1-\frac{1}{100}=\frac{99}{100}\)
\(\Rightarrow A=\frac{99}{300}\)
b, \(\frac{1}{2}\times\frac{2}{3}\times...\times\frac{99}{100}=\frac{1\times2\times...\times99}{2\times3\times...\times1000}=\frac{1}{100}\)
c, \(\frac{3}{4}\times\frac{8}{9}\times...\times\frac{99}{100}=\frac{1.3}{2.2}\times\frac{2.4}{3.3}\times...\times\frac{9.11}{10.10}=\frac{1.2.....9}{2.3.....10}\times\frac{3.4.....11}{2.3.....10}=\frac{1}{10}\times\frac{11}{2}=\frac{11}{20}\) (dấu . là dấu nhân)