Tìm x :
1- (5 \(\frac{4}{9}\)+ x-7 \(\frac{7}{18}\)) : 15 \(\frac{3}{4}\)= 0
\(1-\left[5\frac{4}{9}+x-7\frac{7}{18}\right]:15\frac{3}{4}=0\)
TÌM X NHA
1.Tính x:
\(1-\left\{5-\frac{4}{9}+x-7\frac{7}{18}\right\}:15\frac{3}{4}=0\)
mik nhầm nha mn
\(1-\left\{5\frac{4}{9}+x-7\frac{7}{18}\right\}:15\frac{3}{4}=0\)
Bài làm :
Ta có :
\(...\)
\(\left\{5-\frac{4}{9}+x-7\frac{7}{18}\right\}\div15\frac{3}{4}=1\)
\(5-\frac{4}{9}+x-7\frac{7}{18}=15\frac{3}{4}\)
\(x-\frac{17}{6}=15\frac{3}{4}\)
\(x=15\frac{3}{4}+\frac{17}{6}=\frac{223}{12}\)
Vậy x=223/12
Bài làm khi sửa lại đề :
Ta có :
\(1-\left\{5\frac{4}{9}+x-7\frac{7}{18}\right\}\div15\frac{3}{4}=0\)
\(\left\{5\frac{4}{9}+x-7\frac{7}{18}\right\}\div15\frac{3}{4}=1\)
\(x-\frac{35}{18}=15\frac{3}{4}\)
\(x=15\frac{3}{4}+\frac{35}{18}=\frac{637}{36}\)
Vậy x=637/36
bài 1 : tìm x biết
a, \(\frac{2}{3}\times\left(x-\frac{5}{6}\right)+\frac{1}{4}=\frac{22}{9}\)
b, \(\frac{2}{3}:\frac{x}{5}=\frac{10}{21}\)
c, \(\frac{7}{3}:\frac{x}{5}=\frac{14}{15}\)
d, \(1-\left(5\frac{4}{9}\times x-7\frac{7}{18}\right):15\frac{3}{4}=0\)
bài 2 : tính gtri bt
a,\(\frac{8}{7}+\frac{1}{5}\times\frac{10}{9}\)
b, \(\frac{3}{2}+\left(\frac{9}{2}+\frac{2}{9}\right)\times\left(\frac{4}{3}-\frac{5}{4}\right)\)
!_ove
a) x = 99/20
b) x = 7
c) x = 2
( chỉ lm đc đến đó thui nk )
1 - ( 5\(\frac{4}{9}\)+ X - 7\(\frac{7}{18}\)) : 15\(\frac{3}{4}\)= 0
1 - (49/9 + x -133/18) : 63/4 = 0
1 - (49/9 + x -133/18) = 0 x 63/4
1 - (49/9 + x -133/18) = 0
49/9 + x -133/18 = 1 - 0
49/9 + x -133/18 = 1
49/9 + x = 1 + 133/18
49/9 + x = 151/18
x = 49/9 +151/18
x = 53/18
Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)
Tìm số nguyên x
a) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
b)\(\frac{5}{17}+\frac{-9}{4}+\frac{-26}{31}+\frac{12}{17}+\frac{-11}{31}< \frac{x}{9}\le\frac{-3}{7}+\frac{7}{15}+\frac{4}{-7}+\frac{8}{15}\)
\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)
\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)
\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)
\(\Rightarrow-1\le x< 6\)
\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)
Bài b tương tự
bạn ơi bạn giải câu b được ko. mk ko biết làm câu b
1- \(\left(5\frac{4}{9}+x-7\frac{7}{18}\right):15\frac{3}{4}\)= 0
Mk gấp lắm lun ý !!!! chiều nay mk cần rùi !!!!!
\(1-\left(5\frac{4}{9}+x-7\frac{7}{18}\right)\div15-\frac{3}{4}=0\)
khỏi chép lại đề nha
\(1-\left(\frac{49}{9}+x-\frac{133}{18}\right):15=0+\frac{3}{4}\)
\(1-\left(\frac{49}{9}+x-\frac{133}{18}\right):15=\frac{3}{4}\)
\(1-\left(\frac{49}{9}+x-\frac{133}{18}\right)=\frac{3}{4}.15\)
\(1-\left(\frac{49}{9}+x-\frac{133}{18}\right)=\frac{45}{4}\)
\(\frac{49}{9}+x-\frac{133}{18}=1-\frac{45}{4}\)
\(\frac{49}{9}+x-\frac{133}{18}=\frac{-41}{4}\)
\(\frac{49}{9}+x=\frac{-41}{4}+\frac{133}{18}\)
\(\frac{49}{9}+x=\frac{-103}{36}\)
\(x=\frac{-103}{3}-\frac{49}{9}\)
\(x=\frac{-299}{36}\)
tk mik nha
Tìm x biết:
\(1-\left(5\frac{4}{9}+x-7\frac{7}{18}\right)\div15\frac{3}{4}=0\)