\(\frac{12}{2}+2,5+2-4\)
2\(\frac{7}{9}-\frac{12}{13}x=\frac{7}{9}\)
\(x:4\frac{1}{3}=-2,5\)
\(\frac{3}{4}x\frac{1}{2}\)
a) Cho \(A=\frac{1}{5^2}+\frac{1}{6^2}+....+\frac{1}{100^2}\)
C/mR: \(\frac{1}{6}
1) \(\left(\frac{1,5+1-0,5}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)
2) A=\(\frac{1,11+0,19-1,3.2}{2,06+0,54}-\left(\frac{1}{3}+\frac{1}{2}\right):2\)
3) A= \(1+\frac{3}{2^3}+\frac{4}{2^4}+...+\frac{100}{2^{100}}\)
Tính : \(A=\frac{2,5-4\left(\frac{5}{2}-1,2\right)+\frac{3}{8}}{4\left(\frac{5}{2}-1,2\right)-\frac{3}{5}:\frac{2}{5}}-\frac{55}{148}\)
Rút gọn \(B=\frac{3^9-2^3.3^7+2^{10}.3^2-2^{13}}{3^{10}-2^2.3^7+2^{10}.3^3-2^{12}}\)
Thực hiện phép tính :
a, \(\sqrt{12\frac{1}{4}}.\left(-\frac{2}{7}\right)^2-\left[2,\left(4\right).2\frac{5}{11}\right]:(-\frac{42}{5})\)
b, \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2007}\right)\)
c, \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
Các bạn giải nhanh giúp mình nha!
27 *18 * 15 =
3,8 * 2,5 * 4 =
1,9 * 1,4 * 1,5 =
\(\frac{4}{3}x\frac{5}{4}x\frac{2}{3}=\)
15,5* 6,4 * 10 =
1,75 * 0,4 * 0,8 =
8 * 5 * 4,5 =
2 * 0,5 * 0,75 =
( 15 - 12 ) *10,5 * 8 =
10 * 4,5 *12 =
27*18*15=7290
3.8*2.5*4=38
1.9*1.4*1.5=3.99
\(\frac{4}{3}x\frac{5}{4}x\frac{2}{3}=\frac{10}{9}\)
15.5*6.4*10=992
1.75*0.4*0.8=0.56
8*5*4.5=180
2*0.5*0.75=0.75
(15-12)*10.5*8=252
10*4.5*12=540
= 7290
= 38
= 3,99
= 10 / 9
= 992
= 0,56
= 180
= 0,75
= 252
= 540
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)\)
\(4\frac{3}{4}+\left(-0,37\right)+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{12}\)
(giải giúp mình với)
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)=\frac{58}{7}-\left(\frac{7}{6}+\frac{1}{4}\right)=\frac{58}{7}-\frac{17}{12}=\frac{577}{84}\)
\(4\frac{3}{4}+\left(-0,37\right)+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{12}\)
\(=\frac{19}{4}+\left(-\frac{83}{20}\right)+\frac{37}{12}=\frac{3}{5}+\frac{37}{12}=\frac{221}{60}\)
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)=\frac{58}{7}-\left(\frac{7}{6}+\frac{1}{4}\right)=\frac{58}{7}-\frac{17}{12}=\frac{577}{84}\)
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)\)
\(=\frac{58}{7}-\left(\frac{7}{6}+\frac{1}{4}\right)\)
\(=\frac{58}{7}-\frac{17}{12}\)
\(=\frac{577}{84}\)
Tính:
1,\(\frac{2}{5}+\left(-\frac{4}{5}\right)+\left(-\frac{1}{2}\right)\)
2,\(A=\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
3,\(B=\frac{\frac{1}{3}-\frac{1}{7}-\frac{1}{13}}{\frac{2}{3}-\frac{2}{7}-\frac{2}{13}}.\frac{\frac{1}{3}-0,25+0,2}{1\frac{1}{6}-0,875+0,7}+\frac{6}{7}\)
Bài 1 : Tính giá trị của biểu thức :
1) \(\left(\frac{12}{32}+\frac{5}{-20}-\frac{10}{24}\right)\): \(\frac{2}{3}\)
2) 4\(\frac{1}{2}\): (2,5 - 3\(\frac{3}{4}\)) + \(\left(\frac{1}{2}\right)\)2
\(\left(\frac{12}{32}+\frac{5}{-20}-\frac{10}{24}\right):\frac{2}{3}=\left(\frac{1}{8}-\frac{10}{24}\right):\frac{2}{3}=-\frac{7}{24}:\frac{2}{3}=-\frac{7}{16}\)
\(4\frac{1}{2}:\left(2,5-3\frac{3}{4}\right)+\left(\frac{1}{2}\right)^2=\frac{9}{2}:\left(2,5-\frac{15}{4}\right)+\frac{1}{4}=\frac{9}{2}:-\frac{5}{4}+\frac{1}{4}=-\frac{18}{5}+\frac{1}{4}=-\frac{67}{20}\)