Tính :
A = \(\frac{25^3.5^5}{6.5^{10}}\)
dễ quá nha
Thực hiên phép tính :
\(\frac{25^3.5^5}{6.5^{10}}\)
= \(\frac{5^6.5^5}{6.5^{10}}\) = \(\frac{5^{11}}{6.5^{10}}\)= \(\frac{5}{6}\)
\(\frac{25^3.5^5}{6.5^{10}}\)=\(\frac{5^{11}}{6.5^{10}}\)=\(\frac{5}{6}\)
ok 100% chính xác
\(\frac{25^3\cdot5^5}{6\cdot5^{10}}=\frac{25^3}{6\cdot5^5}\)
\(\frac{\left(5^2\right)^3}{6\cdot5^5}=\frac{5^6}{6\cdot5^5}=\frac{5}{6}\)
TÍNH GIÁ TRỊ CÁC BIỂU THỨC:
a) \(A=\frac{25^3.5^5}{6.5^{10}}\)
b) \(B=\frac{2^5.6^3}{8^2.9^2}\)
C) \(C=\frac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}\)
\(A=\frac{25^3.5^5}{6.5^{10}}=\frac{\left(5^2\right)^3.5^5}{6.5^{10}}=\frac{5^6.5^5}{6.5^{10}}=\frac{5^{11}}{6.5^{10}}=\frac{5}{6}\)
\(B=\frac{2^5.6^3}{8^2.9^2}=\frac{2^5.2^3.3^3}{\left(2^3\right)^2.\left(3^2\right)^2}=\frac{2^8.3^3}{2^6.3^4}=\frac{4}{3}\)
\(A=\frac{25^3.5^3}{6.5^{10}}=\frac{5^6.5^3}{6.5^{10}}=\frac{5^9}{6.5.5^9}=\frac{1}{30}\)
\(B=\frac{2^5.6^3}{8^2.9^2}=\frac{2^5.2^3.3^3}{2^6.3^4}=\frac{2^8.3^3}{2^6.3^4}=\frac{2^2}{3}=\frac{4}{3}\)
\(C=\frac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}=\frac{5^3\left(3^3+3^2-1\right)}{6^3\left(3^3+3^2-1\right)}=\frac{5^3}{6^3}\)
rút gọn:
a)\(\frac{4^3.1^5}{9^2.8^2}\) b)\(\frac{25^2.2^2.4^1}{3^3.2^3.224}\) c)\(\frac{25^3.5^6.5^2}{9^4.10^2}\)
\(a.\frac{4^3.1^5}{9^2.8^2}=\frac{2^6.1}{3^4.2^6}=\frac{1}{81}\)
\(b.\frac{25^2.2^2.4^1}{3^3.2^3.224}=\frac{5^4.2^4}{3^3.2^8.7}=\frac{5^4}{3^3.2^4.7}=\frac{625}{3024}\)
\(c.\frac{25^3.5^6.5^2}{9^4.10^2}=\frac{5^{14}}{3^8.2^2.5^2}=\frac{5^{10}}{3^8.2^2}\)
tính:a.\(2^6.5^6\)b.\(8^2.5^2\)c.\(4^3.5^3\)d.\(5^2.6^2.3^2\)e.\(\frac{625^5}{25^8}\)g.\(\frac{3^9}{7}.\frac{7^9}{3}\)
giúp mình nha các bạn !
a , 106 b , 402 c 203 d,902 e , 54 g , 218
#)Giải :
a)\(2^6.5^6=\left(2.5\right)^6=10^6\)
b)\(8^2.5^2=\left(8.5\right)^2=40^2\)
c)\(4^3.5^3=\left(4.5\right)^3=20^3\)
d)\(5^2.6^2.3^2=\left(5.6.2\right)^2=60^2\)
e)\(\frac{625^5}{25^8}=\frac{\left(25^2\right)^5}{25^8}=\frac{25^{10}}{25^8}=25^2\)
g)\(\frac{3^9}{7}.\frac{7^9}{3}=\frac{\left(3.7\right)^9}{7.3}=\frac{21^9}{21}=21^8\)
a) 26 . 56 = (2.5)6 = 106
b) 82.52 = (8.5)2 = 402
c) 43.53 = (4.5)3 = 203
d) 52.62.32 = (5.6.2)2 = 602
e) \(\frac{625^5}{25^8}=\frac{\left(25^2\right)^5}{25^8}=\frac{25^{2.5}}{25^8}=\frac{25^{10}}{25^8}=\frac{25^8.25^2}{25^8}=25^2=625\)
g) \(\frac{3^9}{7}.\frac{7^9}{3}=\frac{3^9.7^9}{7.3}=\frac{\left(7.3\right)^9}{7.3}=\frac{21^9}{21}=21^8\)
Áp dụng tính chất lũy thừa của 1 tích để rút gọn các phân số sau
a)\(\frac{2^2.3^3.5^7}{2^3.3^4.5^6}\)
b)\(\frac{6^5.35^7}{14^7.15^5}\)
c)\(\frac{10^5.21^4.7}{6^4.35^2.4}\)
GIẢI CHI TIẾT ĐẦY ĐỦ DỄ HIỂU NHA
\(\frac{2^2.3^3.5^7}{2^3.3^4.5^6}=\frac{1.1.5}{2.3.1}=\frac{5}{6}\)
Làm tương tự
tính nhanh
6.5 +1.2 +3.5 -5.2 +6.5-4.8
\(6.5+1.2+3.5-5.2+6.5-4.8\)
\(=30+2+15-10+30-32\)
\(=\left(30+2\right)+\left(15-10+30\right)-32\)
\(=32+35-32\)
\(=\left(32-32\right)+35\)
\(=0+35\)
\(=35\)
Tìm x,biết
A) (-3)^2x=9^5
B) 9.5^ x-3=6.5^6+3.5^6
C) 5^x+4-3.5^x+3=5^11.2
D) 3^x+2+4.3^x+1=7.3^6
E) 5^x+3=10^5.6^3:4^4.3^3
Tính giá trị của biểu thức sau :
a . \(A=\frac{25^3.5^5}{6.5^{10}}\) c . \(C=\frac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}\)
b . \(B=\frac{2^5.6^3}{8^2.9^2}\) d . \(D=\frac{\left(7^4-7^3\right)^2}{49^3}\)
a . Ta có : \(A=\frac{25^3.5^5}{6.5^{10}}=\frac{5^{11}}{6.5^{10}}=\frac{5}{6}\)
b . Ta có : \(B=\frac{2^6.6^3}{8^2.9^2}=\frac{2^5.\left(2.3\right)^3}{\left(2^3\right)^2.\left(3^2\right)^2}=\frac{2^8.3^3}{2^6.3^4}=\frac{4}{3}\)
c . Ta có :
\(C=\frac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}=\frac{\left(3.5\right)^3+5.\left(3.5\right)^2-5^3}{\left(6.3\right)^3+6.\left(3.6\right)^2-6^3}=\frac{5^3.\left(3^3-3^2-1\right)}{6^3.\left(3^3+3^2-1\right)}=\frac{5^3}{6^3}\)
d . Ta có :
\(D=\frac{\left(7^4-7^3\right)^2}{49^3}=\frac{7^4-7^3}{49^3}.\left(7^4-7^3\right)=\left(\frac{7^4}{49^3}-\frac{7^3}{49^3}\right).\left(7^4-7^3\right)\)
\(=\left(\frac{7^4}{7^6}-\frac{7^3}{7^6}\right).\left(7^4-7^3\right)=\left(\frac{1}{7^2}-\frac{1}{7^3}\right).\left(7^4-7^3\right)\)
\(=\frac{6}{7^3}.\left(7^4-7^3\right)=\frac{6}{7^3}.7^3.\left(7-1\right)=36\)
a) \(A=\frac{\left(5^2\right)^3.5^5}{6.5^{10}}=\frac{5^6.5^5}{6.5^{10}}=\frac{5^{11}}{6.5^{10}}=\frac{5}{6}\)
b) \(B=\frac{2^5.6^3}{8^2.9^2}=\frac{2^5.\left(2.3\right)^3}{\left(2^3\right)^2.\left(3^2\right)^2}=\frac{2^5.2^3.3^3}{2^6.3^4}=\frac{2^8.3^3}{2^6.3^4}=\frac{2^2}{3}=\frac{4}{3}\)
a) \(A=\frac{25^5.5^5}{6.5^{10}}\)=\(\frac{\left(5^2\right)^3.5^5}{6.5^{10}}=\frac{5^6.5^5}{6.5^{10}}=\frac{5^{11}}{6.5^{10}}=\frac{5}{6}\)
b)\(B=\frac{2^5.6^3}{8^2.9^2}=\frac{2^5.\left(2.3\right)^3}{\left(2^3\right)^2.\left(3^2\right)^2}=\frac{2^5.2^3.3^3}{2^6.3^4}=\frac{2^8.3^3}{2^6.3^4}=\frac{2^2}{3}=\frac{4}{3}\)
c)\(C=\frac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}=\frac{\left(3.5\right)^3+5.\left(3.5\right)^2-5^3}{\left(3.6\right)^3+6.\left(3.6\right)^2-6^3}\)=\(\frac{3^3.5^3+5.3^2.5^2-5^3}{3^3.6^3+6.3^2.6^2-6^3}=\frac{5^3.\left(3^3+3^2-1\right)}{6^3.\left(3^3+3^2-1\right)}=\frac{5^3}{6^3}=\frac{125}{216}\)
d)\(D=\frac{\left(7^4-7^3\right)^2}{49^3}=\frac{2058^2}{\left(7^2\right)^3}=\frac{7^3.6}{7^6}=\frac{6}{7^3}=\frac{6}{343}\)
6.5+3.5=?
Trả lời đc kết bạn với mình nha!