a) \(2^4.x-3^2.x=145-\frac{255}{51}\Rightarrow x.\left(2^4-3^2\right)=145-5\)

\(\Rightarrow7.x=140\Rightarrow x=20\)

b) \(\frac{580}{x-24}=329-150.2\Rightarrow\frac{580}{x-24}=329-300\Rightarrow\frac{580}{x-24}=29\Rightarrow x-24=20\)

\(\Rightarrow x=44\)

c) \(7.\left(x-14\right)+35=25+\frac{279}{9}\Rightarrow7.\left(x-14\right)=25+31-35\)

\(\Rightarrow7.\left(x-14\right)=21\Rightarrow x-14=3\Rightarrow x=17\)

( 32 - x ) + ( -7 + |x| ) - ( |-x| + 25 ) = -45

( 32 - x ) + ( -7 + |x| )                    = -45 + ( |-x| + 25 )

( 32 - x ) + ( -7 + |x| )                    = -45 + 25 + |-x|

( 32 - x ) + ( -7 + |x| )                    = -20 + |-x|

( 32 - x )                                      = -20 + |-x| - ( -7 ) + |x|

( 32 - x )                                      = -20 + 7 + |-x| + |x|

( 32 - x )                                      = -13 + x + x

( 32 - x )                                      = -13 + 2x

32 - x                                          = -13 + 2x

-2x + ( -x )                                   = -13 -32

-3x                                              = -45

3x                                               = 45

x                                                 = 45 : 3 = 15

a) (x+1997) + 2003 = 5432

x+ 1997 = 5432 - 2003

x + 1997 = 3429

x = 3429 - 1997

x= 1432

b) 329 - (129 +x) = 14*7

329 - (129 + x) = 98

129 + x= 329 -98

129 + x = 231

x = 231 - 129

x = 102

a. (x+1997) + 2003= 5432 

=> x = 5432 -( 2003 + 1997)

=> x = 5432 - 4000

=> x = 1432

b. 329 - (129 + x ) = 14*7

=> 129+ x = 329 - 98

=> 129 + x = 231

=> x = 231 - 129

=> x = 102

a.(x+1997)+2003=5432

x + 1997 = 5432 - 2003

x + 1997 = 3429

x = 3429 - 1997

x = 1432

b) 329 - ( 129 + x ) = 14 * 7

329 - ( 129 + x ) = 98

129 + x = 329 - 98

129 + x = 231

x = 231 - 129

x = 102

Bài làm:

Ta có: \(290\div\left(x-12\right)=329-75.4\)

\(\Leftrightarrow290\div\left(x-12\right)=329-300\)

\(\Leftrightarrow290\div\left(x-12\right)=29\)

\(\Leftrightarrow x-12=10\)

\(\Rightarrow x=22\)

\(\frac{290}{x-12}=319-75.4\Leftrightarrow\frac{290}{x-12}=19\)

\(\Leftrightarrow290=19x-228\Leftrightarrow x=\frac{518}{19}\)

khi nhân một số tự nhiên với 1234.bạn An đã viết nhầm các tích riêng thẳng cột như trong phép cộng nên có kết quả sai là 43210.hãy tính tích đúng

giúp với nhé

− 3 29 − 2 29 ≤ x 29 < 5 29 − 7 29 . ⇒ − 5 29 ≤ x 29 < − 2 29 ⇒ − 5 ≤ x < − 2 ⇒ x ∈ − 5 ; − 4 ; − 3

Lời giải:
$(x+2)+(x+4)+(x+6)+...+(x+32)=352$

$(x+x+...+x)+(2+4+6+...+32)=352$

$16x+272=352$

$16x=352-272=80$

$x=80:16=5$