tìm x: \(71+65\cdot4=\frac{x+140}{x}+260\)
giải chi tiết giúp mình mình cảm ơn
\(71+65\cdot4=\frac{x+140}{x}+260\)
Ta có \(71+65\times4=\frac{x+140}{x}+26\)
\(\Rightarrow71+260=\frac{x+140}{x}+260\)
\(\Rightarrow\frac{x+140}{x}=71\)( triệt tiêu hai vế đi 260 )
\(\Rightarrow x+140=71x\)
\(\Rightarrow70x=140\)
\(\Rightarrow x=2\)
Vậy x = 2
\(71+65.4=\frac{x+140}{x}\)\(+260\)
\(71+260=\frac{x+140}{x}+260\)
=>\(\left(x+140\right):x=71\)
=>\(x+140=71x\)
=>\(71x-x=140\)
=>\(70x=140\)
=>\(x=140:70\)
=>\(x=2\)
Vậy x = 2
CHÚC BẠN HỌC TỐT!
Tìm x
71 + 65 x 4 = \(\frac{x+140}{x}+260\)
#)Giải :
\(71+65.4=\frac{x+140}{x}+260\)
\(\frac{x+140}{x}+260=71+65.4\)
\(\frac{x+140}{x}+260=71+260\)
\(\frac{x+140}{x}=71\)
\(\frac{x}{x}+\frac{140}{x}=71\)
\(1+\frac{140}{x}=71\)
\(\frac{140}{x}=71-1\)
\(\frac{140}{x}=70\)
\(x=140:70\)
\(x=2\)
#~Will~be~Pens~#
\(71+65.4=\frac{x+140}{x}+260\)
\(\Rightarrow\frac{x+140}{x}+260=71+65.4\)
\(\frac{x+140}{x}+260=331\)
\(\frac{x+140}{x}=331-260=71\)
\(\frac{x}{x}+\frac{140}{x}=71\)
\(1+\frac{140}{x}=71\)
\(\frac{140}{x}=71-1=70\)
\(x=\frac{140}{70}=2\)
Vậy x=2
\(71+65\text{ x }4=\frac{x+140}{x}+260\)
\(\frac{x+140}{x}+260=71+65\text{ x }4\)
\(\frac{x+140}{x}+260=71+260\)
\(\frac{x+140}{x}=71\)
\(71x=x+140\)
\(71x-x=140\)
\(70x=140\)
\(x=140\text{ : }70\)
\(x=2\)
Tìm x biết \(71+65\times4=\frac{x+140}{x+260}\)
71 + 65 x 4 = \(\frac{x+140}{x}+260\).Tìm x
71 + 65 x 4 = x + 140/x + 260
x + 140/x + 260 = 71+ 65 x4
x + 140/x + 260 = 71 + 260
x + 140/x = 71
x/x + 140/x = 71
140/x = 71 - 1
140/x = 70
x = 140 : 70
x = 2
71 + 65 x 4 = X + 140 / X + 260. tìm X
tìm X
71 + 65 x 4 = X + 140 / X +260
hình như bn viết ngược
bài giải
x + 140/x + 260=331
x nhân 2 + 140 =331-260=71
x nhân 2 =71 : 140 =0,50
x= 0,50 : 2
x=0,25
hok tốt
\(71+65\) x 4 = \(\frac{x+140}{x+260}\)
=> 71 + 260 = \(\frac{x+140}{x+260}\)
=> \(331=\frac{x+140}{x+260}\)
=> \(331.\left(x+260\right)=x+140\)
=> \(331x+86060=x+140\)
=> \(331x-x=-86060+140\)
=>330x =- 85920
=> x = -2864/11
=> \(330x=-85920\)
Tìm x biết 71 + 65 nhân 4=x+140 / x+260
Tìm \(x\)
\(71+65\)x 4= \(\frac{x+140}{x}\)+ 260
\(71+65\cdot4=\frac{x+140}{x}+260\)
\(\Rightarrow71+260=\frac{x}{x}+\frac{140}{x}+260\)
\(\Rightarrow71=1+\frac{140}{x}\)
\(\Rightarrow\frac{140}{x}=70\)
\(\Rightarrow x=2\)
71+65*4=x+140 +260
x
=>71+260= x + 140 +260
x x
=>71=1+ 140
x
=> 71-1 = 140
x
=> 70=140:x
=>x=140:70=2
71 + 65 x 4 = x + 140/x + 260
331 = x/x + 140/x + 260
331 = 1 + 140/x + 260
=> 331 - 1 - 260 = 140/x
70 = 140/x
x = 140 : 70
x = 2
71 + 65 x 4 \(=\frac{x+140}{x}+260\)
Để mình giải lần nữa cho:
71 + 65 x 4 = \(\frac{x+140}{x}+260\)
71 + 260 = \(\frac{x}{x}+\frac{140}{x}+260\)
71 = \(1+\frac{140}{x}\)
\(71-1\) = \(\frac{140}{x}\)
70 = \(\frac{140}{x}\)
x = 140 : 70
x = 2
cho mk 1 cái l-i-k-e đi minh phương cái này mk giải đầu mà