\(71+65.4=\frac{x+140}{x}+260\)
\(71+260=\frac{x}{x}+\frac{140}{x}+260\)
=> \(1+\frac{140}{x}=71\)
=> \(\frac{140}{x}=71-1=70\)
=> \(\frac{140}{x}=\frac{140}{2}\)
=> x = 2
Vậy x = 2
giải chi tiết giúp mình mình cảm ơn
\(71+65\cdot4=\frac{x+140}{x}+260\)
Tìm x
71 + 65 x 4 = \(\frac{x+140}{x}+260\)
Tìm x biết \(71+65\times4=\frac{x+140}{x+260}\)
71 + 65 x 4 = \(\frac{x+140}{x}+260\).Tìm x
tìm X
71 + 65 x 4 = X + 140 / X +260
Tìm \(x\)
\(71+65\)x 4= \(\frac{x+140}{x}\)+ 260
71 + 65 x 4 \(=\frac{x+140}{x}+260\)
tìm x
( x * 0,25 + 1999 ) * 2000 = ( 53 + 1999 ) * 2000
71 + 65 * 4 = \(\frac{x+140}{x}\) + 260
Tìm x:
a) (X x 0,25 + 1999) x 2000 = ( 53 + 1999 ) x 2000
b) 71 + 65 x 4 = \(\dfrac{x+140}{x}\) + 260
