\(\frac{17-x}{1+\frac{1}{2}}=1-\frac{1}{12}.x=>\frac{17-x}{\frac{3}{2}}=1-\frac{1}{12}.x=>\frac{\left(17-x\right).2}{3}=1-\frac{1}{12}.x\)

\(=>\left(17-x\right).2=\left(1-\frac{1}{12}.x\right).3=>34-2x=3-\frac{1}{4}x\)

\(=>34-2x-3+\frac{1}{4}x=0=>-\frac{7}{4}x+31=0=>-\frac{7}{4}x=-31=>x=\left(-31\right):\left(-\frac{7}{4}\right)=\frac{124}{7}\)

Đề bài bn ghi thek thì ai làm nổi cho bn :V ?

<>?/[;b[]rwel;u];53pjkjnlgkljtreylkeuro;uwqr[i5uiwehhwwejokejoiyufljukneghnmknbfvhdbg.elkgiwr;iewqirluoyeiwhtgo

tớ chịu.

hi hi.

a,

(x²-x+1)(x+1)-x³+3x=15

x³-x²+x+x²-x+1-x³+3x=15

x³-x³-x²+x²+x-x+3x+1=15

3x+1=15

3x=15-1

3x=14

x=14/3

b,

(x+3)(x-2)+3x=\(\frac{4}{x+\frac{3}{4}}\)

x²-2x+3x-6+3x=\(\frac{4}{x+\frac{3}{4}}\)

x²-2x+3x+3x-6=\(\frac{4}{x+\frac{3}{4}}\)

Tới đây hết biết , đề có gì sai sai sao ý !

c,

(x²-5)(x+2)+5x=2x²+17

x³+2x²-5x-10+5x=2x²+17

x³+2x²-5x+5x-10=2x²+17

x³+2x²-10=2x²+17

x³-10=17

x³=17+10

x³=27

\(\Rightarrow x=3\)(Vì : 3³=27)

_k_ nhé bn

Nhân ra thôi bạn, có hằng đẳng thức gì đâu !

a) \(\left(x^2-x+1\right)\left(x+1\right)-x^3+3x=15\)

\(\Leftrightarrow\left(x^2-x+1\right)\cdot x+x^2-x+1-x^3+3x=15\)

\(\Leftrightarrow x^3-x^2+x+x^2-x+1-x^3+3x=15\)

\(\Leftrightarrow1+3x=15\Leftrightarrow3x=14\Leftrightarrow x=\frac{14}{3}\)

b) \(\left(x+3\right)\left(x-2\right)+3x=4\cdot\left(x+\frac{3}{4}\right)\)

\(\Leftrightarrow x^2+3x-2x-6+3x=4x+3\)

\(\Leftrightarrow x^2+4x-6=4x+3\)

\(\Leftrightarrow x^2=9\Leftrightarrow\orbr{\begin{cases}x=-3\\x=3\end{cases}}\)

c) \(\left(x^2-5\right)\left(x+2\right)+5x=2x^2+17\)

\(\Leftrightarrow x^3-5x+2x^2-10+5x=2x^2+17\)

\(\Leftrightarrow x^3=27\Leftrightarrow x=3\)