720:[X+2xX+3]=2x3
720 :[X +2 x X +3] =2x3
720 :[x +2 . x +3] =2.3
720:(x+2.x+3)=6
x+2.x+3=120
x.(2+3)=120
x.5=120
x=24
\(720:\left[X+2xX+3\right]=2x3\)
\(720:\left[x+\left(2+3\right)\right]=6\)
\(x+5=720:6\)
\(x+5=120\)
\(x=120-5\)
\(x=115\)
\(720\div\left(x\times5\right)=6\)
\(x\times5=720\div6\)
\(x\times5=120\)
\(x=120\div5\)
\(x=24\)
#TThuHuongg
Tìm X:
a,2xX-5=21
b,3/4+1/4xX=5/6
c,7/8-1/2xX=5/6
d(1/1x2+1/2x3+1/3x4)x100-[5/2:(X+206/100)]:1/2=89
\(a)\) \(2x-5=21\)
\(\Leftrightarrow\) \(2x=21+5\)
\(\Leftrightarrow\) \(2x=26\)
\(\Leftrightarrow\) \(x=26:2\)
\(\Leftrightarrow\) \(=13\)
\(b)\) \(\frac{3}{4}+\frac{1}{4}x=\frac{5}{6}\)
\(\Leftrightarrow\) \(\frac{1}{4}x=\frac{5}{6}-\frac{3}{4}\)
\(\Leftrightarrow\) \(\frac{1}{4}x=\frac{1}{12}\)
\(\Leftrightarrow\) \(x=\frac{1}{3}\)
\(c)\) \(\frac{7}{8}-\frac{1}{2}x=\frac{5}{6}\)
\(\Leftrightarrow\) \(\frac{1}{2}x=\frac{7}{8}-\frac{5}{6}\)
\(\Leftrightarrow\) \(\frac{1}{2}x=\frac{1}{24}\)
\(\Leftrightarrow\) \(x=\frac{1}{12}\)
Tìm X biết 720:(X x 2 + X x 3) = 2x3
\(720:\left(x\times2+x\times3\right)=2\times3\)
\(720:\left(x\times5\right)=6\)
\(x\times5=720:6\)
\(x\times5=120\)
\(x=120:5\)
\(x=24\)
tìm X :
720 : ( X x 2+ X x 3)= 2x3
720 : ( X x5 )= 6
X x 5 = 720 : 6
X x 5 =120
X = 120 : 5
X = 24
chúc bạn học tốt
720:(x.2+x.3)=2.3
=> 720:[x.(2+3)]=6
=> x.5 =720:6
=> x.5 =120
=> x =120:5
=> x =24
Vậy x=24
720 : ( X x 2+ X x 3)= 2x3
720 : ( X x 2+ X x 3)= 6
720 : [X x (2+3)] = 6
720 : (X x 5) = 6
720 : 5 x X = 6
X = 720 : 5 : 6
X = 24
2)Tìm x
a)720:(41-(2xX-5))=120
b)4,8x5-x+100=250
c)3/5+2/5:x=1và1/4
720:[41-(2×x-5)]=120
[41-(2×x-5)]=720:120
[41-(2×x-5)]=6
(2×x-5)=41-6
(2×x-5)=35
2×x=35+5
2x=40
x=40:2
vậy x=20
a) \(720:\left[41-\left(2x-5\right)\right]=120\)
\(\Rightarrow\left[41-\left(2.x-5\right)\right]=6\)
\(\Rightarrow2x-5=35\Rightarrow2x=40\Rightarrow x=20\)
b) \(4,8.5-x+100=250\)
\(\Rightarrow4,8.5-x=150\Rightarrow24-x=150\Rightarrow x=-126\)
c)+) \(\frac{3}{5}+\frac{2}{5}:x=1\Rightarrow\frac{2}{5}:x=\frac{2}{5}\Rightarrow x=1\)
+) \(\frac{3}{5}+\frac{2}{5}:x=\frac{1}{4}\Rightarrow\frac{2}{5}:x=\frac{-7}{20}\Rightarrow x=\frac{-8}{7}\)
Cậu có thể tham khảo bài làm trên đây ạ, chúc cậu hok tốt ^^
2. Tìm x:
a) 720: [41-(2.x-5)] = 120 b) 4,8.5-x+100 = 250 c) 3/5 +2/5:x =1 và 1/4
[41-(2.x-5)] = 720:120 24-x+100 =250 3/5 + 2/5 :x = 5/4
[41-(2.x-5)] = 6 24-x = 250 -100 2/5:x = 5/4 - 3/5
(2.x-5) = 41-6 24-x = 150 2/5:x = 25/20 - 12/20
(2.x-5) = 35 x = 150 - 24 2/5:x = 13/20
2.x = 35+5 x = 126 x = 2/5:13/20
2.x = 40 x = 8/20 : 13/20
x = 40: 2 = 20 x = 8/13
720:[41-(2xX-5)]=8x5
720:[41-(2xX-5)]=40
41-(2xX-5)=720:40
41-(2xX-5)=18
2xX-5=41-18
2xX-5=23
2xX=23+5
2xX=28
X=28:2
X=14
Vây X=14.
Nếu đúng bạn **** cho mình nhé.
720:[41-(2xX-5)]=8x5 = 40.
cho [41-(2xX-5)] = x .
theo đề ta có : 720 : 40 = x
x = 18 => [41-(2xX-5)] = 18 .
( 2xX-5 ) = 41 - 18
( 2xX-5 ) = 23
2xX = 23 + 5
2xX = 28
suy ra : X = 28 : 2
X = 14
720:[118-(2xX+10)]=60
720:[118-(2.x + 10)]=60
118 - (2.x+10) = 720 : 60
118 - (2.x + 10 ) = 12
2.x +10 = 118 - 12
2.x + 10 = 106
2.x = 106 - 10
2.x = 96
x = 96 : 2
x = 48
Vậy x = 48
Cho hàm số f x = 2 x 3 - 2 x x ≥ 1 x 3 - 3 x x < 1
- Tìm: lim x → 1 - f x ; lim x → 1 + f x
- Hàm số có giới hạn tại x = 1 không? Vì sao?
- Ta có:
- Vì
nên hàm số đã cho không có giới hạn tại x = 1
720:(yx2+yx3)=2x3
ai nhanh nhất tick 3 cái
720:(yx2+yx3)=2x3
720:(yx2+yx3)=6
(yx2+yx3)=720:6
yx2+yx3=120
yx(2+3)=120
yx5=120
y=120:5
y=24
nhé bạn
MK đầu tiên
\(720\div\left(y\times5\right)=6\)
\(\Rightarrow y\times5=120\)
\(\Rightarrow y=24\)