14%.6^12+99999999999=603^5
1+2+3+4+5+6+7+8+9+99999999999=???
1+2+3+4+5+6+7+8+9+99999999999=100000000044
ta có: 1+...+9
= \(\left(\frac{9-1}{1}+1\right)\left(\frac{9+1}{2}\right)\)
=9 x 5 =45
=> 1+2+3+4+5+6+7+8+9+99999999999=45+99999999999=100000000044
Bài: Tính
a) \(1-2-3+4+5-6-7+...+601-602-603+604\)
b) \(\frac{\left(140\frac{7}{3}-138\frac{5}{12}\right):18\frac{1}{6}}{0,002}\)
1 - 2 - 3 + 4 + 5- 6 - 7 + .... + 601 - 602 - 603 + 604
= (1 - 2 - 3 + 4) + (5 - 6 - 7 + 8) + ... + (601 -602 - 603 + 604)
= 0 + 0 + ... + 0
= 0
Bài: Tính
a) \(1-2-3+4+5-6-7+...+601-602-603+604\)
b) \(\frac{\left(140\frac{7}{3}-138\frac{5}{12}\right):18\frac{1}{6}}{0,002}\)
a) 1−2−3+4+5−6−7+...+601−602−603+604
<=>(1-2-3+4)+(5-6-7+8)+....+(601-602-603+604)=0+0+...+0
=0
1-2-3+4+5-6-7+...+601-603+604
1 - 2 - 3 + 4 + 5 - 6 - 7 + ...+ 601 - 603 + 604
= (1 - 2 - 3 + 4) + (5- 6 - 7 + 8) + ... + (601 - 602 - 603 + 604)
= 0 + 0 + ... + 0
= 0
P/s : Đề bạn viết thiếu 602 nhé
1-2-3+4+5-6-7+...+601-602-603+604 = ?
1-2 - 3 + 4 + 5 -6 - 7 +8 +...+601 - 602 -60 3 +604
= -4 + 4 +- 8 + 8 +..........+-604+604
=0
(l ikr cho mình nhe)
Tinh: 1-2-3+4+5-6-7+...+601-602-603+604.
\(=( 1 - 2 - 3 + 4 ) + ( 5 - 6 - 7 + 8 ) + ....+ ( 601 - 602 - 603 + 604 ) = 0 + 0 + .. + 0 = 0 \)
=4+1-2-3+8+5-6-7+...+604+601-602-603
=5-(2+3)+13-(6+7)+...+1205-(602+603)
=0+0+...+0
=0
1-2-3+4+5-6-7+...+601-602-603+604
=-4+4+ -8+8 +....+ -604+604
=0+0 +...+0
=0
Tính : 1-2-3+4+5-6-7+...+601-602-603+604
B=5+52+53+54+...+560
=(5+52)+(53+54)+...+(559+560)
=5(1+5)+53(1+5)+...+559(1+5)
=(5+53+...+559)(5+1)
=(5+53+...+559)6 chia hết cho 6
=>đpcm
1+99999999999-99999999999
ai nhanh se duoc 1 mk
o nha bn
tk cho mk nha, mk đg bị âm điểm
Trong các phân số sau, những phân số nào biểu diễn số hữu tỉ \dfrac{5}{-6} ?
\dfrac{-10}{14}\dfrac{-20}{24}\dfrac{-5}{6}\dfrac{-10}{12}\dfrac{-6}{6}