8/3.2/5.3/8.10.19/92=8.2.3.10.19/3.5.8.92=2.19/46=19/23

\(=\frac{16}{15}.\frac{15}{4}.\frac{19}{92}=4.\frac{19}{92}=\frac{76}{92}=\frac{19}{23}\)

NHỚ K GIÚP MK HA

8/3.3/8.2/5.10.19/92

=1.4.19/92=19/23

a, 11 1/4-(2 5/7+5 1/4)

= 45/4-(19/7+21/4)

= 45/4-223/28

=23/7

b, (8 5/11+3 5/8)-3 5/11

=(93/11+29/8)-38/11

=1063/88-38/11

=69/8

a,  =\(11\frac{1}{4}-2\frac{5}{7}-5\frac{1}{4}\)

\(=\left(11\frac{1}{4}-5\frac{1}{4}\right)-2\frac{5}{7}\)

\(=6-2\frac{5}{7}\)

\(=\frac{23}{7}\)

b,  \(=8\frac{5}{11}+3\frac{5}{8}-3\frac{5}{11}\)

\(=\left(8\frac{5}{11}-3\frac{5}{11}\right)+3\frac{5}{8}\)

\(=5+3\frac{5}{8}\)

\(=\frac{69}{8}\)

Bạn Pham Ngoc Anh ơi ! Sorry bạn nhé ! mik chỉ có thể k 1 lần thay vì không k được mik sẽ kết bạn nhé !

a.

\(-\frac{2}{3}-\frac{1}{3}\times\left(2x-5\right)=\frac{3}{2}\)

\(-\frac{2}{3}-\frac{2}{3}x+\frac{5}{3}=\frac{3}{2}\)

\(\left(-\frac{2}{3}+\frac{5}{3}\right)-\frac{2}{3}x=\frac{3}{2}\)

\(\frac{3}{3}-\frac{2}{3}x=\frac{3}{2}\)

\(1-\frac{2}{3}x=\frac{3}{2}\)

\(\frac{2}{3}x=1-\frac{3}{2}\)

\(\frac{2}{3}x=\frac{2}{2}-\frac{3}{2}\)

\(\frac{2}{3}x=-\frac{1}{2}\)

\(x=-\frac{1}{2}\div\frac{2}{3}\)

\(x=-\frac{1}{2}\times\frac{3}{2}\)

\(x=-\frac{3}{4}\)

b.

\(\frac{1}{3}x+\frac{2}{5}\times\left(x-1\right)=0\)

\(\frac{1}{3}x+\frac{2}{5}x-\frac{2}{5}=0\)

\(x\times\left(\frac{1}{3}+\frac{2}{5}\right)=\frac{2}{5}\)

\(x\times\left(\frac{5}{15}+\frac{6}{15}\right)=\frac{2}{5}\)

\(x\times\frac{11}{15}=\frac{2}{5}\)

\(x=\frac{2}{5}\div\frac{11}{15}\)

\(x=\frac{2}{5}\times\frac{15}{11}\)

\(x=\frac{6}{11}\)

Chúc bạn học tốt

a ) \(-\frac{2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)

                  \(\frac{1}{3}\left(2x-5\right)=-\frac{2}{3}-\frac{3}{2}\)

                   \(\frac{1}{3}\left(2x-5\right)=\frac{-13}{6}\)

                        \(\left(2x-5\right)=-\frac{13}{6}:\frac{1}{3}\)

                         \(\left(2x-5\right)=-\frac{13}{6}.\frac{3}{1}\)

                         \(\left(2x-5\right)=-\frac{13}{2}\)

                           \(2x=-\frac{13}{2}+5\)

                            \(2x=-\frac{3}{2}\)

                              \(\Rightarrow x=-\frac{3}{2}:2\)

                              \(\Rightarrow x=-\frac{3}{2}.\frac{1}{2}\)

                              \(\Rightarrow x=-\frac{3}{4}\)

1)

a)    \(-\frac{2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)

  \(\Rightarrow-\frac{2}{3}-\frac{2}{3}x-\frac{5}{3}=\frac{3}{2}\)

  \(\Rightarrow1-\frac{2}{3}x=\frac{3}{2}\)

  \(\Rightarrow\frac{2}{3}x=1-\frac{3}{2}\)

  \(\Rightarrow\frac{2}{3}x=-\frac{1}{2}\)

  \(\Rightarrow x=-\frac{1}{2}:\frac{2}{3}\)

  \(\Rightarrow x=-\frac{3}{4}\)

                                   Vậy \(x=-\frac{3}{4}\)

b) 

\(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)

\(\Rightarrow\frac{1}{3}x+\frac{2}{5}x-\frac{2}{5}=0\)

\(\Rightarrow x.\left(\frac{1}{3}+\frac{2}{5}\right)=\frac{2}{5}\)

\(\Rightarrow x.\left(\frac{5}{15}+\frac{6}{15}\right)=\frac{2}{5}\)

\(\Rightarrow x.\frac{11}{15}=\frac{2}{5}\)

\(\Rightarrow x=\frac{2}{5}:\frac{11}{15}\)

a) \(\frac{14}{21}+1-\left|\frac{1}{3}-1\right|\)

\(=\frac{2}{3}+1-\frac{2}{3}\)

\(=1+\left(\frac{2}{3}-\frac{1}{3}\right)\)

\(=1\)

b) \(\frac{1}{3}-\left|\frac{-1}{4}+\frac{5}{6}\right|-\left|\frac{-7}{12}\right|\)

\(=\frac{1}{3}-\frac{7}{12}-\frac{7}{12}\)

\(=-\frac{5}{6}\)

Các câu khác làm tương tự thôi :))

\(\frac{1}{3}-|\frac{-1}{4}+\frac{5}{6}|-|\frac{-7}{12}|\)

\(=\frac{2}{3}+1-\frac{2}{3}\)

\(=1+(\frac{2}{3}-\frac{2}{3})\)

\(=1\)

a) \(\left(\frac{1}{3}-\frac{1}{5}\right)^2:\left(\frac{1}{5}\right)^2=\left[\left(\frac{1}{3}-\frac{1}{5}\right):\frac{1}{5}\right]^2=\left(\frac{2}{15}:\frac{1}{5}\right)^2=\left(\frac{2}{3}\right)^2=\frac{4}{9}\)

c)\(7\frac{1}{23}+\frac{10}{27}-5\frac{1}{23}+\frac{17}{27}+2^3=\left(7\frac{1}{23}-5\frac{1}{23}\right)+\left(\frac{10}{27}+\frac{17}{27}\right)+2^3=2+1+8=11\)

d)\(5.\left(-\frac{5}{2}\right)^2+\frac{1}{5}.\left(-3\right)^2=5.\frac{25}{4}+\frac{1}{5}.9=\frac{125}{4}+\frac{9}{5}=\frac{661}{20}\)

a)  \(\left(\frac{1}{3}-\frac{1}{5}\right)^2:\left(\frac{1}{5}\right)^2=\left[\left(\frac{1}{3}-\frac{1}{5}\right):\frac{1}{5}\right]^2=\left[\left(\frac{5}{15}-\frac{3}{15}\right):\frac{1}{5}\right]^2=\left[\frac{2}{15}.5\right]^2=\left[\frac{2}{3}\right]^2=\frac{4}{9}\)

b) \(\frac{2^3.5^2.8}{10^{10}}=\frac{2^3.5^2.2^3}{\left(2.5\right)^{10}}=\frac{\left(2^3.2^3\right).5^2}{2^{10}.5^{10}}=\frac{2^6.5^2}{2^{10}.5^{10}}=\frac{1}{2^4.5^8}=\frac{1}{6250000}\)

c) \(7\frac{1}{23}+\frac{10}{27}-5\frac{1}{23}+\frac{17}{27}+2^3\)

\(=\left(7\frac{1}{23}-5\frac{1}{23}\right)+\left(\frac{10}{27}+\frac{17}{27}\right)+2^3\)

\(=2+1+8\)

\(=11\)

d) \(5.\left(-\frac{5}{2}\right)^2+\frac{1}{5}.\left(-3\right)^2\)

\(=5.\frac{25}{4}+\frac{1}{5}.9\)

\(=\frac{125}{4}+\frac{9}{5}\)

\(=\frac{625}{20}+\frac{36}{20}=\frac{661}{20}\)

Chuk bạn hok tốt ! 

A) \(\frac{1}{2}\cdot\left(\frac{2}{9}+\frac{3}{7}-\frac{5}{27}\right)\) 

\(=\frac{1}{2}\cdot\frac{1}{2}\)

\(=\frac{1}{4}\)

B)   \(\left(\frac{-5}{28}+1.75+\frac{8}{35}\right):\left(-3\frac{9}{20}\right)\)

\(=\left(\frac{-5}{28}+\frac{7}{4}+\frac{8}{35}\right):\frac{-69}{20}\)

\(=\frac{14}{5}:\frac{-69}{20}\)

\(=\frac{-56}{69}\)