So sánh:
S=1/4+2/4^2+3/4^3+..+2014/4^2014 với 1/2
Cho \(M=\frac{1}{4}+\frac{2}{4^2}+\frac{3}{4^3}+...+\frac{2014}{4^{2014}}\). So sánh M với 4/9
\(4.M=4.\left(\frac{1}{4}+\frac{2}{4^2}+\frac{3}{4^3}+...+\frac{2014}{4^{2014}}\right)=1+\frac{2}{4}+\frac{3}{4^2}+...+\frac{2014}{4^{2013}}\)
=> 4M - M = \(1+\left(\frac{2}{4}-\frac{1}{4}\right)+\left(\frac{3}{4^2}-\frac{2}{4^2}\right)+...+\left(\frac{2014}{4^{2013}}-\frac{2013}{4^{2013}}\right)-\frac{2014}{4^{2014}}\)
=> 3.M = \(1+\frac{1}{4}+\frac{1}{4^2}+...+\frac{1}{4^{2013}}-\frac{2014}{4^{2014}}\)
Tính \(N=1+\frac{1}{4}+\frac{1}{4^2}+...+\frac{1}{4^{2013}}\)
=> \(4.N=4+1+\frac{1}{4}+\frac{1}{4^2}+...+\frac{1}{4^{2012}}\)
=> 4N - N = 4 - \(\frac{1}{4^{2013}}\)=> N = \(\frac{4}{3}-\frac{1}{3.4^{2013}}\)=> N < 4/3
Ta có: 3M < N => M < N/3 => M < (4/3)/3 = 2/9
vậy M < 4/9
so sánh:S=2/1*2*3+2/2*3*4+2/3*4*5+...+2/2009+2010+2011 và P=1/2
Câu hỏi của Nguyễn Thị Hạnh Linh - Chuyên mục hỏi đáp - Giúp tôi giải toán. - Học toán với OnlineMath
rut gon bieu thuc
1/(1^4+1^2+1)+2/(2^4+2^2+1)+3/(3^4+3^2+1)+...+2014/(2014^4+2014^2+2014)=...
{giup minh vs}
cho A=1*2*3+1/2*3*4+1/3*4*5+...+1/2014*2015*2016.so sánh A với 1/4
A=\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{2014.2015.2016}\)
A=\(\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{2014.2015}-\frac{1}{2015.2016}\right)\)
A=\(\frac{1}{2}\left(\frac{1}{2}-\frac{1}{2015.2016}\right)\)
A=\(\frac{1}{4}-\frac{1}{2015.2016.2}\)\(\Rightarrow A<\frac{1}{4}\)
Cho M=\(\frac{\sqrt{2}-\sqrt{1}}{1+1}+\frac{\sqrt{3}-\sqrt{2}}{2+3}+\frac{\sqrt{4}-\sqrt{3}}{3+4}+...+\frac{\sqrt{2015}-\sqrt{2014}}{2014+2015}\)
Hãy so sánh M với 1/2
Tính giá trị biểu thức 1×2×3×4×.........×2015 - 1×2×3×4×.......×2014 - 1×2×3×4×........×2014^(2) Giúp mik với ạ Thank you very much
Rút gọn biểu thức : \(\frac{1}{1^4+1^2+1}+\frac{2}{2^4+2^2+2}+\frac{3}{3^4+3^2+3}+...+\frac{2014}{2014^4+2014^2+2014}\)
Cho tong gom 2014 so hang:
S=1/4+2/4²+3/4³+......+2014/4²ⁿ¹⁴
Chung minh:S<1/2
so sánh A= 1/1 x 2 x 3 + 1/2 x 3 x 4 + 1/3 x 4 x 5 + ...+ 1/ 2014 x 2015 x 2016 với 1/4
2A=2/1.2.3 + 2/2.3.4 + 2/3.4.5 + ...+2/2014.2015.2016
Ta có: 2/1.2.3=1/1.2-1/2.3; 2/2.3.4=1/2.3-1/3.4; 2/3.4.5=1/3.4-1/4.5; ....; 2/2014.2015.2016=1/2014.2015-1/2015.2016
=> 2A=1/1.2-1/2015.2016
=> 2A < 1/2 => A < 1/4