so sanh voi trung gian la 200^20=2000^15

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199²⁰< 200²⁰ = (2³.5²)²⁰ = 2⁶⁰.5⁴⁰

2003¹⁵ > 2000¹⁵ =(2⁴.5³)¹⁵  = 2⁶⁰.5⁴⁵ > 2⁶⁰.5⁴⁰

Vậy 2003¹⁵ > 199²⁰

ta có:

\(199^{20}=\left(199^4\right)^5=1568239201^5\)

\(2003^{15}=\left(2003^3\right)^5=8036054027^5\)

vì \(1568239201>1\)

    \(8036054027>1\)

\(1568239201< 8036054027\)

=>\(199^{20}< 2003^{15}\)

199²⁰=(199⁴)⁵=1568239201⁵

2003¹⁵=(2003³)⁵=8036054027⁵

Vì 1568239201<8036054027

Vậy 199²⁰ <2003¹⁵

\(199^{20}< 2003^{15}\)

199^20<2003^15

199²⁰=(199⁴)⁵

2003¹⁵=(2003³)⁵

Vì 199⁴<2003³=>199²⁰<2003¹⁵

Lũy thừa để so sánh là :

199²⁰ = ( 199⁴⁵ )

2003¹⁵ = ( 2003³⁵ )

Do : 199⁴ < 2003³ => 199²⁰ < 2003¹⁵ .

Ta có: 199^20<200^20 và 2000^15<2003^15

200^20=200^(4.5)=(200^4)^5

2000^15=2000^(3.5)=(2000^3)^5

So sánh: 200^4 và 2000^3

200^4=200^3.200

2000^3=(200.10)^3=200^3.10^3=200^3.1000

Vì 200<1000 =>200^4<2000^3 =>200^20<2000^15 =>199^20<2003^15.

Câu hỏi này khó wá ko thể trả lời đc .

{'-'}...{'^'}

199\(^{20}\)<200\(^{20}\) =(2\(^3\).5\(^2\))\(^{20}\)=2\(^{60}\).5\(^{40}\)

2003\(^{15}\)>2000\(^{15}\)=(2.10\(^3\))\(^{15}\)=(2\(^4\).5\(^3\))\(^{15}\)=2\(^{60}\).5\(^{45}\)

\(\Rightarrow\)2\(^{60}\).5\(^{40}\)<2\(^{60}\).5\(^{45}\)\(\Rightarrow\)199\(^{20}\)<2003\(^{15}\)

\(199^{20}\)\(< \)\(200^{20}\)\(=\)\(\left(2^3.5^2\right)^{20}\)\(=\)\(2^{60}\)\(.\)\(5^{40}\)

\(2003^{15}\)\(>\)\(2000^{15}\)\(=\)\(\left(2^4.5^3\right)^{15}\)\(=\)\(2^{60}\)\(.\)\(5^{45}\)

\(\Rightarrow\)\(2^{60}\)\(.\)\(5^{40}\)\(< \)\(2^{60}\)\(.\)\(5^{45}\)

\(\Rightarrow\)...........................................

199^20 = (199^4) ^5

2003^15 = (2003^3)^5

Vì 199^4 < 2003^3 => 199^20 < 2003^15

Có: \(199^{20}=199^{4.5}=\left(199^4\right)^5=1568239201^5\)

       \(2003^{15}=2003^{3.5}=\left(2003^3\right)^5=8036054027^5\)

Có : 8036054027 > 1568239201 

=> \(199^{20}< 2003^{15}\)

Ủng hộ mik nhá ^_^"

NHẦM 

2003³=8036054027⁵

Ta có : 199²⁰ < 200²⁰ = (8.25)²⁰ = (2³.5²)²⁰ = 2⁶⁰.5⁴⁰

           2003¹⁵ > 2000¹⁵ = (16.125)¹⁵ = (2⁴.5³)¹⁵ = 2⁶⁰.5⁴⁵

Vì 5⁴⁰ < 5⁴⁵ nên 199²⁰ < 2003¹⁵

Ta thấy: 2003¹⁵>1990¹⁵=(199.10)¹⁵=[(199.10)³]⁵=(199³.10³)⁵

=(199³.1000)⁵>(199³.199)⁵=(199⁴)⁵=199²⁰

=>2003¹⁵>199²⁰