Tìm x :
a . X x 9.99 + X : 100 = 9.8
b. X : 2/3 + X: 2/5 + X =1
Tính
a) (x-1/2)+(x-1/4)+(x-1/8)+...+(x-1/512)
Tìm x
a) (x-1/1×2)+(x-1/2×3)+...+(x-1/100×101)
b) (x-1)+(x-2)+(x-3)+...+(x-101)=5050
c) x+1/2+1/3+1/4+...+1/100=3/2+4/3+5/4++...+101/100
Tìm x
a) 5^x -1 = 5^2 + 100
b) x^10=x
2 x 5^2 x 3^2 + {[2 x 5^3 - (5x + 4) x 5 : (2^3 x 3 x 5)]}=455
a) 5^x-1 = 5^2 + 100
=> 5x-1 = 125 = 53
=> x - 1 = 3
=> x = 4.
b) x10 = x
=> x = {-1;0;1}
2.52.32 + {[2.53 - (5x + 4).5 : (23.3.5)]} = 455
=> 450 + {250 - (5x + 4).5 : 120} = 455
=> 250 - (5x + 4).5 : 120 = 5
=> (5x + 4).5 : 120 = 245
=> (5x + 4).5 = 245.120 = 29400
=> 5x + 4 = 29400 : 5 = 5880
=> 5x = 5876
=> x = 1175,2
1. Tìm x
a)/ x-3/2 /+ / x+1 /+/ x-2 /= 4x
b)/ 2x-1 /+/ x+3 /=5
c)/ 3x-1 /+/ 3x+1 /=/ x-2 /
2. Tìm M
M=1+ 3/2^3+ 4/2^4+...+100/2^100
1.a) có: \(|x-\frac{3}{2}|,|x+1|,\left|x-2\right|\ge0\Rightarrow4x\ge0\Rightarrow x\ge0\)
\(x\ge0\Rightarrow x-\frac{3}{2}\ge\frac{-3}{2}\Rightarrow\left|x-\frac{3}{2}\right|\ge\left|\frac{-3}{2}\right|=\frac{3}{2}\Rightarrow\left|x-\frac{3}{2}\right|=x-\frac{3}{2}\)
cmtt: \(|x-2|=x-2\)
\(\Rightarrow3x-\frac{3}{2}+1-2=4x\)
\(\Rightarrow3x-\frac{5}{2}=4x\)
\(\Rightarrow x=\frac{-5}{2}\left(ko,t/m\right)\)
Tìm x:
a) 720:[41-(2.x-5)]=23.5
b) (x+1)+(x+2)+(x+3)+...(x+100)=5750
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)
\(\Rightarrow100x+5050=5750\Rightarrow x=5750-5050\)
\(100x=700\Rightarrow x=700:100=7\)
\(a,\text{ }720\text{ : }\left[41-\left(2x-5\right)\right]=2^3\cdot5\)
\(720\text{ : }\left[42-2x+5\right]=8\cdot5\)
\(720\text{ : }\left[42+5-2x\right]=40\)
\(720\text{ : }\left[47-2x\right]=40\)
\(47-2x=720\text{ : }40\)
\(47-2x=18\)
\(2x=47-18\)
\(2x=29\)
\(x=\frac{29}{2}\)
\(b,\text{ }\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)
\(100x+\left[\left(100-1\right)\text{ : }1+1\right]\text{ x }\left(100+1\right)\text{ }:\text{ }2=5750\)
\(100x+100\text{ x }101\text{ : }2=5750\)
\(100x+10100\text{ : }2=5750\)
\(100x+5050=5750\)
\(100x=5750-5050\)
\(100x=700\)
\(x=700\text{ : }100\)
\(x=7\)
Bài 1: Tính:
a) 10 000 x 9 + 1 000 x 8 + 100 x 7 + 10 x 6 + 5
b) 100 000 x 3 + 100 x 6 + 10 x 5 + 7
c) 100 000 x 6 + 10 000
Bài 2: Tìm X:
a) X + 77=600x30
b) 8950 : X=10:2
c) 5 x X=8765
Bài 1 :
a) = 98765
b) = 300657
c) 610000
Bài 2:
a) X + 77 = 1800
X = 1800 - 77
X = 1723
b) 8950 : x = 5
x = 8950 : 5
x = 1790
c) x = 8765 : 5
x = 1753
a,98765 b,300657 c,610000 Bài 2 : a, 17923 b, 1790 c, 1753
Bài 1 : tính
A.98765
B.3000657
C.6100000
Bài 2 : tim X
A. 17923
B.1790
C.1753
tìm x: a,11/12.x+3/4.x=-1/6
b,(x-5).30/100=20.x/100+5
c,1/3.x-1/2.x=75/100
d,3-(1/6-x).2/3=-1/6
Ta có S=1/2^2+1/3^2+1/4^2+...+1/9^2
<1/2²+1/2*3+1/3*4+....+1/8*9
=1/2²+1/2-1/3+1/3-1/4+....+1/8-1/9
=1/4+1/2-1/9=23/36<32/36=8/9 (♪)
Ta lại có S=1/2^2+1/3^2+1/4^2+...+1/9^2
>1/2²+1/3*4+1/4*5+....+1/9*10
=1/2²+1/3-1/4+1/4-1/5+........+1/9-1/10
=1/2²+1/3-1/10
=19/20>8/20=2/5 ( ♫)
Từ (♪)( ♫) cho ta đpcm
Tìm x thuộc Z
a.(x+5)(x-2)<0
b.(x+1)+(x+2)+(x+3)+....+(x+100)=5750
a, x\(\in\left\{-5;2\right\}\)
b,X=7
Bài 1:Tìm x
a) ( x - 2 ) . (5 - x) = 0
b) (x - 1) . (x mũ 2 + 1) = 0
c) -12 . (x - 5) + 7 . (3 - x) = 5
d) 30 . (x + 2) - 6 . (x - 5) = 24 . x = 100
Bài 2: Tìm giá trị nhỏ nhất của biểu thức
a) 3 . (x + 1)mũ 2 - 2
b) /x - 2/ - 10
Làm ơn giúp mk vs nè!!~~
1/ a) TH1: x-2 = 0 => x= 0+2 = 2
TH2: 5-x= 0 => x= 5-0 = 5
b)???
duyệt đi
tìm x thuộc Z
a,2|x| +5=23
b,(x+5)(x+2)<0
c,(x+1)+(x+2)+(x+3)+..........+(x+100)=5750
lớp 7 chắc làm tắt thế này cũng hiểu
a)2|x| +5=23
<=>2|x|=18
=>|x|=±9
b)ta xét th (x+5)(x+2)=0
=>Th1:x+5=0 Th2:x+2=0
=>x=-5 =>x=-2
vì (x+5)(x+2)<0
=>\(x\in\left\{-\infty;-2;-5\right\}\)
c)(x+1)+(x+2)+(x+3)+..........+(x+100)=5750
<=>(x+x+..x)+(1+2+3+...+100)=5750
=>5050+100x=5750
=>100x=5750-5050
=>100x=700
=>x=7
b) vì x+2 < x+5 mà (x+2)(x+5) < 0
=> x +2 <0 => x< -2 và x+5 > 0 => x> -5 Vậy -5<x<-2
x + 5 > 0 => x> -5