A=6/1*3+6/3*5+6/5*7+.....+6/99*101
A = 1-2+3-4+5-6+.....+97-98+99-100+101
B = 1+2-3-4+5+6-7-8+......+98-99-100+101
B=1+2-(3+4)+5+6-..-100+101
B=(3+11+19+...+195)-(7+15+...+199)+101
B=25.99-25.103+101
B=-100+101=1
Vậy B=1
a=151
B=1 nha
a) A= 1+(-2)+(-3)+4+5(-6)+(-7)+8+9+...+99+100-101+102+103
b) B=1+(-3)+5+(-7)+...+57+(-99)+101
bài 1
A=1*2*3+2*3*4+3*4*5+...+99*100*101
B=1*3*5+3*5*7+...+95*97*99
C=2*4+4*6+..+98*100
D=1*2+3*4+5*6+...+99*100
E=1^2+2^2+3^2+...+100^2
G=1*3+2*4+3*5+4*6+...+99*101+100*102
H=1*2^2+2*3^2+3*4^2+...+99*100^2
I=1*2*3+3*4*5+5*6*7+7*8*9+...+98*99*100
K=1^2+3^2+5^2+...+99^2
A = 1*2*3 + 2*3*4 + 3*4*5 ... + 99*100*101
=> 4A = 1*2*3*4 + 2*3*4*4 + 3*4*5*4 + ... +99*100*101*4
=> 4A = 1*2*3*4 + 2*3*4*(5 - 1) + 3*4*5*( 6 - 2) + ... + 99*100*101*(102 - 98)
=> 4A = 1*2*3*4 + 2*3*4*5 - 1*2*3*4 + 3*4*5*6 - 2*3*4*5 + ... + 99*100*101*102 - 98*99*100*101
=> 4A = 99*100*101*102
=> 4A = 101989800
=> A = 25497450
tính
A=1*3+3*5+5*7+............+97*99+99*101
B=2*4+4*6+6*8+...............+98*100+100*102
Tính:
a, A= 1+(-2)+(-3)+4+5+(-6)+(-7)+8+...+99-100-101+102+103
b,B=1+(-3)+5+(-7)+...+97+(-99)+101
a, 3-4+5-6+7-8+...+99-100
b, 2-5+8-11+14-17+...+98-101
c, 1+2+(-3)-4+5+6-...-99
bn chỉ cần nhóm chúng lại từng nhóm là được
M=1÷2×3÷4×5÷6×...×99÷100 & N=2÷3×4÷5×6÷7×...×100÷101
M*N=1/2*3/4*5/6*..*99/100*2/3*4/5*6/7*..... = 1/101 (1)
Mặt khác :
1/2 <2/3
3/4<4/5
........
99/100 < 100/101
=>1/2*3/4*5/6*....*99/100 < 2/3*4/5*6/7*....*100/101
hay M< N =>M*M<M*N hay M^2 < 1/101 <1/100
=>M^2 < 1/100 hay M^2 < (1/10)^2 =>M<1/10 (vì M>0 ) (đpcm)
yêu cầu là j?k có yêu cầu sao mà giải dc hả bạn??
Bài 1:
a, A=1+(-2)+(-3)+4+5+(-6)+(-7)+8+...+99-100-101+102+103
b, B=1+(-3)+5+(-7)+...+97+(-99)+101
Bài 2:
a,|x+2|-x=2
b,|x-3|+x-3=0
c, |x+1|+|x+2|=1
d,|x-5|+x-8=6
1
b;
B=1+ (7-5) + (11-9) + ...+(101-99)
B=1+2+2+..+2
B=1+25.2=51
2.
a.
ĐK : x+2 >=0 => x>=-2
\(\left|x+2\right|-x=2\\ \Rightarrow\left|x+2\right|=2+x\\ \Rightarrow\left[{}\begin{matrix}x+2=x+2\\x+2=-x-2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}0x=0\\2x=-4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}0x=0\\x=-2\end{matrix}\right.\)
Vậy x=-2
2.
d;
\(\left|x-5\right|\)=14-x
\(\Leftrightarrow\left[{}\begin{matrix}x-5=14-x\\x-5=x-14\end{matrix}\right.\)
em giải 2 cái này ra để tìm x
2*6*10+6*10*14+10*14*18+...+194*198*202/1*3*5+3*5*7+5*7*9+...+97*99*101
rút gọn
ta có
\(\frac{2.6.10+6.10.14+..+194.198.202}{1.3.5+3.5.7+..+97.99.101}=\frac{8.1.3.5+8.3.5.7+..+8.97.99.101}{1.3.5+3.5.7+..+97.99.101}\)
\(=\frac{8.\left(1.3.5+3.5.7+..+97.99.101\right)}{1.3.5+3.5.7+..+97.99.101}=8\)