Tìm x
\(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
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Tìm x biết:\(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
tìm x: \(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
Loan còn lượt cho đúng cho mình không chứ mấy bn kia chắc ko cho đúng đâu?
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(3x/7+1):(-4)=-1/28
3x/7+1=-1/28x(-4)
3x/7+1=1/7
3x/7=1/7-1=-6/7
3x=-6
x=-6:3=-2
Vậy x=-2
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Mình cần gấp bài này !!!
1/Tìm x, biết :
a/ \(\frac{7}{\left(x+3\right)\left(x+10\right)}+\frac{11}{\left(x+10\right)\left(x+21\right)}+\frac{13}{\left(x+21\right)\left(x+34\right)}+\frac{x}{\left(x+3\right)\left(x+34\right)}\)
b/ \(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(x-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=\frac{-1}{20}\)
Tìm x, biết :
\(\frac{7}{\left(x+3\right)\left(x+10\right)}+\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(x-7\right)\left(x-13\right)}\)
\(+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=\frac{-1}{20}\)
giúp mình với các bạn !!!!!!!!!!!!
\(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(2-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=-\frac{1}{20}\)
\(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(2-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=-\frac{1}{20}\)
ghi sai để nên mik ko giải dc
\(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(2-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=-\frac{1}{20}\)
Tìm x :\(\left(\frac{3x}{7}+1\right):\left(-4\right)=-\frac{1}{28}\)
\(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
\(\Leftrightarrow\frac{3x+7}{7}.\frac{1}{-4}=\frac{-1}{28}\)
\(\Leftrightarrow-\frac{3x+7}{28}=\frac{-1}{28}\)
\(\Leftrightarrow-\left(3x+7\right)=-1\)
\(\Leftrightarrow3x+7=1\)\(\Leftrightarrow3x=-6\)
\(\Leftrightarrow x=-2\)
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Tìm x
a)\(\frac{3}{\left(x-4\right).\left(x-7\right)}+\frac{6}{\left(x-7\right).\left(x-3\right)}+\frac{15}{\left(x-3\right).\left(x-38\right)}-\frac{1}{x-28}=\frac{-1}{20}\)