khó thế toy ko bt =)))

toy cũng vậy

Đặt A=1x3+3x5+5x7+7x9+...+99x101

6A=6x(1x3+3x5+5x7+7x9+...+99x101)

6A=1x3x6+3x5x6+5x7x6+7x9x6+...+99x101x6

6A=1x3x(5+1)+3x5x(7-1)+5x7x(9-3)+7x9x(11-5)+...+99x101x(103-97)

6A=1x3x5+1x3+3x5x7-3x5+5x7x9-3x5x7+7x9x11-5x7x9+...+99x101x103-99x101x97

6A=3+99x101x103

=>A=\(\frac{\text{3+99x101x103}}{6}\)

bài đó có ở trong sách toán ko hay tự đố ở ngoài vậy?

ds:6

\(\dfrac{1}{7}\times\dfrac{21}{8}-\dfrac{3}{8}\times\dfrac{1}{7}-\dfrac{1}{7}\times\dfrac{2}{8}\\ =\dfrac{1}{7}\times\left(\dfrac{21}{8}-\dfrac{3}{8}-\dfrac{2}{8}\right)\\ =\dfrac{1}{7}\times\dfrac{16}{8}\\ =\dfrac{1}{7}\times2\\ =\dfrac{2}{7}\)

\(\dfrac{1}{7}\times\dfrac{21}{8}-\dfrac{3}{8}\times\dfrac{1}{7}-\dfrac{1}{7}\times\dfrac{2}{8}\)

=\(\dfrac{1}{7}\times\left(\dfrac{21}{8}-\dfrac{3}{8}-\dfrac{2}{8}\right)\)

=\(\dfrac{1}{7}\times2\)

=\(\dfrac{2}{7}\)

\(=\dfrac{1}{7}\text{×}\left(\dfrac{21}{8}-\dfrac{3}{8}-\dfrac{2}{8}\right)\)

\(=\dfrac{1}{7}\text{×}2\)

\(=\dfrac{2}{7}\)

1 + 9 + 2 + 8 + 3 + 7 + 4 + 6 + 5 + 5 + 6 + 4 + 7 + 3 + 8 + 2 + 9 + 1

= 10 + 10 + 10 +10 +10 + 10 + 10 + 10 + 10

= 10 x 9

= 90

1+9+2+8+3+7+4+6+5+5+6+4+7+3+8+2+9+1

=10+10+10+10+10

=50

1.

\(\frac{3}{5}+\left\{\frac{2}{8}+\frac{2}{5}+\frac{6}{8}\right\}\)

\(=\frac{3}{5}+\left(\frac{10}{40}+\frac{36}{40}+\frac{30}{40}\right)\)

\(=\frac{3}{5}+\frac{76}{40}\)

\(=\frac{24}{40}+\frac{76}{40}\)

\(=\frac{100}{40}=\frac{5}{2}\)

2. 

\(3\frac{2}{9}-\left\{1\frac{5}{8}+1\frac{2}{9}\right\}\)

\(=\frac{29}{9}-\left\{\frac{13}{8}+\frac{11}{9}\right\}\)

\(=\frac{29}{9}-\left\{\frac{117}{72}+\frac{88}{72}\right\}\)

\(=\frac{29}{9}-\frac{205}{72}\)

\(=\frac{232}{72}-\frac{205}{72}\)

Chúc cậu học tốt !!!

\(=\frac{27}{72}=\frac{3}{8}\)

a) 3/5x7/8:10/9=21/40:10/9=189/400

b) 3 2/7x2 1/4:1 2/5=23/7x9/4:7/5=207/28:7/5=1035/196

c) 6/9+24/15+12/9+6/15=34/15+12/9+6/15=18/5+6/15=4

d) 3 2/9-( 1 5/8+1 2/9 )=29/9-(13/8+11/9)=29/9-205/72=3/8

tinh

a)  3/5 x 7/8 : 10/9

b) 3 2/7 x 2 1/4 : 1 2/5

c) 6/9 + 24/15 + 12/9 + 6/15

Đặt S = 1 x 2 + 2 x 3 + ..... + 9 x 10

3S = 1 x 2 x (3-0) + 2 x 3 x (4 - 1) + ....... + 9 x 10 x (11 - 8)

3S = 1 x 2 x 3 + 2 x 3 x 4 - 1 x 2 x 3 + ......... + 9 x 10 x 11 - 8 x 9 x 10

3S = ( 1 x 2 x 3 -1 x 2 x 3) + ( 2 x 3 x4 - 2 x 3 x 4) + ..... + (8 x 9  x 10 - 8 x 9 x 10) + 9 x 10 x 11

3S = 9 x 10 x 11 = 990

S = 990 : 3 = 330     

A=1/1*2+1/2*3+...+1/9*10

=1-1/2+1/2-1/3+...+1/9-1/10

=(1-1/10)+(1/2-1/2)+...+(1/9-1/9)

=(10/10-1/10)+0+...+0=9/10

\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}=1-\frac{1}{10}=\frac{9}{10}\)