\(A=\frac{1}{5}+\frac{1}{20}+\frac{1}{44}+\frac{1}{77}+...+\frac{1}{299}+\frac{1}{377}\)
Tính A.
Những câu hỏi liên quan
Tính tổng :\(\frac{1}{5}+\frac{1}{20}+\frac{1}{44}+\frac{1}{77}+\frac{1}{119}+\frac{1}{170}+\frac{1}{230}+\frac{1}{299}\)
Mình biết là 4/13 rồi nhưng các bạn trình bày ra giúp mình được không
Đúng 0
Bình luận (0)
Tinh
\(\frac{1}{5}\)+\(\frac{1}{20}\)+\(\frac{1}{44}+\frac{1}{77}+\frac{1}{119}+\frac{1}{170}+\frac{1}{230}+\frac{1}{299}\)
\(\frac{1}{5}+\frac{1}{20}+\frac{1}{44}+\frac{1}{77}+\frac{1}{119}+\frac{1}{170}+\frac{1}{230}+\frac{1}{299}\)
\(=\frac{1}{1.5}+\frac{1}{5.4}+\frac{1}{4.11}+\frac{1}{11.7}+...+\frac{1}{23.13}\)
\(=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{4}+...+\frac{1}{23}-\frac{1}{13}\)
\(=1-\frac{1}{13}\)
\(=\frac{12}{13}\)
Đúng 0
Bình luận (0)
Tính :
a) \(S=\frac{1}{5}+\frac{1}{20}+\frac{1}{44}+...+\frac{1}{1175}\)
b)\(S=1\frac{1}{3}.1\frac{1}{8}.1\frac{1}{15}.1\frac{1}{24}.1\frac{1}{35}.....1\frac{1}{9800}\)
tính giá trị biểu thứcAfrac{-378.132+189.64}{15+18+21+......+45+48}B1,4.frac{15}{14}-left(frac{4}{5}+frac{2}{5}right):2frac{1}{5}-frac{frac{73}{77}+frac{73}{165}+frac{73}{285}}{frac{25}{24}+frac{15}{180}+frac{20}{285}}Cfrac{7+frac{7}{12}-frac{7}{144}+frac{7}{60}}{5+frac{6}{12}-frac{5}{144}}.frac{frac{3}{4}-frac{3}{16}+frac{3}{64}-frac{3}{256}}{1-frac{1}{4}+frac{1}{16}-frac{1}{34}}-frac{1}{20}
Đọc tiếp
tính giá trị biểu thức
\(A=\frac{-378.132+189.64}{15+18+21+......+45+48}\)
\(B=1,4.\frac{15}{14}-\left(\frac{4}{5}+\frac{2}{5}\right):2\frac{1}{5}-\frac{\frac{73}{77}+\frac{73}{165}+\frac{73}{285}}{\frac{25}{24}+\frac{15}{180}+\frac{20}{285}}\)
\(C=\frac{7+\frac{7}{12}-\frac{7}{144}+\frac{7}{60}}{5+\frac{6}{12}-\frac{5}{144}}.\frac{\frac{3}{4}-\frac{3}{16}+\frac{3}{64}-\frac{3}{256}}{1-\frac{1}{4}+\frac{1}{16}-\frac{1}{34}}-\frac{1}{20}\)
Tính A=\(\frac{\frac{1}{1\cdot300}+\frac{1}{2\cdot301}+\frac{1}{3\cdot302}+...+\frac{1}{101\cdot400}}{\frac{1}{1\cdot102}+\frac{1}{2\cdot103}+\frac{1}{3\cdot104}+...+\frac{1}{299\cdot400}}\)
Gọi tử số là \(C\)và mẫu số là \(D\)
Ta có:
\(A=\frac{C}{D}\)
\(C=\frac{1}{1.300}+\frac{1}{2.301}+\frac{1}{3.102}+...+\frac{1}{101.400}\)
\(C=\frac{1}{299}\left[\left(1-\frac{1}{300}\right)\right]+\left(\frac{1}{2}-\frac{1}{301}\right)+\left(\frac{1}{3}-\frac{1}{302}\right)+...+\left(\frac{1}{101}-\frac{1}{400}\right)\)
\(C=\frac{1}{299}\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{101}-\frac{1}{300}-\frac{1}{301}-\frac{1}{302}-...-\frac{1}{400}\right)\)
\(D=\frac{1}{1.102}+\frac{1}{2.103}+\frac{1}{3.104}+...+\frac{1}{299.400}\)
\(D=\frac{1}{101}\left[\left(1-\frac{1}{102}\right)+\left(\frac{1}{2}-\frac{1}{103}\right)+\left(\frac{1}{3}-\frac{1}{104}\right)+...+\left(\frac{1}{299}-\frac{1}{400}\right)\right]\)
\(D=\frac{1}{101}\left(1+\frac{1}{2}+\frac{1}{3}+..+\frac{1}{299}-\frac{1}{102}-\frac{1}{103}-\frac{1}{104}-...-\frac{1}{400}\right)\)
\(D=\frac{1}{101}\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{101}-\frac{1}{300}-\frac{1}{301}-\frac{1}{302}-...-\frac{1}{400}\right)\)
\(\Rightarrow A=\frac{C}{D}=\frac{\frac{1}{299}\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{101}-\frac{1}{300}-\frac{1}{301}-\frac{1}{302}-...-\frac{1}{400}\right)}{\frac{1}{101}\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{101}-\frac{1}{300}-\frac{1}{301}-\frac{1}{302}-...-\frac{1}{400}\right)}\)
\(=\frac{\frac{1}{299}}{\frac{1}{101}}=\frac{101}{299}.\)
Vậy \(A=\frac{101}{299}.\)
Đúng 0
Bình luận (0)
Tìm x :
a) 10 + 15 + 20 + ... + 300 + x = 6750
b) \(\frac{1}{42}+\frac{1}{30}+\frac{1}{20}+\frac{1}{12}+\frac{1}{6}+\frac{1}{2}-\frac{1}{x+1}=\frac{59}{77}\)
a)Ta đặt A=10+15+...+300
Số số hạng của A là:(300-10):5+1=59(số)
Tổng của A là:(10+300).59:2=9145
=>9145+x=6750
=>x=6750-9145
=>x=-2395
b)\(\frac{1}{42}+\frac{1}{30}+\frac{1}{20}+\frac{1}{12}+\frac{1}{6}+\frac{1}{2}-\frac{1}{x+1}=\frac{59}{77}\)
<=>\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{6.7}-\frac{1}{x+1}=\frac{59}{77}\)
<=>\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{6}-\frac{1}{7}-\frac{1}{x+1}=\frac{59}{77}\)
<=>\(1-\frac{1}{7}-\frac{1}{x+1}=\frac{59}{77}\)
<=>\(\frac{6}{7}-\frac{1}{x+1}=\frac{56}{77}\)
<=>\(\frac{1}{x+1}=\frac{6}{7}-\frac{56}{77}=\frac{66}{77}-\frac{56}{77}\)
<=>\(\frac{1}{x+1}=\frac{10}{77}\)
<=>10(x+1)=77
<=>10x+10=77
<=>10x=67
<=>x=6,7
Đúng 0
Bình luận (0)
\(3\frac{2}{5}+4\frac{3}{7}-\frac{1}{4}+\frac{44}{77}-2\frac{2}{5}-0,75\)
3 / 2 / 5 + 4 / 3 / 7 - 1 / 4 + 44 / 77 - 2 / 2 / 5 - 0,75
= 17 / 5 + 31 / 7 - 1 / 4 + 4 / 7 - 12 / 5 - 3 / 4
= ( 17 / 5 - 12 / 5 ) + ( 31 / 7 - 4 / 7 ) + ( 1 / 4 + 3 / 4 )
= 1 + 9 + 1
= 11
Đúng 0
Bình luận (0)
Bài làm
=17/5 + 31/7 - 1/4 +4/7 - 12/5 - 3/10
=( 17/5+12/5)-(31/7+4/7)-3/10
=29/5-5/1-3/10
=29/5-3/10-5/1
=61/10
Mình ko chác đâu nhé!
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
Tính A biết :\(A=\frac{1}{21}+\frac{1}{77}+\frac{1}{165}+\frac{1}{285}+\frac{1}{437}\)
A = \(\frac{1}{21}+\frac{1}{77}+\frac{1}{165}+\frac{1}{285}+\frac{1}{437}\)
A = \(\frac{1}{3.7}+\frac{1}{7.11}+\frac{1}{11.15}+\frac{1}{15.19}+\frac{1}{19.23}\)
A = \(\frac{1}{4}.\left(\frac{1}{3}-\frac{1}{7}\right)+\frac{1}{4}.\left(\frac{1}{7}-\frac{1}{11}\right)+\frac{1}{4}.\left(\frac{1}{11}-\frac{1}{15}\right)+\frac{1}{4}.\left(\frac{1}{15}-\frac{1}{19}\right)+\frac{1}{4}.\left(\frac{1}{19}-\frac{1}{23}\right)\)
A = \(\frac{1}{4}.\left(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+\frac{1}{15}-\frac{1}{19}+\frac{1}{19}-\frac{1}{23}\right)\)
A = \(\frac{1}{4}.\left(\frac{1}{3}-\frac{1}{23}\right)\)
A = \(\frac{1}{4}.\frac{20}{69}\)
A = \(\frac{5}{69}\)
Đúng 0
Bình luận (0)
Tính giá trị biểu thức:
a) \(M=\frac{3}{299}.\left(2+\frac{1}{433}\right)-\frac{1}{229}.\frac{432}{433}-\frac{4}{229.433}\)
b) \(N=3.\frac{1}{117}.\frac{1}{119}-\frac{4}{117}.5\frac{118}{119}-\frac{5}{117.119}+\frac{8}{39}\)