tim x thoa man: -12(x-5)+7(3-x)=5
Tìm x thoa man:-12(x-5)+7(3-x)=5
Tim x thoa man -12 * (x-5) + 7(3-x )=5
-12x+60+21-7x=5
-12x-7x=-60-21+5
-19x=-76
x=4
-12.x + 12.5+7.3-7.x=5
-12.x+ 60+21-7.x=5
-19.x=76
=> không có x
Tim x thoa man : -12.(x-5)+7.(3-x0) =5 .
- 12.( x - 5 ) + 7.( 3 - x ) = 5
=> - 12x + 60 + 21 - 7x = 5
=> ( - 12x - 7x ) + 60 + 21 = 5
=> - 19x + 81 = 5
=> - 19x = 5 - 81
=> - 19x = - 76
=> x = ( - 76 ) : ( - 19 )
=> x = 4
Vậy x = 4
-12x+60+21=5
-12x+81=5
-12x=-76
x=19/3 k nha
tim x thoa man -12*(x-5)+7*(3-x)=5
(-12) (x - 5) + 7(3 - x) = 5
=> -12x + 60 + 21 - 7x - 5 = 0
=> -19x + 76 = 0
=> -19x = -76
=> x = 4
-12(x-5)+7(3-x)=5
<=>(-12x)-(-60)+21-7x=5
<=>(-12x)+60+21-7x=5
<=>(-12x-7x)+81=5
<=>(-19x)=-76<=>x=4
vậy x=4
Tìm tập hop cac so nguyen x thoa man cac dieu kien sau
a)7/2 . 5/12 - 1 < x < 23/3 ÷ 7/3 + 5/7
b)-2240/6 x + 3 ÷5/3 la so nguyen
tim x thoa man -12(x-5)+7(3-x) =5
tim x thoa man :12(x-5)+7(3-x)=5
12(x-5)+7(3-x)=5
<=>12x-60+21-7x=5
<=>12x-39-7x=5
<=>12x-7x=39+5
<=>5x=44<=>x=44/5
Vậy x=44/5
so nguyen duong x thoa man x^5=x^12
Ta có : x5 = x12
=> x5 - x12 = 0
x5 ( 1 - x7 ) = 0
=> x5 = 0 hoặc 1 - x7 = 0
+ Nếu x5 = 0 => x = 0
+ Nếu 1 - x7 = 0
=> x7 = 1 = 17
=> x = 1
Vậy : x thuộc { 0 ; 1 }
cho x la so nguyen thoa man : -7/25<x/30<-1/5. so gia tri cua x thoa man la
-7/25<x/30<-1/5
quy đồng mẫu
=>(-42/150)<(5x/150)<(-30/150)
vậy số giá trị là 11