Ta có: \(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}\) = \(\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}\) = \(\frac{2^5.8}{2^5.22}\) = \(\frac{8}{22}\) =\(\frac{56}{154}\)

​\(\frac{3^4.5-3^6}{3^4.13+3^4}\) = \(\frac{3^4.\left(5-3^2\right)}{3^4.\left(13+1\right)}\) = \(\frac{3^4.\left(-4\right)}{3^4.14}\) = \(\frac{-4}{14}\)= \(\frac{-44}{154}\)

a , 5.6 + 5.7 / 5.8 + 20 = 5.6 + 5.7 / 5.8 + 5 . 4 = 5 . ( 6+7 ) / 5 . ( 8 + 4 ) = 6 + 7 / 8 + 4 = 13 / 12                                                                8 . 9 + 4 .15 / 12 . 7 - 180 = 4 . 2 . 3 . 3 + 2 . 2 . 3 . / 4 . 3 . 7 - 180 = 4 . 2 . 3 . 3 + 2.2.3.5 / 3 . 4 . 7 - 3 . 2 . 2 . 3. 5 = 1 . 2 . 1 . 1 + 1 . 1 . 1. 1 / 1 . 1 . 7 - 1 . 1 . 1 . 1 .1 = 3 / 6 = 1/2                                                                                                                                                      b , 2^5 . 7 +2^5 / 2^5 . 5^2 - 2^5 .3  = 2^5 . ( 7 + 1) / 2^5 ( 5^2 - 3 ) = 7+1 / 5^2 - 3 = 8 / 22 = 4 / 11                                                           3^4 . 5 - 3^6 / 3^4 . 13 + 3^4 = 3^4 . 5 - 3^4 . 3^2  / 3^4 . 13 + 3^4 = 3^4 . ( 5 - 3^2 ) / 3^4 . ( 13 + 1 ) = 5 - 3^2 / 13 + 1 = -4 / 14 = -2 / 12

a) \(\frac{25.9-25.17}{-8.80-8.10}=\frac{25.\left(9-17\right)}{-8.\left(80+10\right)}=\frac{25.\left(-8\right)}{-8.90}=\frac{5}{18}\)

b) \(\frac{48.12-48.15}{-3.270-3.30}=\frac{48.\left(12-15\right)}{-3.\left(270+30\right)}=\frac{48.\left(-3\right)}{-3.300}=\frac{4}{25}\)

c) \(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}=\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}=\frac{2^5.8}{2^5.\left(25-3\right)}=\frac{2^5.8}{2^5.22}=\frac{4}{11}\)

d) \(\frac{3^4.5-3^6}{3^4.13+3^4}=\frac{3^4.\left(5-3^2\right)}{3^4.\left(13+1\right)}=\frac{3^4.\left(5-9\right)}{3^4.14}=\frac{3^4.\left(-4\right)}{3^4.14}=\frac{-2}{7}\)

Nguyễn Lương Bảo Tiên tại sao 

3^4 × 5 - 3^6 lại = 3^4 (5 - 3^2) vậy

phần d ý

à Bảo Tiên lm đúng rồi

Xét: 2^5x7+2^5/2^5.5^2-2^5.3

=2^5x7+2^5x1/2^5x25-2^5x3

=2^5x(7+1)/2^5x(25-3)

=2^5x8/2^5x22

=8/22

=4/11

Xét: 3^4x5-3^6/3^4x13+3^4

=3^4x5-3^4x3^2/3^4x13+3^4

=3^4x(5-9)/3^4x(13+1)

=3^4x(-4)/3^4x14

=-4/14

=-2/7

Mẫu số chung của 4/11 và -2/7 là 77

-->Thừa số phụ tương ứng là 7 và 11

Quy đồng : 4/11=4x7/11x7=28/77

                -2/11=(-2)x11/7x11=-22/77

Vậy ta có 28/77 và -22/77

\(\frac{3^4\cdot5-3^6}{3^4\cdot13+3^4}=\frac{3^4\cdot5-3^2\cdot3^4}{3^4\cdot13+3^4}=\frac{5-3^2}{13}=\frac{5-9}{13}=\frac{-4}{13}\)

Chắc là vậy đó

\(\frac{3^4.5-3^6}{3^4.13+3^4}=\frac{3^4.5-3^4.3^2}{3^4.\left(13+1\right)}=\frac{3^4.\left(5-9\right)}{3^4.14}=-\frac{4}{14}=-\frac{2}{7}\)