(1/2+1/4+1/8+1/16):x=1/2+1/6+1/12+1/20+...+1/132
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Tìm x biết (1/2+1/4+1/8+1/16):x=1/2+1/6+1/12+1/20+...+1/132
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Tìm x biết (1/2+1/4+1/8+1/16):x=1/2+1/6+1/12+1/20+...+1/132
Ta có:
(1/2 + 1/4 + 1/8 + 1/16) = 8/16 + 4/16 + 2/16 + 1/16 = 15/16.
1/2 + 1/6 + 1/12 + 1/20 +…+ 1/132 = 1/(1.2) + 1/(2.3) + 1/(3.4) + 1/(4.5) +…+1/(11.12)
= (1 – 1/2) + (1/2 – 1/3) + (1/3 – 1/4) + (1/4 – 1/5) +…+ (1/11 – 1/12)
= 1 – 1/12 = 11/12
Vậy x = (15/16) : (11/12) = 45/44.
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(1/2+1/4+1/8+1/16):x=1/2+1/6+1/12+1/20+...+1/132
(1-1/2+1/2-1/4+1/4-1/8+1/8-1/16):x=1/1x2+1/2x3+1/3x4+1/4x5+...+1/11x12
(1-1/16):x=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/11-1/12
15/16:x=1-1/12
15/16:x=11/12
x=15/16:11/12
x=45/44
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Tìm x biết (1/2+1/4+1/8+1/16):x=1/2+1/6+1/12+1/20+...+1/132
tìm x
[ 1/2 + 1/4 + 1/8 + 1/16 ] : x = 1/2 + 1/6 + 1/12 + 1/20 + .......+ 1/132
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(1/2+1/4+1/8+1/16):x=1/2+1/6/+1/12+1/20+......+1/132
ai giải đc cảm ơn nhìu
(1/2+1/4+1/8+1/16):x=1/2+1/6+1/12+.....+1/132
15/16 : x = 1/1x2+1/2x3+1/3x4+.........+1/11x12
15/16 : x = 1-1/2+1/2-1/3+1/3-1/4+........+1/11-1/12
15/16 :x = 1-1/12
15/16 : x = 11/12
x = 15/16 : 11/12
x= 45/44
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<1/2+1/4+1/8+1/16> x y =1/2+1/6+1/12+1/20+........+1/132
mình đang cần liền ai nhanh mình tick
tìm x biết : {1/2+1/6+1/8+1/16}:x=1/2+1/6+1/12+1/20+...+1/132 .CÁC BẠN GIÚP MÌNH NHA
Tìm y (1/2+1/4+1/8+1/16):y=1/2+1/6+1/12+1/20+1/30+...+1/132
( 1/2 + 1/4 + 1/8 + 1/16 ) : x = 1/2 + 1/6 + 1/12 + ... + 1/132
( 1/2 + 1/4 + 1/8 + 1/16) = 8/16 + 4/16 + 2/16 + 1/16
= 15/16
= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ...+ 1/11 - 1/12
= 1 - 1/12 = 11/12
=> x = 15/16 : 11/12
x = 45/44
Vậy x = 45/44
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