32 x 2 = ?
32 x 67 +32 x 2 - 32 x 2
= 32 x (67 + 2 - 2 ) = 32 x 67 = 2144
32 x 67 + 32 x 2 - 32 x 2
= 32 x (67+2-2)
=32 x 67
=2144
Đúng ghi Đ, sai ghi S:
a) 32 : 4 : 2 = 8 : 2 = 4
32 : 4 : 2 = 32 : 2 = 16
b) 18 : 2 x 3 = 18 : 6 = 3
18 : 2 x 3 = 9 x 3 = 18
a) 32 : 4 : 2 = 8 : 2 = 4
32 : 4 : 2 = 32 : 2 = 16
b) 18 : 2 x 3 = 18 : 6 = 3
18 : 2 x 3 = 9 x 3 = 18
1.Tính
a) 81 + 243+ 19
b) 2 x 25 x 2 x 16 x 4
c) 32 x 47 + 32 x 54 - 32
Bài giải
a, \(81+243+19=\left(81+19\right)+243=100+243=343\)
b, \(2\text{ x }25\text{ x }2\text{ x }16\text{ x }4=25\text{ x }4\text{ x }2\text{ x }2\text{ x }16=25\text{ x }8\text{ x }32=200\text{ x }32=6400\)
c, \(32\text{ x }47+32\text{ x }54-32=32\text{ x }\left(47+54-1\right)=32\text{ x }100=3200\)
a,81+19+243
=100+243
b,(2x25)x2x(16x4)
=50x2x64
=100x64
=6400
c,32x47+32x54-32x1
=32x(47+54-1)
=32x100
=3200
a,\(81+243+19=\left(81+19\right)+243\)
\(=100+243=343\)
b,\(2\times25\times2\times16\times4=\left(25\times4\right)\times\left(2\times2\times16\right)\)
\(=100\times64=6400\)
c,\(32\times47+32\times54-32=32\times47+32\times54-32\)
\(=\left(47+54-1\right)\times32\)
\(=3200\)
32 x [ 2 x X 9 ] = 32
32 . ( 2 . x9) = 32
2 . x9 = 32 : 32
2 . x9 = 1
x9 = 1:2
x9= 1/2
x = 1/2 : 9
x= 1/18
dấu chấm là nhân nha
l-ike đi
tìm x:
x/32=2/x
x phần 32= 2 phần x
x/32=2/x
=xx=32.2
=2x=64
x=64:2
x=32
chúc bạn học tốt
\(\frac{x}{32}=\frac{2}{x}\)
NHÂN CHÉO CHO NHAU TA CÓ:
\(x.x=32.2\)
\(\Leftrightarrow x^2=64\)
\(\Leftrightarrow x^2=8^2\)
\(\Leftrightarrow x=8\)
BẠN KIA LÀM SAI RỒI X.X MÀ BẰNG 2X CÓ PHẢI X+X ĐÂU
Chứng minh rằng:
A = 1/3 + 1/32 + 1/33 + ..........+ 1/399 < 1/2
B = 3/12x 22 + 5/22 x 32 + 7/32 x 42 +............+ 19/92 x 102 < 1
C = 1/3 + 2/32 + 3/33 + 4/34 +.........+ 100/3100 ≤ 0
\(A=\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{99}}\)
\(\Rightarrow\dfrac{A}{3}=\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{100}}\)
\(\Rightarrow A-\dfrac{A}{3}=\dfrac{2A}{3}=\left(\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{99}}\right)-\left(\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{100}}\right)\)
\(\Rightarrow\dfrac{2A}{3}=\left(\dfrac{1}{3^2}-\dfrac{1}{3^2}\right)+\left(\dfrac{1}{3^3}-\dfrac{1}{3^3}\right)+...+\left(\dfrac{1}{3^{99}}-\dfrac{1}{3^{99}}\right)+\left(\dfrac{1}{3}-\dfrac{1}{3^{100}}\right)=\dfrac{1}{3}-\dfrac{1}{3^{100}}\)
\(\Rightarrow2A=3\cdot\left(\dfrac{1}{3}-\dfrac{1}{3^{100}}\right)\)
\(\Rightarrow\text{A}=\dfrac{1-\dfrac{1}{3^{99}}}{2}\)
\(\Rightarrow A=\dfrac{1}{2}-\dfrac{1}{2.3^{99}}< \dfrac{1}{2}\)
a. 27 x (-17) + (17) x 127
b. 2 x (1 + 32) - 2 x 32
a) 27 x (-17) + 17 x 127
= 27 x (-17) - 17 x (-127)
= -17 x (27-127)
= -17 x -100 = 1700
b) 2 x (1 +32) - 2 x 32
= 2 x (1 + 32 - 32)
= 2 x 1 = 2
Giúp mik với
2 x ( 1 + 32 ) -2 x 32
\(\text{2 x ( 1 + 32 ) -2 x 32}\)
\(=2.33-2.32\)
\(=2.\left(33-32\right)\)
\(=2.1\)
\(=2\)
chúc bạn học tốt
tìm x:\(\frac{32}{8.11}+\frac{32}{11.14}+\frac{32}{14.17}+...+\frac{32}{197.200}-x=\frac{1}{2}\)
\(32\left(\frac{1}{8.11}+\frac{1}{11.14}+\frac{1}{14.17}+...+\frac{1}{197.200}\right)-x=\frac{1}{2}\)
\(\frac{32}{3}\left(\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}+....+\frac{3}{197.200}\right)-x=\frac{1}{2}\)
\(\frac{32}{3}\left(\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}+...+\frac{1}{197}-\frac{1}{200}\right)-x=\frac{1}{2}\)
\(\frac{32}{3}\left(\frac{1}{8}-\frac{1}{200}\right)-x=\frac{1}{2}\)
x=0.78
tìm x:
a,[ ( x+32)-17]*2=42
b,[ 61+(53-x)]*17=1785
c,[ ( x^2+54)-32 ] * 2=244
a) => (x+32) - 17 = 42:2 = 21
=> x+32 = 21+17 = 38
=> x=38-32=6
b) => 61+(53-x) = 1785:17=105
=> 53-x = 105-61=44
=> x = 53-44 =9
c) => x^2 +54 -32 = 244:2 = 122
=> x^2 +22 = 122
=> x^2 = 122-2=100
=> x= 10 hoặc -10
giải oy pn **** giùm mk nka