(8796-1102).(8796-1102)+8796+1102

=7694.7694+8796+1102

=59197636+8796+1102 

=59207534

=>7694 x 7694 + 8796 + 1102 = 59207534

(k) đúng cho mình

(8796-1102)x(8796-1102)+8796+1102=59207534

x + 1254 = 8796

         x   = 8796 - 1254

         x   =      6542

tink nhé

\(x=8796-1254\Rightarrow x=7542\)

x + 1254 = 8796

                      x = 8796 - 1254

                      x = 7542

đáp số : x=7542

4152 x 5 x 6 = 124560

4152 x 5 x 6 = 124560. 

124560

4152 x 11 - 1268 + 256 x 473

= 45672 - 1268 + 121088

= 165492

= 45672-1268+121088

=44404+121088

= 165,492

nhớ tích cho mình nha mình cảm ơn rất nhìu  =)))

58889 nha

67685-8796=58889

58889

\(7086+6547\)

\(=13633\)

\(6076+7534\)

\(=13610\)

\(7980+7088\)

\(=15068\)

\(8796+8764\)

\(=17560\)

` @ H A N `

$7086+6547$

$=13633$

$6076+7534$

$=13610$

$7980+7088$

$=15068$

$8796+8764$

$=17560$

\(\dfrac{3876}{3879}\)=1-\(\dfrac{3}{3879}\)=1-\(\dfrac{1}{1293}\)

\(\dfrac{4152}{4155}\)=1-\(\dfrac{3}{4155}\)=1-\(\dfrac{1}{1385}\)

vì 1293<1385 nên \(\dfrac{1}{1293}\)>\(\dfrac{1}{1385}\)

nên ta có 1-\(\dfrac{1}{1293}\)<1-\(\dfrac{1}{1385}\)

hay\(\dfrac{3876}{3879}\)<\(\dfrac{4152}{4155}\)

Tả lời nhanh giùm tôi

3900+8796+ 1 - 1 + 11= 12707

12707

ket qua bang 12707

h minh nha