Tim x,y biet (x+2).(3-x)>0 ......(cac ban trinh bay ro rang giup minh nha)
Những câu hỏi liên quan
Tim x biet :
a, |2x+1|-x=5
b, |x-10|10+|x-11|10=1
Trinh bay cach lam ro rang cho minh nhe
Chieu phai nap roi
Ai trinh bay ro rang nhat minh se tick
\(\left|2x+1\right|-x=5\)
\(\Rightarrow2x+1-x=5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=5-1\)
\(\Rightarrow x=4\)
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Tim 2 so tu nhien X;Y biet rang :X<19,99<Y?
cac ban cung giup minh nha. thank you,thank you
1, tim x
5+x-3=5-(x+4)
x-(5|-7|+3)=|-8|+6-2
|x-3|+7
12-3|x-1|=6
cac ban giup minh nhe nho cac buoc tinh ro rang nha minh se like cho
\(5+x-3=5-\left(x+4\right)\)
\(5+x-3=5-x-4\)
\(x+x=5-4-5+3\)
\(2x=-1\)
\(x=\frac{-1}{2}\)
vay \(x=\frac{-1}{2}\)
\(x-\left(5.\left|-7\right|+3\right)=\left|-8\right|+6-2\)
\(x-\left(5.7+3\right)=8+6-2\)
\(x-38=12\)
\(x=12+38\)
\(x=50\)
vay \(x=50\)
\(\left|x-3\right|+7=0\)
\(\left|x-3\right|=-7\)( ko ton tai)
\(12-3\left|x-1\right|=6\)
\(3\left|x-1\right|=6\)
\(\left|x-1\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-1=2\\x-1=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
vay \(\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
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cac ban trinh bay giup minh voi nhe:
1.Tim so du khi chia so tu nhien n cho 7 , biet rang 6n:7 du 2
tim 5 gia tri cua x
a, 1983(x-7)>0
b, (-2010)(x+3)>0
cac ban giai giup minh voi giai ro rang ai nhanh se dc 3 tick ^.^
a, Vì 1983 > 0
Mà 1983.(x-7) > 0
=> x-7 > 0
=> x > 7
5giá trị của x là : 8;9;10;11;12
b, Vì -2010 < 0
Mà (-2010).(x+3) > 0
=> x+3 < 0
=> x < -3
5 giá trị của x là : -4;-5;-6;-7;-8
Tk mk nha
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mình sẽ cho cac ban dung 3 k nhung phai giai ro ra nhe tung buoc mot
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Bai1 : -5 phan 2 -7x=x-4 phan 3
bai 2: Mot ba no mang mot ro trung ra ban . Sau khi ban mot hoi lau ba kiem tra tay rang neu ba ban them duoc 2 qua nua thi ba se ban duoc 4 phan 5 so trung luc dau. Tim so trung trong ro luc dau biet so trung con lai la 13 qua
CAC BAN GIUP MKNH NHA! MINH SE KET BAN
tim x biet;
/x+1/2/+/x+1/6/+.......+/x+1/110/=11*x
Cac ban trinh bay that day du nhe
Cac ban lam nhanh ho minh,minh dang can gap
Theo bài ra ta có:
|x+\(\frac{1}{2}\)|\(\ge\)0
|x+\(\frac{1}{6}\)|\(\ge\)0
............................
|x+\(\frac{1}{110}\)|\(\ge\)0
\(\Rightarrow\)|x+\(\frac{1}{2}\)|+|x+\(\frac{1}{6}\)|+...+|x+\(\frac{1}{110}\)|\(\ge\)0
\(\Rightarrow\)11.x\(\ge\)0
\(\Rightarrow\)x\(\ge\)0
\(\Rightarrow\)x dương.
Khi đó:|x+\(\frac{1}{2}\)|+|x+\(\frac{1}{6}\)|+...+|x+\(\frac{1}{110}\)|=11.x
\(\Rightarrow\)x+\(\frac{1}{2}\)+x+\(\frac{1}{6}\)+...+x+\(\frac{1}{110}\)=11.x
\(\Rightarrow\)27.x+\(\left(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{110}\right)\)=11x
\(\Rightarrow\)\(\left(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{110}\right)\)=-16x
\(\Rightarrow\)\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{10.11}\)=-16x
\(\Rightarrow\)\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{10}-\frac{1}{11}\)=-16x
\(\Rightarrow\)\(\frac{10}{11}\)=-16x
\(\Rightarrow\)\(\frac{10}{-176}=x\)
Vậy \(x=\frac{10}{-176}\).
giup minh voi
cho 1 so tu nhien co 2 chu so . Biet rang tong cac so tu nhien lien tiep bat dau tu den so nay la 1 so ma 2 chu so tan cung cua no bang chinh so so co 2 chu so ban dau . tim so ban dau
trinh bay cach giai nhu the nao day cac ban giup minh voi
tim x biet
/x+2/=/x-2/
minh biet dap an la 0 nhung trinh bay kieu gi
giup minh nhe, nhanh len minh can gap
