Dịch bài toán sau và giải :
"Give a right triangle ABC (Â=90) with B =40 and the line d is a the midperpendicular of the segment BC . Suppose that d AB = {E} , E of the segment BC . If BE=16 cm then the area of ABC is ... cm^2.
(round to three demical places in each step)
A . 256
B . 147,95
C . 128
D . 295,9
Những câu hỏi liên quan
6 tháng 1 2022 lúc 6:15
The triangle ABC has \(AB=24cm\). If D is on the line segment AC such that \(\widehat{ABC}=\widehat{BDC}\)and \(AD=7cm;DC=9cm\)then what is the length of BD?
Note: You must write your answer in English.
vtui,yvtnytifn tfmt rtdnhx gh yhf g fgxh
We have \(\Delta CAB\sim\Delta CDB\left(g.g\right)\Rightarrow\dfrac{CB}{CD}=\dfrac{CA}{CB}\) \(\Rightarrow CB^2=CD\cdot CA\) We have \(CA=CD+DA=16\left(cm\right)\) \(\Rightarrow CB^2=9\cdot16=144\Rightarrow CB=12\left(cm\right)\) We have \(\dfrac{DB}{BA}=\dfrac{CB}{CA}=\dfrac{12}{16}=\dfrac{3}{4}\) \(\Rightarrow DB=\dfrac{3}{4}AB=18\left(cm\right)\)
1. Two bisector BD and CE of the triangle ABC intersect at O. Suppose that BD.CE 2BO.OC . Denote by H the point in BC such that .OH⊥BC . Prove that AB.AC 2HB.HC 2. Given a trapezoid ABCD with the based edges BC3cm , DA6cm ( AD//BC ). Then the length of the line EF ( Ein AB,Fin CD and EF // AD ) through the intersection point M of AC and BD is ............... ? 3. Let ABC be an equilateral triangle and a point M inside the triangle such that MA^2MB^2+MC^2 . Draw an equilateral triangle ACD whe...
Đọc tiếp
1. Two bisector BD and CE of the triangle ABC intersect at O. Suppose that BD.CE = 2BO.OC . Denote by H the point in BC such that .\(OH⊥BC\) . Prove that AB.AC = 2HB.HC
2. Given a trapezoid ABCD with the based edges BC=3cm , DA=6cm ( AD//BC ). Then the length of the line EF ( \(E\in AB,F\in CD\) and EF // AD ) through the intersection point M of AC and BD is ............... ?
3. Let ABC be an equilateral triangle and a point M inside the triangle such that \(MA^2=MB^2+MC^2\) . Draw an equilateral triangle ACD where \(D\ne B\) . Let the point N inside \(\Delta ACD\) such that AMN is an equilateral triangle. Determine \(\widehat{BMC}\) ?
4. Given an isosceles triangle ABC at A. Draw ray Cx being perpendicular to CA, BE perpendicular to Cx \(\left(E\in Cx\right)\) . Let M be the midpoint of BE, and D be the intersection point of AM and Cx. Prove that \(BD⊥BC\)
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
I don't know English very much so i can't answere your question. Sory about that :(
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
Mới học lớp 7 thôi, ko làm được bài nhưng để mk dịch đề thử nhá:
Cho tam giác ABC (A^= 90o), BD là tia phân giác của góc B (D thuộc AC). Nếu AD= 6cm, AB= 12cm thì diện tích của tam giác ABC là .....cm2.
Đúng 0
Bình luận (0)
Dựng DE vuông góc với BC (E thuộc BC).2 tam giác vuông ABD và EBD bằng nhau (gcg) nên \(S_{ABD}=S_{EBD}=\frac{1}{2}\cdot12\cdot6=36\)(cm2)Và cạnh DE=AD=6(cm)2 tam giác vuông CED và CAB có chung góc C thì đồng dạng với nhau với tỷ lệ cạnh là: \(\frac{DE}{AB}=\frac{6}{12}=\frac{1}{2}\)nên tỷ lệ diện tích bằng bình phương tỷ lệ cạnh, ta có:\(\frac{S_{CED}}{S_{CAB}}=\frac{1}{2^2}=\frac{1}{4}\)Vậy \(S_{ABC}=S_{ABD}+S_{BDE}+S_{CED}=\left(2+\frac{1}{4}\right)S_{ABD}=\frac{9}{4}S_{ABD}=\frac{9}{4}\cdot36=81\)(cm2).
Đúng 0
Bình luận (0)
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
Let ABC be a triangle with AB = 3cm, AC = 7cm. The internal bisector of the angle BAC intersects BC at D. The line passing through D and parallel to AC cuts AB at E. Find the measure of DE. Answer: DE = ..........cm.
with triangle ABC, d is the line passing through B, E of AC. Via E draw straight lines parallel to AB and BC cut d at M, N. D is the intersection of ME and BC. NE lines cut AB and MC at F and K. CMR AFN triangles are in the same form as the MDC triangle
In triangle ABC, BC=AC and BCA=900. D and E are points on AC and AB respectively such that AD=AE and 2CD =BE.Let P be the point of intersection of BD with the bisector of angle CAB. What is the angle PCB in degrees?
In triangle ABC, BC=AC and BCA=900. D and E are points on AC and AB respectively such that AD=AE and 2CD =BE.Let P be the point of intersection of BD with the bisector of angle CAB. What is the angle PCB in degrees?