a, x = 384

b, x = 161

c, x = 8

d, x = 15

X

Tìm x εIN biết
a) 390 - (x-8) = 168:13
b) (x-140) : 7 = 27 - 24
c) x- 6 :2 - ( 48 - 24 ) :2 :6 - 3 = 0
d) x+5.2-(32+16.3:6-15)=0

b) \(\left(x-140\right):7=27-24\)

\(\left(x-140\right):7=3\)

\(x-140=21\)

\(x=161\)

      vay   \(x=161\)

c) \(x-6:2-\left(48-24\right):2:6-3=0\)

\(x-3-24:2:6-3=0\)

\(x-3-2-3=0\)

\(x-8=0\)

\(x=8\)

vay \(x=8\)

d) \(x+5.2-\left(32+16.3:6-15\right)=0\)

\(x+10-\left(32+8-15\right)=0\)

\(x+10-25=0\)

\(x-15=0\)

\(x=15\)

vay \(x=15\)

a) \(390-\left(x-8\right)=168:13\)

\(390-x+8=\frac{168}{13}\)

\(x+8=390-\frac{168}{13}\)

\(x+8=\frac{5070}{13}-\frac{168}{13}\)

\(x+8=\frac{4902}{13}\)

\(x=\frac{4902}{13}-8\)

\(x=\frac{4798}{13}\)

vay \(x=\frac{4798}{13}\)

(6^2+7^2+8^2+9^2+10^2)-(1^2+2^2+3^2+4^2+5^2)

a)\(\left(x-140\right)\)\(\div\)7=27-4-3 =20\(\Rightarrow\)    \(\left(x-140\right)\) =20x7=140\(\Rightarrow\) x=0                                                                                                                                                                              

390-(x-7)=169

x-7=221

x=228

mấy bài kia tương tự

x + 10 - (32 + 48 : 6 - 15) = 0

x + 10 - (32 + 8 - 15)       = 0

x + 10 - 25                     = 0

x                                   = 0 + 25 - 10

x                                  =15

bay gio mk ranh rui mk lam cho

x+5.2-(32+16.3:6-15)=0

x+5.2-(32+48:6-15)   =0

x+5.2-(32+6-15)        =0

x+5.2-(38-15)            =0

x+5.2-23                   =0

x+10-23                    =0

x+10                         =0+23

x+10                         =23

                              x=23-10

                              x=13

chuc bn hoc gioi!

x+5.2-(32+16:3x6-15)=0

=> x+ 5+10-(32:32-15)=0

=> x+ 15- (-14)=0

=>x+15 +14=0

=> x= 0-14-15

=>x= -29

25 nhé bạn

ý lộn 15 nhé bạn

\(\Leftrightarrow\)\(5x+10-25=0\)

\(\Leftrightarrow\)\(5x=15\)

\(\Leftrightarrow\)\(x=\frac{15}{5}=3\)