-3/15 + -3/35 + -3/63 + -3/99 + -3/143 + -3/195
-3/15 + -3/35 + -3/63 + -3/99 + -3/143 + -3/195
Các bạn giúp mk với. Mk cần gấp
\(\frac{-3}{15}+\frac{-3}{35}+\frac{-3}{63}+\frac{-3}{99}+\frac{-3}{143}+\frac{-3}{195}\)
\(=\frac{-3}{3.5}+\frac{-3}{5.7}+\frac{-3}{7.9}+\frac{-3}{9.11}+\frac{-3}{11.13}+\frac{-3}{13.15}\)
\(=\frac{-3}{2}\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}+\frac{2}{13.25}\right)\)
\(=\frac{-3}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}\right)\)
\(=\frac{-3}{2}.\left(\frac{1}{3}-\frac{1}{15}\right)=\frac{-3}{2}.\frac{4}{15}=\frac{-2}{5}\)
\(=\frac{-3}{3\cdot5}+\frac{-3}{5\cdot7}+\frac{-3}{7\cdot9}+...+\frac{-3}{13\cdot15}\)
\(=-\frac{3}{2}\left(\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+...+\frac{2}{13\cdot15}\right)\)
\(=-\frac{3}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{13}-\frac{1}{15}\right)\)
\(=-\frac{3}{2}\left(\frac{1}{3}-\frac{1}{15}\right)\)
\(=-\frac{3}{2}\cdot\frac{4}{15}\)
\(=\frac{-2}{5}\)
2/3+2/15+2/35+2/63+2/99+2/143+2/195
mi tích tau tau tích mi xong tau trả lời nka việt nam nói là làm
A = 1/3+1/15+1/35+1/63+1/99+1/143+1/195=?
Giải:
Đặt A = 1/3+1/15+1/35+1/63+1/99+1/143+1/195
2A= 2/(1.3) + 2/(3.5) + 2/(5.7) + 2/(7.9)+2/(9.11) + 2/(11.13)+2/(13.15)
2A=1/1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9...
2A=1/1-1/15=14/15
Vậy A=14/15 : 2 = 7/15
Nhấn đúng mk nha Tran Dan
\(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+..+\frac{1}{143}+\frac{1}{195}\)
=\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+..+\frac{1}{13.15}\)
= \(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+..+\frac{1}{13}-\frac{1}{15}\)
= \(1-\frac{1}{15}=\frac{14}{15}\)
tick đúng nha
A = \(\frac{1}{1\times3}+\frac{1}{3\times5}+\frac{1}{5\times7}+...+\frac{1}{13\times15}=\frac{1}{2}\times\left(\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+...+\frac{2}{13\times15}\right)\)
A = \(\frac{1}{2}\times\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{13}-\frac{1}{15}\right)=\frac{1}{2}\times\left(1-\frac{1}{15}\right)=\frac{7}{15}\)
1 / 3 + 1 /15 + 1/ 35 + 1 / 63 + 1 / 99 + 1 / 143 + 1 / 195
Đặt A = 1 / 3 + 1 / 15 + 1 / 35 + 1 / 63 + 1 / 99 + 1 / 143 + 1 / 195
A = 1 / 1 x 3 + 1 / 3 x 5 + 1 / 5 x 7 +1 / 7 x 9 + 1 / 9 x 11 + 1 / 11 x 13 + 1 / 13 x 15
A x 2 = 2 / 1 x 3 + 2 / 3 x 5 +2/ 5 x 7 + 2/ 7 x 9 + 2 / 9 x 11 + 2/ 11 x 13 +2 / 13 x 15
A x 2 = 1 / 1 - 1 / 3 + 1 / 3 - 1 /5 + 1 / 5 - 1 / 7 + 1 / 7 - 1 / 9 + 1 / 9 - 1 / 11 + 1 / 11 - 1 / 13 + 1 / 13 - 1 / 15
A x 2 = 1 / 1 - 1 / 15
A x 2 = 14 / 15
A = 7 / 15
=1/3+1/3.5+1/5.7+1/7.9+1/9.11+1/11.13+1/13.15
=1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11+1/11-1/13+1/13-1/15
=1-1/15
=14/15
vậy đáp số là 14/15
nó bằng
1/1x3+1/3x5+1/5x7+1/7x9+1/9x11+1/11x13+1/13x15
=1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11+1/11-1/13+1/13-1/15
loại đi thì còn
=1-1/15
=14/15
câu này dễ mà cũng hỏi là sao bạn ?
a) A = 1/15+1/35+1/63+1/99+1/143+1/195
a) M= 1+3+3^2+3^3+...+3^25 và N = 3^26 : 2 Tính N-M
a)\(A=\frac{1}{15}+\frac{1}{35}+...+\frac{1}{195}=\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{13.15}=\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\right)=\frac{1}{2}\left(\frac{1}{3}-\frac{1}{15}\right)=\frac{2}{15}\)
b)\(M=1+3+3^2+...+3^{25}=\frac{3^{26}-1}{3-1}=\frac{3^{26}-1}{2}
\(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)
bạn có thể trình bày cách làm cho mình ko
Giúp mk với đg cần gấp lắm
7/3+7/15+7/35+7/63+7/99+7/143+7/195
=7/2.(2/1.3+2/3.5+....+2/13.15)
=7/2.(1/1-1/3+1/3-1/5+....+1/13-1/15)
=7/2.(1-1/15)
=7/2.14/15=7.14/2.25
=7.7/1/15=49/15
\(\frac{7}{1\cdot3}+\frac{7}{3\cdot5}+\frac{7}{5\cdot7}+\frac{7}{7\cdot9}+\frac{7}{9\cdot11}+\frac{7}{11\cdot13}+\frac{7}{13\cdot15}\)
\(=\frac{7}{2}\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+..........+\frac{2}{13\cdot15}\right)\)
\(=\frac{7}{2}\left(\frac{2}{1}-\frac{2}{3}+\frac{2}{3}-\frac{2}{5}+.........+\frac{2}{13}-\frac{2}{15}\right)\)
\(=\frac{7}{2}\left(2-\frac{2}{15}\right)=\frac{98}{15}\)
A=\(\dfrac{2}{3}\)+\(\dfrac{14}{15}\)+\(\dfrac{34}{35}\)+\(\dfrac{62}{63}\)+\(\dfrac{98}{99}\)+\(\dfrac{142}{143}\)+\(\dfrac{194}{195}\)
Và B=5+\(\dfrac{1}{2^2}\)+\(\dfrac{1}{3^3}\)+\(^{\dfrac{1}{4^4}}\)+\(\dfrac{1}{5^5}\)+\(\dfrac{1}{6^6}\)+\(\dfrac{1}{7^7}\).So sánh A và B
Tính nhanh
\(1\frac{7}{15}-\frac{1}{3}-\frac{1}{15}-\frac{1}{35}-\frac{1}{63}-\frac{1}{99}-\frac{1}{143}-\frac{1}{195}\)
Đặt \(A=1\frac{7}{15}-\frac{1}{3}-\frac{1}{15}-\frac{1}{35}-\frac{1}{63}-\frac{1}{99}-\frac{1}{143}-\frac{1}{195}\)
\(\Rightarrow A=\frac{22}{15}-\left(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\right)\)
Đặt \(B=\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)
\(\Rightarrow B=\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}+\frac{1}{11\cdot13}+\frac{1}{13\cdot15}\)
\(\Rightarrow2B=2\left(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}+\frac{1}{11\cdot13}+\frac{1}{13\cdot15}\right)\)
\(\Rightarrow2B=\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+\frac{2}{9\cdot11}+\frac{2}{11\cdot13}+\frac{2}{13\cdot15}\)
\(\Rightarrow2B=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}\)
\(\Rightarrow2B=1-\frac{1}{15}\)
\(\Rightarrow2B=\frac{14}{15}\)
\(\Rightarrow B=\frac{14}{15}:2\Rightarrow B=\frac{7}{15}\)
\(\Rightarrow A=\frac{22}{15}-\frac{7}{15}\Rightarrow A=\frac{15}{15}=1\)
=22/15- 1/1.3 - 1/3.5 - 1/5.7 -.........- 1/11.13 - 1/13.15
=22/15 - (1/1.3+1/3.5+....+1/13.17)
=22/15 - 1/2(2/1.3+2/3.5.........+2/13.17)
=22/15 - 1/2(1-1/3+1/3-1/4+.............+1/13-1/17)
=22/15 - 1/2(1-1/17)
=22/15-8/17
=254/255