\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.16}{3^9.16}=3\)

\(B=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.78}{2^8.104}=\frac{2^{10}.26.3}{2^8.2^2.26}=3\)

\(C=\frac{72^3.52^4}{108^4}=\frac{\left(3^2.2^3\right)^3.\left(13.2^2\right)^4}{\left(3^3.2^2\right)^4}=\frac{3^6.2^9.13^4.2^8}{3^{12}.2^8}=\frac{2^9.13^4}{3^6}\)

\(D=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(33-1\right)}{2^2.3^{28}}=\frac{3^{29}.2^5}{2^2.3^{28}}=3.8=24\)

\(a,4^{10}\cdot8^{15}=2^{20}\cdot2^{45}=2^{65}\)

\(b,4^{15}\cdot5^{30}=4^{15}\cdot5^{15}\cdot5^{15}=\left(4\cdot5\cdot5\right)^{15}=100^{15}\)

\(c,27^{16}\cdot9^{10}=3^{48}\cdot3^{20}=3^{68}\)

a) \(4^{10}.8^{15}=\left(2^2\right)^{10}.\left(2^3\right)^{15}=2^{20}.2^{45}=2^{20+45}=2^{65}\)

b) \(4^{15}.5^{30}=\left(2^2\right)^{15}.5^{30}=2^{30}.5^{30}=\left(2.5\right)^{30}=10^{30}\)

c) \(27^{16}.9^{10}=\left(3^3\right)^{16}.\left(3^2\right)^{10}=3^{48}.3^{20}=3^{48+20}=3^{68}\)

\(\frac{3^{10}.11+3^{10}.10}{3^9.2^4}\)

\(=\frac{3^{10}.\left(11+10\right)}{3^9.2^4}=\frac{3^{10}.21}{3^9.16}\)

\(=\frac{3.21}{16}=\frac{63}{16}\)

Bài giải.

\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.(11+5)}{3^9.2^4}=\frac{3.16}{2^4}=\frac{3.2^4}{2^4}=3\)

_Học tốt_

\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)

\(=\frac{3^{10}.\left(11+5\right)}{3^9.2^4}=\frac{3^{10}.16}{3^9.16}\)

\(=\frac{3^{10}}{3^9}=3\)

\(C=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.\left(11+5\right)}{3^9.2^4}=\frac{3^{10}.16}{3^9.16}=\frac{3^{10}}{3^9}=3\)

3^10.11 + 3^10.5 : ( 3^9.2^4)

=3^10.(11+5) : (3^9.2^4)

=(3^10.16) : (3^9.16)

=3^10 : 3^9

=3

Có gì sai thì góp ý cho mình nhé, Tks ! :)))