tìm x :71+65x4=x+140/x+260
tìm X
71+65x4=X+140/X+260
tìm x biết
71 + 65x4=(x + 140):x +260
71+ 65x4 = (x+140) :x + 260
71 + 260 = x:x + 140:x + 260
71 + 260 - 1- 260 = 140x
70 = 140x
x= 70 : 140
x= 1/2
71+65x4=x+140/x+260
71 + 65 x 4 = x + 140/x + 260
x + 140/x + 260 = 71 + 65 x 4
x + 140/x + 260 = 71 + 260
x + 140/x = 71
x/x + 140/x = 71
1 + 140/x = 71
140/x = 71 - 1
140/x = 70
x = 140/70
x = 2
71+ 65 x 4 = (X+14) /X + 260
71 + 260 = X : X + 14 : X + 260
71 = 1 + 14 : X (Cùng bớt 2 vế đi 260)
1 + 14 : X = 71 (đảo vế)
14 : X = 71 - 1
14 : X = 70
X = 14 : 70
X = 0,2
mik nha !!!
71+65x4=x+140:x=260
Tìm X:
71+65x4=X+140/X+260
71+65x4=x+140/x+260
71 + 65 x 4 = \(\frac{x+140}{x+260}\)
71 + 260 = \(\frac{x+140}{x+260}\)
331 = \(\frac{x+140}{x+260}\)
\(\Rightarrow x+140=331\left(x+260\right)\)
\(\Rightarrow x+140=331x+86060\)
\(\Rightarrow140-86060=331x-x\)
\(\Rightarrow330x=85920\)
\(\Rightarrow x=\frac{2864}{11}\)
Tìm x
d)( x+1) +(x +4) +(x+7)+...+ (x+28)=155
e) (x+140): x + 260 =71+65x4
(x+1)+(x+4)+(x+7)+....+(x+28)=155
x+x+x+...+x+(1+4+7+....+28) = 155
10x + 145 = 155
=> 10x = 155 - 145
=> 10x = 10
=> x = 10:10
=> x =1
a) (x + 1 ) + ( x + 4 ) + ( x + 7 ) + ... + ( x + 28 ) = 155
( x + x + x + ... + x ) + ( 1 + 4 + 7 + ... + 28 ) = 155
10x + 145 = 145
10x = 155 - 145
10x = 10
=> x = 10 : 10
=> x = 1
tôi chỉ trả lời cho phần e thôi . Vi phan d của bạn tôi làm dài lam
\(71+65x4=\frac{x+140}{x}+260\)
\(71+65\times4=\frac{x+140}{x}+260\)
\(71+260=\frac{x}{x}+\frac{140}{x}+260\)
\(71\) \(=1+\frac{140}{x}\)
\(70\) \(=\frac{140}{x}\)
\(x\) \(=2\)
ai giúp mình giải bài không 71+65x4=x+140/x +260 dấu / là phân số nha
\(\frac{x+140}{x+260}=71+65.4\)
\(\Leftrightarrow\frac{x+140}{x+260}=71+260\)
\(\Leftrightarrow\frac{x+140}{x+260}=331\)
\(\Leftrightarrow x+140=\left(x+260\right)331\)
\(\Leftrightarrow x+140=86060+331x\)
\(\Leftrightarrow x-331x=85920\)
\(\Leftrightarrow x\left(331-1\right)=85920\)
\(\Leftrightarrow x330=85920\)
\(\Leftrightarrow x\approx260,2\)